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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude18 ÷ √36 * (369 + x) = 2040
Correct
Answer – 3. 311
Explanation:
18 /6 * (369 + x) = 2040
3x = 2040 – 1107
x = 311Incorrect
Answer – 3. 311
Explanation:
18 /6 * (369 + x) = 2040
3x = 2040 – 1107
x = 311 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude40% of 360 – 60% of x = 120
Correct
Answer – 1. 400
Explanation:
40% of 360 = 144
144 – 0.06x = 120
144 – 120 = 0.06xIncorrect
Answer – 1. 400
Explanation:
40% of 360 = 144
144 – 0.06x = 120
144 – 120 = 0.06x 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude23 ? 32 43 61 88
Correct
Incorrect

Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitudex² + 19x + 90 = 0
y² + 12y + 32 = 0Correct
Answer – 2. X < Y
Explanation:
x² + 19x + 90 = 0
x = 9, 10
y² + 12y + 32 = 0
y = – 4, – 8Incorrect
Answer – 2. X < Y
Explanation:
x² + 19x + 90 = 0
x = 9, 10
y² + 12y + 32 = 0
y = – 4, – 8 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeSharmi gave 25% of her monthly salary to her father. From the remaining salary, she paid 15% towards rent and 25%, she kept aside for EMI. The remaining amount was kept in bank account. The sum of the amount she kept in the bank and that she gave to her father was Rs 42000. What was her monthly salary?
Correct
Answer – 2. Rs 60000
Explanation:
Amount given to her father = x/4
Remaining salary = 3x/4
Rent + EMI = 40%
Remaining salary = 3x/4 * 60/100 = 9x/20
x/4 + 9x/20 = 42000
x = 60000Incorrect
Answer – 2. Rs 60000
Explanation:
Amount given to her father = x/4
Remaining salary = 3x/4
Rent + EMI = 40%
Remaining salary = 3x/4 * 60/100 = 9x/20
x/4 + 9x/20 = 42000
x = 60000 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeAjay is thrice as efficient as Balaji. Ajay started working and after 4 days he was replaced by Balaji. Balaji then worked for 15 days and left. If Ajay and Balaji together finished 75% of the total work, in how many days Balaji alone can finish the whole work?
Correct
Answer – 4. 36 days
Explanation:
Time taken by Ajay = x
Time taken by Balaji = 3x
4/x + 15/3x = 3/4
9/x = 3/4
x = 12 days
Time taken by Balaji = 36 daysIncorrect
Answer – 4. 36 days
Explanation:
Time taken by Ajay = x
Time taken by Balaji = 3x
4/x + 15/3x = 3/4
9/x = 3/4
x = 12 days
Time taken by Balaji = 36 days 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe cost price of Watch B is Rs 150 more than the cost price of Watch A, A was sold at a profit of 10% and Watch B was sold at a loss of 20%. If the respective ratio of selling price of Watches A and B is 11 : 12, what is the cost price of Watch B?
Correct
Answer – 1. Rs 450
Explanation:
CP of Watch A = x
CP of Watch B = x + 150
110x/(x+150)80 = 11/12
10x/(x+150)20 = 1/3
3x = 2x + 300
x = 300
CP of Watch B = 300 + 150 = 450Incorrect
Answer – 1. Rs 450
Explanation:
CP of Watch A = x
CP of Watch B = x + 150
110x/(x+150)80 = 11/12
10x/(x+150)20 = 1/3
3x = 2x + 300
x = 300
CP of Watch B = 300 + 150 = 450 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA vessel contains a mixture of Lime and water in the respective ratio of 10 : 3. Twentysix litres of this mixture was taken out and replaced with 10 L of water. If the resultant respective ratio of Lime and water in the mixture was 5 : 2, what was the initial quantity of mixture in the vessel?
Correct
Answer – 4. 156 L
Explanation:
In 26L of mixture,
Lime = 10/13 * 26 = 20L
Water = 6L
Lime = 10x; Water = 3x
10x20/3x6+10 = 5/2
2x4/3x+4 = 1/2
x= 12
Initial quantity of mixture = 13x = 156Incorrect
Answer – 4. 156 L
Explanation:
In 26L of mixture,
Lime = 10/13 * 26 = 20L
Water = 6L
Lime = 10x; Water = 3x
10x20/3x6+10 = 5/2
2x4/3x+4 = 1/2
x= 12
Initial quantity of mixture = 13x = 156 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIn a bag there are 6 red balls and 9 green balls. Two balls are drawn at random, what is the probability that at least one of the balls drawn is red?
Correct
Answer – 3. 23/35
Explanation:
Total numbers of balls in the bag = 6 + 9 = 15
15c2 = 105
6C1*9C1 + 6C2 = 69
Required Probability = 69/105 = 23/35Incorrect
Answer – 3. 23/35
Explanation:
Total numbers of balls in the bag = 6 + 9 = 15
15c2 = 105
6C1*9C1 + 6C2 = 69
Required Probability = 69/105 = 23/35 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA cistern is filled in eight hours by three pipes P, A and M. Pipe P is twice as fast as pipe A, and A is twice as fast as M. How much time will pipe A alone take to fill the cistern?
Correct
Answer – 3. 28 hours
Explanation:
1/P + 1/A + 1/M = 1/8
P = 2A and A = 2M
=> 1/2A + 1/A + 2/A = 1/8
=> (1 + 2 + 4)/2A = 1/8
=> 2A/7 = 8
=> A = 28 hours.Incorrect
Answer – 3. 28 hours
Explanation:
1/P + 1/A + 1/M = 1/8
P = 2A and A = 2M
=> 1/2A + 1/A + 2/A = 1/8
=> (1 + 2 + 4)/2A = 1/8
=> 2A/7 = 8
=> A = 28 hours.
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