Hello Aspirants

Welcome to Online **Quant** **Test** in AffairsCloud.com. We are starting **Cumulus Course for SBI Clerk 2019 Mains Exam** and we are creating sample questions in Quant section, this type of Question will be asked in SBI Clerk 2019!!!

**Click Here to View Cumulus Course: SBI Clerk 2019 Mains**

**SBI Clerk 2019 Mains: GA Test **– 7.00 PM Every Day

**SBI Clerk 2019 Mains: Reasoning Test **– 8.00 PM Every Day

**SBI Clerk 2019 Mains: Quant Test **– 9.00 PM Every Day

**SBI Clerk 2019 Mains: English Test **– 10.00 PM Every Day

**Help:- **Share Our Cumulus Course for SBI Clerk 2019 Exam Course page to your Friends & FB Groups

**Click Here to Subscribe Crack High Level Puzzles & Seating Arrangement Questions PDF 2019 Plan**

_______________________

#### Quiz-summary

0 of 10 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

#### Information

**All the Best**

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

- Quantitative Aptitude 0%

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

- Answered
- Review

- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions: (1-5) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.**

**If the speed of the boat in still water on Monday is 22km/h and the speed of stream on Monday is 30% of the speed of stream on Tuesday then, find the time taken by boat in travelling upstream on Monday?**Correct**Answer: 1. 20 hours**

Explanation:

Upstream distance on Monday = total distance travelled on Monday – distance travelled downstream on Monday

Upstream distance on Monday = 48*18 – 22*22 = 380

Speed of stream on Monday= 30% of 10 =3

Speed of boat in upstream on Monday = 22-3 = 19

Time taken by boat in travelling upstream on Monday = 380/19 = 20hIncorrect**Answer: 1. 20 hours**

Explanation:

Upstream distance on Monday = total distance travelled on Monday – distance travelled downstream on Monday

Upstream distance on Monday = 48*18 – 22*22 = 380

Speed of stream on Monday= 30% of 10 =3

Speed of boat in upstream on Monday = 22-3 = 19

Time taken by boat in travelling upstream on Monday = 380/19 = 20h - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions: (1-5) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.**

**If the time taken by boat in travelling total distance on Thursday is 18 hours, then find the speed of the boat in still water on Thursday?**Correct**Answer: 4. 38km/h**

Explanation:

Speed of stream on Thursday = 6km/h

Distance travelled upstream on Thursday = 48*14 – 22*16 = 320

Distance travelled downstream on Thursday = 22*16 = 352

Let the speed of boat in still water = x

ATQ,

(352/x+6) + (320/x-6) = 18

x = 38Incorrect**Answer: 4. 38km/h**

Explanation:

Speed of stream on Thursday = 6km/h

Distance travelled upstream on Thursday = 48*14 – 22*16 = 320

Distance travelled downstream on Thursday = 22*16 = 352

Let the speed of boat in still water = x

ATQ,

(352/x+6) + (320/x-6) = 18

x = 38 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions: (1-5) In a day a boat covers a certain distance in upstream while the rest of the distance in downstream. The speed of stream on different days is given in the table while the total distance covered by the boat in a day is given in first pie chart and the distance covered by boat in downstream in that day is given in second pie chart. Read the data carefully and answer the following questions.**

**If the speed of the boat in still water on Wednesday is 49 km/h and time taken by the boat to cover the upstream distance is 16 hours, then the speed of stream on Wednesday is what percent of the speed of stream on Thursday?**Correct**Answer: 4. 150%**

Explanation:

Distance travelled in upstream on Wednesday = 48*28 – 32*22 = 640

Let the speed of stream on Wednesday = s km/h

ATQ,

(640/49-s) = 16

s = 9km/h

Required percentage = (9/6)*100 = 150%Incorrect**Answer: 4. 150%**

Explanation:

Distance travelled in upstream on Wednesday = 48*28 – 32*22 = 640

Let the speed of stream on Wednesday = s km/h

ATQ,

(640/49-s) = 16

s = 9km/h

Required percentage = (9/6)*100 = 150% - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

**If the speed of the boat in still water on Monday, Tuesday, Wednesday and Friday is 22km/h and on Thursday is 26km/h. The speed of stream on Monday is 110% of the speed of stream on Tuesday, speed of stream on Tuesday and Wednesday is 10km/h and the speed of stream on Thursday and Friday is 6km/h and 20km/h respectively. Then find the time total time taken by boat in travelling downstream in all five days?**Correct**Answer: 1. 66 hours**

Explanation:

Speed of stream on Monday = 110% of 10 =11

Time taken on Monday = 22*{22/(22+11)} = 22*(2/3)

Time taken on Tuesday = 22*{16/(22+10)} = 22*(1/2)

Time taken on Wednesday = 22*{32/(22+10)} = 22

Time taken on Thursday = 22*{16/(26+6)} = 22*(1/2)

Time taken on Friday = 22*{(14/(22+20)} 22*(1/3)

Total time taken = 22(2/3 + 1/2 + 1 + 1/2 + 1/3 ) = 22*3 = 66 hoursIncorrect**Answer: 1. 66 hours**

Explanation:

Speed of stream on Monday = 110% of 10 =11

Time taken on Monday = 22*{22/(22+11)} = 22*(2/3)

