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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections: (15) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.
If the speed of the boat in still water on Monday is 22km/h and the speed of stream on Monday is 30% of the speed of stream on Tuesday then, find the time taken by boat in travelling upstream on Monday?
Correct
Answer: 1. 20 hours
Explanation:
Upstream distance on Monday = total distance travelled on Monday – distance travelled downstream on Monday
Upstream distance on Monday = 48*18 – 22*22 = 380
Speed of stream on Monday= 30% of 10 =3
Speed of boat in upstream on Monday = 223 = 19
Time taken by boat in travelling upstream on Monday = 380/19 = 20hIncorrect
Answer: 1. 20 hours
Explanation:
Upstream distance on Monday = total distance travelled on Monday – distance travelled downstream on Monday
Upstream distance on Monday = 48*18 – 22*22 = 380
Speed of stream on Monday= 30% of 10 =3
Speed of boat in upstream on Monday = 223 = 19
Time taken by boat in travelling upstream on Monday = 380/19 = 20h 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections: (15) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.
If the time taken by boat in travelling total distance on Thursday is 18 hours, then find the speed of the boat in still water on Thursday?
Correct
Answer: 4. 38km/h
Explanation:
Speed of stream on Thursday = 6km/h
Distance travelled upstream on Thursday = 48*14 – 22*16 = 320
Distance travelled downstream on Thursday = 22*16 = 352
Let the speed of boat in still water = x
ATQ,
(352/x+6) + (320/x6) = 18
x = 38Incorrect
Answer: 4. 38km/h
Explanation:
Speed of stream on Thursday = 6km/h
Distance travelled upstream on Thursday = 48*14 – 22*16 = 320
Distance travelled downstream on Thursday = 22*16 = 352
Let the speed of boat in still water = x
ATQ,
(352/x+6) + (320/x6) = 18
x = 38 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections: (15) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.
If the speed of the boat in still water on Wednesday is 49 km/h and time taken by the boat to cover the upstream distance is 16 hours, then the speed of stream on Wednesday is what percent of the speed of stream on Thursday?
Correct
Answer: 4. 150%
Explanation:
Distance travelled in upstream on Wednesday = 48*28 – 32*22 = 640
Let the speed of stream on Wednesday = s km/h
ATQ,
(640/49s) = 16
s = 9km/h
Required percentage = (9/6)*100 = 150%Incorrect
Answer: 4. 150%
Explanation:
Distance travelled in upstream on Wednesday = 48*28 – 32*22 = 640
Let the speed of stream on Wednesday = s km/h
ATQ,
(640/49s) = 16
s = 9km/h
Required percentage = (9/6)*100 = 150% 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections: (15) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.
If the speed of the boat in still water on Monday, Tuesday, Wednesday and Friday is 22km/h and on Thursday is 26km/h. The speed of stream on Monday is 110% of the speed of stream on Tuesday, speed of stream on Tuesday and Wednesday is 10km/h and the speed of stream on Thursday and Friday is 6km/h and 20km/h respectively. Then find the time total time taken by boat in travelling downstream in all five days?
Correct
Answer: 1. 66 hours
Explanation:
Speed of stream on Monday = 110% of 10 =11
Time taken on Monday = 22*{22/(22+11)} = 22*(2/3)
Time taken on Tuesday = 22*{16/(22+10)} = 22*(1/2)
Time taken on Wednesday = 22*{32/(22+10)} = 22
Time taken on Thursday = 22*{16/(26+6)} = 22*(1/2)
Time taken on Friday = 22*{(14/(22+20)} 22*(1/3)
Total time taken = 22(2/3 + 1/2 + 1 + 1/2 + 1/3 ) = 22*3 = 66 hoursIncorrect
Answer: 1. 66 hours
Explanation:
Speed of stream on Monday = 110% of 10 =11
Time taken on Monday = 22*{22/(22+11)} = 22*(2/3)
Time taken on Tuesday = 22*{16/(22+10)} = 22*(1/2)
Time taken on Wednesday = 22*{32/(22+10)} = 22
Time taken on Thursday = 22*{16/(26+6)} = 22*(1/2)
Time taken on Friday = 22*{(14/(22+20)} 22*(1/3)
Total time taken = 22(2/3 + 1/2 + 1 + 1/2 + 1/3 ) = 22*3 = 66 hours 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections: (15) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.
