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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
The number of females in different departments of a company along with the ratio of number of males to females in respective departments.
The number of Females in departments P and Q is what percent of total employees in these two departments?
Correct
Answer – 1. 45.33%
Explanation:
Required % = (36 + 100) /(120 + 180) * 100 = 45.33%Incorrect
Answer – 1. 45.33%
Explanation:
Required % = (36 + 100) /(120 + 180) * 100 = 45.33% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
The number of females in different departments of a company along with the ratio of number of males to females in respective departments.
What is the total number of males in departments P and T?
Correct
Answer – 3. 118
Explanation:
Total number of males in departments P and T = (7*12) + (2*17) = 84 + 34 = 118Incorrect
Answer – 3. 118
Explanation:
Total number of males in departments P and T = (7*12) + (2*17) = 84 + 34 = 118 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
The number of females in different departments of a company along with the ratio of number of males to females in respective departments.
If 5% males and 10% females in department S are PG holders, then find the number of PG holder employees in the same department
Correct
Answer – 5. 13
Explanation:
8x = 160; x = 20
Male = 3x = 60; Female = 5x = 100
Total number of PG holder employees in Department S = 3 + 10 = 13Incorrect
Answer – 5. 13
Explanation:
8x = 160; x = 20
Male = 3x = 60; Female = 5x = 100
Total number of PG holder employees in Department S = 3 + 10 = 13 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
The number of females in different departments of a company along with the ratio of number of males to females in respective departments.
If 10% males and 20% females from department Q transferred to department T, find the new ratio of females to males in department T.Correct
Answer – 4. 42 : 71
Explanation:
9x = 180 ; x = 20
Male = 4x = 80 ; Female = 5x = 100
10% of Male = 8 ; 20% of Female = 20/100 * 100 = 20
Males in Department = 34 + 8 = 42
Females in Department = 51 + 20 = 71; New Ratio = 42:71Incorrect
Answer – 4. 42 : 71
Explanation:
9x = 180 ; x = 20
Male = 4x = 80 ; Female = 5x = 100
10% of Male = 8 ; 20% of Female = 20/100 * 100 = 20
Males in Department = 34 + 8 = 42
Females in Department = 51 + 20 = 71; New Ratio = 42:71 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
The number of females in different departments of a company along with the ratio of number of males to females in respective departments.
The male employees in department S and T together are what percent more or less than the females in departments Q and R together?
Correct
Answer – 3. 41.25%
Explanation:
Male employees in department Q and R = 94
Females in departments S and T together = 160
Required % = 160 – 94 / 160 * 100
= 66/160 * 100 = 41.25%Incorrect
Answer – 3. 41.25%
Explanation:
Male employees in department Q and R = 94
Females in departments S and T together = 160
Required % = 160 – 94 / 160 * 100
= 66/160 * 100 = 41.25% 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude√3844 – 1358 ÷ 14 + √(48% of 2700) = ?
Correct
Answer – 5. 1
Explanation:
62 – 97 + 36 = 1Incorrect
Answer – 5. 1
Explanation:
62 – 97 + 36 = 1 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude1425 ÷ 19 – 15% of 600 + √3844 = ?
Correct
Answer – 2. 47
Explanation:
75 – 90 + 62 = 47Incorrect
Answer – 2. 47
Explanation:
75 – 90 + 62 = 47 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeSharmi’s monthly income is Rs. 18,400. She spends 30% of her monthly income on EMIs, 40% of the remaining on investment and food and saves 50% of the remaining. How much money does she save every month?
Correct
Answer – 1. 3864
Explanation:
Saving = 50% of (100 – 40)% of (100 – 30)% of Rs. 18,400
= Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864.Incorrect
Answer – 1. 3864
Explanation:
Saving = 50% of (100 – 40)% of (100 – 30)% of Rs. 18,400
= Rs. (50/100 * 60/100 * 70/100 * 18400) = Rs. 3864. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeSuresh covered a certain distance at some speed. Had he moved 3 km/h faster, he would have taken 40 minutes less. If he had moved 2 km/h slower, he would have taken 40 minutes more. What is the distance (in km)?
Correct
Answer – 3. 40
Explanation:
Let distance = x km and usual rate = y kmph.
Then, x/y – x/(y+3) = 40/60 –> 2y (y+3) = 9x —– (1)
Also, x/(y2) – x/y = 40/60 –> y(y2) = 3x ——– (2)
On dividing (1) by (2), we get:
x = 40 km.Incorrect
Answer – 3. 40
Explanation:
Let distance = x km and usual rate = y kmph.
Then, x/y – x/(y+3) = 40/60 –> 2y (y+3) = 9x —– (1)
Also, x/(y2) – x/y = 40/60 –> y(y2) = 3x ——– (2)
On dividing (1) by (2), we get:
x = 40 km. 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeRamesh, Suresh and Ganesh can complete the work in 18, 36 and 54 days respectively. Ramesh started the work and worked for 8 days, then Suresh and Ganesh joined him and they all worked together for some days. Ramesh left the job one day before completion of work. For how many days they all worked together?
Correct
Answer – 2. 5
Explanation:
Let Ramesh, Suresh and Ganesh worked together for x days.
The total work can be the LCM of 18, 6, 54 = 108 units
Ramesh’s 1 day work = 108/18 = 6 units
Suresh’s 1 day work = 108/36 = 3 units
Ganesh’s 1 day work = 108/54 = 2 units
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 – 48
11x = 55
x = 5 days.
All Ramesh, Suresh and Ganesh together worked for 5 days.Incorrect
Answer – 2. 5
Explanation:
Let Ramesh, Suresh and Ganesh worked together for x days.
The total work can be the LCM of 18, 6, 54 = 108 units
Ramesh’s 1 day work = 108/18 = 6 units
Suresh’s 1 day work = 108/36 = 3 units
Ganesh’s 1 day work = 108/54 = 2 units
8 x 6 + 11x + 5 x 1 = 108
48 + 11x + 5 = 108
11x = 103 – 48
11x = 55
x = 5 days.
All Ramesh, Suresh and Ganesh together worked for 5 days.
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