Time taken on Tuesday = 22*{16/(22+10)} = 22*(1/2)

Time taken on Wednesday = 22*{32/(22+10)} = 22

Time taken on Thursday = 22*{16/(26+6)} = 22*(1/2)

Time taken on Friday = 22*{(14/(22+20)} 22*(1/3)

Total time taken = 22(2/3 + 1/2 + 1 + 1/2 + 1/3 ) = 22*3 = 66 hours - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

**Find the ratio of time taken by boat in travelling downstream on Tuesday to the time taken in travelling upstream on Thursday. The speed of the boat in still water on Tuesday is 22km/h and speed of the boat in still water on Thursday is 38km/h.**Correct**Answer: 3. 11:10**

Explanation:

Distance travelled downstream on Tuesday = 16*22 = 352

Time taken = 352/(22+10) = 11

Distance travelled upstream on Thursday = 48*14-22*16 = 320

Time taken = 320/(38-6) = 10

Ratio = 11/10 = 11:10Incorrect**Answer: 3. 11:10**

Explanation:

Distance travelled downstream on Tuesday = 16*22 = 352

Time taken = 352/(22+10) = 11

Distance travelled upstream on Thursday = 48*14-22*16 = 320

Time taken = 320/(38-6) = 10

Ratio = 11/10 = 11:10 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.**The profit of Aakash is what percent of the profit of Billu at the end of the third year?**Correct**Answer: 2. 90%**

Explanation :

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Required percentage = 22500/25000 =( 9/10)*100 = 90%

the ratio of their investments becomes 5:3:5:6

Since, (4x -2500)/5x = 3/5

x = 2500

(2x+y)/5x = 5/5

y = = 3x =7500

5x/(6x-4000+z) = 5/6

z = 4000

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Chandan’s profit = 15x = 37500

Deepak’s profit = 18x-8000+z = 18*2500-8000+4000 = 41000

Ratio of profits = 225:250:375:410 = 45:50:75:82Incorrect**Answer: 2. 90%**

Explanation :

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Required percentage = 22500/25000 =( 9/10)*100 = 90%

the ratio of their investments becomes 5:3:5:6

Since, (4x -2500)/5x = 3/5

x = 2500

(2x+y)/5x = 5/5

y = = 3x =7500

5x/(6x-4000+z) = 5/6

z = 4000

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Chandan’s profit = 15x = 37500

Deepak’s profit = 18x-8000+z = 18*2500-8000+4000 = 41000

Ratio of profits = 225:250:375:410 = 45:50:75:82 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.**Find the ratio of their profits at the end of 3 years?**Correct**Answer: 4. 45:50:75:82**

Explanation:

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Chandan’s profit = 15x = 37500

Deepak’s profit = 18x-8000+z = 18*2500-8000+4000 = 41000

Ratio of profits = 225:250:375:410 = 45:50:75:82Incorrect**Answer: 4. 45:50:75:82**

Explanation:

Aakash’s profit = 6x+y = 6*2500+7500 = 22500

Billu’s profit = 12x-5000 = 12*2500-5000 = 25000

Chandan’s profit = 15x = 37500

Deepak’s profit = 18x-8000+z = 18*2500-8000+4000 = 41000

Ratio of profits = 225:250:375:410 = 45:50:75:82 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.**Find the difference between the additional amount invested by Aakash and Deepak at the end of the 2nd year?**Correct**Answer: 3. Rs. 3500**

Explanation:

y = 7500

z = 4000

Difference = 7500 – 4000 = 3500Incorrect**Answer: 3. Rs. 3500**

Explanation:

y = 7500

z = 4000

Difference = 7500 – 4000 = 3500 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.**If Chandan will be given 16% of the profit for handling business and at the end of the third year if he receives a total Rs. 12300 as profit, then find total profit earned at the end of the third year?**Correct**Answer: 5. 30000**

Explanation:

Chandan is given 16% for handling

Profit left for all four for their business = 84%

Chandan’s profit = 16%+25% = 12300

41% = 12300

1% = 300

100% = 30000Incorrect**Answer: 5. 30000**

Explanation:

Chandan is given 16% for handling

Profit left for all four for their business = 84%

Chandan’s profit = 16%+25% = 12300

41% = 12300

1% = 300

100% = 30000 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions: (6-10)**Four neighbours Aakash, Billu, Chandan, and Deepak started a business together with initial investments in the ratio 2:4:5:6 respectively. At the end of one year, Billu withdrew Rs. 2500, Deepak withdrew Rs. 4000 rupees and the remaining two kept their investment unchanged. At the end of 2nd year, Deepak and Aakash invested some additional amounts and remaining two kept their investment unchanged such that the ratio of their investments becomes 5:3:5:6 respectively at the end of 2nd year. At the end of the third year, they share profit in the ratio of their investment and time of investment.**Find the total investment done initially?**Correct**Answer: 2. Rs. 42500**

Explanation:

2x+4x+5x+6x = 17x = 17*2500 = 42500Incorrect**Answer: 2. Rs. 42500**

Explanation:

2x+4x+5x+6x = 17x = 17*2500 = 42500

**Click view Questions button to view Explanation****Note:-**We are providing unique questions for you to practice well, have a try !!- Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
- If you find any mistake, please tell us in the comment section.

**Bank Jobs Notification**

**Central Govt Jobs Notification**