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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (Q15). The table given below shows the monthly salary of six employees working in a company in five different years.
What is the difference between the average monthly income of Subhash and average monthly income Ramesh over all the given years?
Correct
Answer 3) Rs 7238.6
Explanation Average monthly income of Subhash = (24600 + 27600 + 31188 + 38985 + 46782)/5 = 169155/5 = Rs 33831
Average monthly income of Ramesh = (23500 + 24440 + 25662 + 28000 + 31360)/5 = 132962/5 =Rs 26592.4
Required difference = 33831 – 26592.4 = Rs 7238.6Incorrect
Answer 3) Rs 7238.6
Explanation Average monthly income of Subhash = (24600 + 27600 + 31188 + 38985 + 46782)/5 = 169155/5 = Rs 33831
Average monthly income of Ramesh = (23500 + 24440 + 25662 + 28000 + 31360)/5 = 132962/5 =Rs 26592.4
Required difference = 33831 – 26592.4 = Rs 7238.6 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (Q15). The table given below shows the monthly salary of six employees working in a company in five different years.
Percentage increase in the monthly income of Raman from the previous year is minimum for which year?
Correct
Answer 2) 2018
Explanation Percentage increase in 2015 = (27300 – 26000)/26000 × 100 = 5%
Percentage increase in 2016 = (29484 – 27300)/27300 × 100 = 8%
Percentage increase in 2017 = (36855 – 29484)/29484 ×100 = 25%
Percentage increase in 2018 = (38000 – 36855)/36855 × 100 = 3% (approx.)
Therefore, 3% is the right answer.Incorrect
Answer 2) 2018
Explanation Percentage increase in 2015 = (27300 – 26000)/26000 × 100 = 5%
Percentage increase in 2016 = (29484 – 27300)/27300 × 100 = 8%
Percentage increase in 2017 = (36855 – 29484)/29484 ×100 = 25%
Percentage increase in 2018 = (38000 – 36855)/36855 × 100 = 3% (approx.)
Therefore, 3% is the right answer. 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (Q15). The table given below shows the monthly salary of six employees working in a company in five different years.
Which employee has the highest percentage increase in the salary in 2018 as compared to year 2014?
Correct
Answer 3) Prakash
Explanation Prakash has the highest increase in his salary because only he has his salary more than double in 2018 as compared to 2014 (Rs 20500 to Rs 41492).Incorrect
Answer 3) Prakash
Explanation Prakash has the highest increase in his salary because only he has his salary more than double in 2018 as compared to 2014 (Rs 20500 to Rs 41492). 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (Q15). The table given below shows the monthly salary of six employees working in a company in five different years.
The average monthly salary of Subhash, Raman, Ramesh and Arun in 2017 is:
Correct
Answer 1) Rs 38549.5
Explanation Required average = (38985 + 36855 + 28000 + 50358)/4 = 154198/4 = Rs 38549.5Incorrect
Answer 1) Rs 38549.5
Explanation Required average = (38985 + 36855 + 28000 + 50358)/4 = 154198/4 = Rs 38549.5 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections (Q15). The table given below shows the monthly salary of six employees working in a company in five different years.
Percentage increase in Prakash’s salary in 2016 as compared to 2015 is:
Correct
Answer 3) 20%
Explanation Required percentage = (28290 – 23575)/23575 × 100 = 20%Incorrect
Answer 3) 20%
Explanation Required percentage = (28290 – 23575)/23575 × 100 = 20% 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeIn the following question, two equations are given. Solve these equations and choose the correct option.
l) 4x^{2} – 12x + 5 = 0
ll) 3y^{2} – 12y – 36 = 0Correct
Answer 3) x = y or the relationship between x and y cannot be established.
Explanation 4x^{2} – 12x + 5 = 0 or 4x^{2} – 10x – 2x + 5 = 0
2x (2x – 5) – 1(2x – 5) = 0
x = 5/2 or 1/23y^{2} – 12y – 36 = 0 or 3y^{2} – 18y + 6y – 36 = 0
3y (y – 6) + 6(y – 6)
y = 6, 1/2Therefore, the relationship between two cannot be established.
Incorrect
Answer 3) x = y or the relationship between x and y cannot be established.
Explanation 4x^{2} – 12x + 5 = 0 or 4x^{2} – 10x – 2x + 5 = 0
2x (2x – 5) – 1(2x – 5) = 0
x = 5/2 or 1/23y^{2} – 12y – 36 = 0 or 3y^{2} – 18y + 6y – 36 = 0
3y (y – 6) + 6(y – 6)
y = 6, 1/2Therefore, the relationship between two cannot be established.

Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeWhat is the value of x if,
27.5 × x/11 = 1331 × 5/121Correct
Answer 2) 22
Explanation We have,
x = 1331 × 5 × 11 / (27.5 × 121) = 22Incorrect
Answer 2) 22
Explanation We have,
x = 1331 × 5 × 11 / (27.5 × 121) = 22 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeWhich number is wrong according to the sequence of the given number series?
13, 18, 27, 40, 63, 98Correct
Answer 4) 27
Explanation Correct sequence is,
13
13 + 5 = 18
18 + (5 + 3) = 26
26 + (5 + 3 + 6) = 40
40 + (5 + 3 + 6 + 9) = 63
63 + (5 + 3 + 6 + 9 + 12) = 98Incorrect
Answer 4) 27
Explanation Correct sequence is,
13
13 + 5 = 18
18 + (5 + 3) = 26
26 + (5 + 3 + 6) = 40
40 + (5 + 3 + 6 + 9) = 63
63 + (5 + 3 + 6 + 9 + 12) = 98 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeCompare the numerical values of the following quantities and choose the correct option.
Quantity 1 The average speed of the bus in the whole journey (in km/h). A bus goes from A to B with the speed of 25km/h and then returns from B to A with the speed of 35km/h.
Quantity 2 20Correct
Answer 2) Quantity 1 > quantity 2
Explanation
Average speed of the bus = 2 × 25 × 35/ (25 + 35) = 175/6 km/h = quantity 1
Therefore, Quantity 1 > quantity 2Incorrect
Answer 2) Quantity 1 > quantity 2
Explanation
Average speed of the bus = 2 × 25 × 35/ (25 + 35) = 175/6 km/h = quantity 1
Therefore, Quantity 1 > quantity 2 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeThe following question is accompanied by two statements (l) and (ll). You have to determine which statement (s) is/are sufficient to answer the question.
What is the amount after fourth year?
(l) The principal amount is Rs 3500 and amount after second year is Rs 4007.15.
(ll) The amount after first year is Rs 3745 and amount after third year is Rs 4287.6505.Correct
Answer 3) Either (l) alone or (ll) alone
Explanation By using statement (l)
Amount after fourth year = 4007.15 × 4007.15/3500 = Rs 4587.78604
By using statement (ll)
By using this statement we can determine interest rate
(4287.6505 – 3745)/3745 × 100 = 14.49%
Clearly the rate of interest is 7% and with that we can easily calculate the amount after 4th year.Incorrect
Answer 3) Either (l) alone or (ll) alone
Explanation By using statement (l)
Amount after fourth year = 4007.15 × 4007.15/3500 = Rs 4587.78604
By using statement (ll)
By using this statement we can determine interest rate
(4287.6505 – 3745)/3745 × 100 = 14.49%
Clearly the rate of interest is 7% and with that we can easily calculate the amount after 4th year.
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