Find the ratio of time taken by boat in travelling downstream on Tuesday to the time taken in travelling upstream on Thursday. The speed of the boat in still water on Tuesday is 22km/h and speed of the boat in still water on Thursday is 38km/h.
Correct
Answer: 3. 11:10
Explanation:
Distance travelled downstream on Tuesday = 16*22 = 352
Time taken = 352/(22+10) = 11
Distance travelled upstream on Thursday = 48*1422*16 = 320
Time taken = 320/(386) = 10
Ratio = 11/10 = 11:10Incorrect
Answer: 3. 11:10
Explanation:
Distance travelled downstream on Tuesday = 16*22 = 352
Time taken = 352/(22+10) = 11
Distance travelled upstream on Thursday = 48*1422*16 = 320
Time taken = 320/(386) = 10
Ratio = 11/10 = 11:10 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections: (610) Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.
The profit of Aakash is what percent of the profit of Billu at the end of the third year?
Correct
Answer: 2. 90%
Explanation :
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Required percentage = 22500/25000 =( 9/10)*100 = 90%
the ratio of their investments becomes 5:3:5:6
Since, (4x 2500)/5x = 3/5
x = 2500
(2x+y)/5x = 5/5
y = = 3x =7500
5x/(6x4000+z) = 5/6
z = 4000
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Chandan’s profit = 15x = 37500
Deepak’s profit = 18x8000+z = 18*25008000+4000 = 41000
Ratio of profits = 225:250:375:410 = 45:50:75:82Incorrect
Answer: 2. 90%
Explanation :
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Required percentage = 22500/25000 =( 9/10)*100 = 90%
the ratio of their investments becomes 5:3:5:6
Since, (4x 2500)/5x = 3/5
x = 2500
(2x+y)/5x = 5/5
y = = 3x =7500
5x/(6x4000+z) = 5/6
z = 4000
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Chandan’s profit = 15x = 37500
Deepak’s profit = 18x8000+z = 18*25008000+4000 = 41000
Ratio of profits = 225:250:375:410 = 45:50:75:82 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections: (610) Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.
Find the ratio of their profits at the end of 3 years?
Correct
Answer: 4. 45:50:75:82
Explanation:
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Chandan’s profit = 15x = 37500
Deepak’s profit = 18x8000+z = 18*25008000+4000 = 41000
Ratio of profits = 225:250:375:410 = 45:50:75:82Incorrect
Answer: 4. 45:50:75:82
Explanation:
Aakash’s profit = 6x+y = 6*2500+7500 = 22500
Billu’s profit = 12x5000 = 12*25005000 = 25000
Chandan’s profit = 15x = 37500
Deepak’s profit = 18x8000+z = 18*25008000+4000 = 41000
Ratio of profits = 225:250:375:410 = 45:50:75:82 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections: (610) Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.
Find the difference between the additional amount invested by Aakash and Deepak at the end of the 2nd year?
Correct
Answer: 3. Rs. 3500
Explanation:
y = 7500
z = 4000
Difference = 7500 – 4000 = 3500Incorrect
Answer: 3. Rs. 3500
Explanation:
y = 7500
z = 4000
Difference = 7500 – 4000 = 3500 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections: (610) Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.
If Chandan will be given 16% of the profit for handling business and at the end of the third year if he receives a total Rs. 12300 as profit, then find total profit earned at the end of the third year?
Correct
Answer: 5. 30000
Explanation:
Chandan is given 16% for handling
Profit left for all four for their business = 84%
Chandan’s profit = 16%+25% = 12300
41% = 12300
1% = 300
100% = 30000Incorrect
Answer: 5. 30000
Explanation:
Chandan is given 16% for handling
Profit left for all four for their business = 84%
Chandan’s profit = 16%+25% = 12300
41% = 12300
1% = 300
100% = 30000 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections: (610) Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.
Find the total investment done initially?
Correct
Answer: 2. Rs. 42500
Explanation:
2x+4x+5x+6x = 17x = 17*2500 = 42500Incorrect
Answer: 2. Rs. 42500
Explanation:
2x+4x+5x+6x = 17x = 17*2500 = 42500
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