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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The table given below shows the monthly salary of six employees working in a company in five different years.**

**What is the difference between the average monthly income of Subhash and average monthly income Ramesh over all the given years?**Correct**Answer- 3) Rs 7238.6**Average monthly income of Subhash = (24600 + 27600 + 31188 + 38985 + 46782)/5 = 169155/5 = Rs 33831

Explanation-

Average monthly income of Ramesh = (23500 + 24440 + 25662 + 28000 + 31360)/5 = 132962/5 =Rs 26592.4

Required difference = 33831 – 26592.4 = Rs 7238.6Incorrect**Answer- 3) Rs 7238.6**Average monthly income of Subhash = (24600 + 27600 + 31188 + 38985 + 46782)/5 = 169155/5 = Rs 33831

Explanation-

Average monthly income of Ramesh = (23500 + 24440 + 25662 + 28000 + 31360)/5 = 132962/5 =Rs 26592.4

Required difference = 33831 – 26592.4 = Rs 7238.6 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The table given below shows the monthly salary of six employees working in a company in five different years.**

**Percentage increase in the monthly income of Raman from the previous year is minimum for which year?**Correct**Answer- 2) 2018**Percentage increase in 2015 = (27300 – 26000)/26000 × 100 = 5%

Explanation-

Percentage increase in 2016 = (29484 – 27300)/27300 × 100 = 8%

Percentage increase in 2017 = (36855 – 29484)/29484 ×100 = 25%

Percentage increase in 2018 = (38000 – 36855)/36855 × 100 = 3% (approx.)

Therefore, 3% is the right answer.Incorrect**Answer- 2) 2018**Percentage increase in 2015 = (27300 – 26000)/26000 × 100 = 5%

Explanation-

Percentage increase in 2016 = (29484 – 27300)/27300 × 100 = 8%

Percentage increase in 2017 = (36855 – 29484)/29484 ×100 = 25%

Percentage increase in 2018 = (38000 – 36855)/36855 × 100 = 3% (approx.)

Therefore, 3% is the right answer. - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (Q1-5). The table given below shows the monthly salary of six employees working in a company in five different years.**

**Which employee has the highest percentage increase in the salary in 2018 as compared to year 2014?**Correct**Answer- 3) Prakash**Prakash has the highest increase in his salary because only he has his salary more than double in 2018 as compared to 2014 (Rs 20500 to Rs 41492).

Explanation-Incorrect**Answer- 3) Prakash**Prakash has the highest increase in his salary because only he has his salary more than double in 2018 as compared to 2014 (Rs 20500 to Rs 41492).

Explanation- - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**The average monthly salary of Subhash, Raman, Ramesh and Arun in 2017 is:**Correct**Answer- 1) Rs 38549.5**Required average = (38985 + 36855 + 28000 + 50358)/4 = 154198/4 = Rs 38549.5

Explanation-Incorrect**Answer- 1) Rs 38549.5**Required average = (38985 + 36855 + 28000 + 50358)/4 = 154198/4 = Rs 38549.5

Explanation- - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**Percentage increase in Prakash’s salary in 2016 as compared to 2015 is:**Correct**Answer- 3) 20%**Required percentage = (28290 – 23575)/23575 × 100 = 20%

Explanation-Incorrect**Answer- 3) 20%**Required percentage = (28290 – 23575)/23575 × 100 = 20%

Explanation- - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**In the following question, two equations are given. Solve these equations and choose the correct option.**

**l) 4x**^{2}– 12x + 5 = 0

**ll) 3y**^{2}– 12y – 36 = 0Correct**Answer- 3) x = y or the relationship between x and y cannot be established.**

**Explanation-**4x^{2}– 12x + 5 = 0 or 4x^{2}– 10x – 2x + 5 = 0

2x (2x – 5) – 1(2x – 5) = 0

x = 5/2 or 1/23y

^{2}– 12y – 36 = 0 or 3y^{2}– 18y + 6y – 36 = 0

3y (y – 6) + 6(y – 6)

y = 6, -1/2Therefore, the relationship between two cannot be established.

Incorrect**Answer- 3) x = y or the relationship between x and y cannot be established.**

**Explanation-**4x^{2}– 12x + 5 = 0 or 4x^{2}– 10x – 2x + 5 = 0

2x (2x – 5) – 1(2x – 5) = 0

x = 5/2 or 1/23y

^{2}– 12y – 36 = 0 or 3y^{2}– 18y + 6y – 36 = 0

3y (y – 6) + 6(y – 6)

y = 6, -1/2Therefore, the relationship between two cannot be established.

- Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**What is the value of x if,**

27.5 × x/11 = 1331 × 5/121Correct**Answer- 2) 22**We have,

Explanation-

x = 1331 × 5 × 11 / (27.5 × 121) = 22Incorrect**Answer- 2) 22**We have,

Explanation-

x = 1331 × 5 × 11 / (27.5 × 121) = 22 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Which number is wrong according to the sequence of the given number series?**

13, 18, 27, 40, 63, 98Correct**Answer- 4) 27**

Explanation- Correct sequence is,

13

13 + 5 = 18

18 + (5 + 3) = 26

26 + (5 + 3 + 6) = 40

40 + (5 + 3 + 6 + 9) = 63

63 + (5 + 3 + 6 + 9 + 12) = 98Incorrect**Answer- 4) 27**

Explanation- Correct sequence is,

13

13 + 5 = 18

18 + (5 + 3) = 26

26 + (5 + 3 + 6) = 40

40 + (5 + 3 + 6 + 9) = 63

63 + (5 + 3 + 6 + 9 + 12) = 98 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Compare the numerical values of the following quantities and choose the correct option.**

Quantity 1- The average speed of the bus in the whole journey (in km/h). A bus goes from A to B with the speed of 25km/h and then returns from B to A with the speed of 35km/h.

Quantity 2- 20Correct**Answer- 2) Quantity 1 > quantity 2**

**Explanation-**

Average speed of the bus = 2 × 25 × 35/ (25 + 35) = 175/6 km/h = quantity 1

Therefore, Quantity 1 > quantity 2Incorrect**Answer- 2) Quantity 1 > quantity 2**

**Explanation-**

Average speed of the bus = 2 × 25 × 35/ (25 + 35) = 175/6 km/h = quantity 1

Therefore, Quantity 1 > quantity 2 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**The following question is accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the question.**

What is the amount after fourth year?

(l) The principal amount is Rs 3500 and amount after second year is Rs 4007.15.

(ll) The amount after first year is Rs 3745 and amount after third year is Rs 4287.6505.Correct**Answer- 3) Either (l) alone or (ll) alone**By using statement (l)

Explanation-

Amount after fourth year = 4007.15 × 4007.15/3500 = Rs 4587.78604

By using statement (ll)

By using this statement we can determine interest rate

(4287.6505 – 3745)/3745 × 100 = 14.49%

Clearly the rate of interest is 7% and with that we can easily calculate the amount after 4th year.Incorrect**Answer- 3) Either (l) alone or (ll) alone**By using statement (l)

Explanation-

Amount after fourth year = 4007.15 × 4007.15/3500 = Rs 4587.78604

By using statement (ll)

By using this statement we can determine interest rate

(4287.6505 – 3745)/3745 × 100 = 14.49%

Clearly the rate of interest is 7% and with that we can easily calculate the amount after 4th year.

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