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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeSuresh’s present age is three times his daughter’s present age and two fifth of his father’s present age. The average of the present age of all of them is 46 years. What is the difference between Suresh’s daughter’s present age and Suresh’s father’s present age?
Correct
Answer – 4. 78 years
Explanation:
Let Suresh’s present age = x
Then, his daughter’s age = x/3
Father’s age = (5/2)x
x + x/3 + (5/2)x / 3 = 46
x = 36 years
Now the required difference = 5/2*36 − 36/3 = 78 yearsIncorrect
Answer – 4. 78 years
Explanation:
Let Suresh’s present age = x
Then, his daughter’s age = x/3
Father’s age = (5/2)x
x + x/3 + (5/2)x / 3 = 46
x = 36 years
Now the required difference = 5/2*36 − 36/3 = 78 years 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeOne year ago the ratio between Mahesh’s and Suresh’s salary was 3 : 4. The ratios of their individual salaries between last year’s and this year’s salaries are 4 : 5 and 2 : 3 respectively. At present the total of their salary is Rs. 4160. The salary of Mahesh, now is?
Correct
Answer – Rs. 1600
Explanation:
Let the salaries of Mahesh and Suresh one year before be M1, S1 and now be M2, S2 respectively.
M1/S1 = 3/4 …..(1)
M1/M2 = 4/5 …..(2)
S1/S2 = 2/3 …..(3)
and M2 + S2 = 4160 …..(4)
Solving all these equations, we get M2 = Rs. 1600.Incorrect
Answer – Rs. 1600
Explanation:
Let the salaries of Mahesh and Suresh one year before be M1, S1 and now be M2, S2 respectively.
M1/S1 = 3/4 …..(1)
M1/M2 = 4/5 …..(2)
S1/S2 = 2/3 …..(3)
and M2 + S2 = 4160 …..(4)
Solving all these equations, we get M2 = Rs. 1600. 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeTap L can fill a tank in 16 minutes while Tap M can empty it in 24 minutes. If both the Taps are opened together after how many minutes should Tap B be closed, so that the tank is filled in 30 minutes?
Correct
Answer – 1. 21 minutes
Explanation:
Let the Tap M be closed after ‘x’ minutes.
30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16
=> x = 14/16 x 24 = 21 minutes.Incorrect
Answer – 1. 21 minutes
Explanation:
Let the Tap M be closed after ‘x’ minutes.
30/16 – x/24 = 1 => x/24 = 30/16 – 1 = 14/16
=> x = 14/16 x 24 = 21 minutes. 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeSumita went to shop with certain amount, with which she can buy 50 chocolates or 40 wafers. She uses 10% amount for petrol and out of the remaining balance, she purchases 20 wafers and some chocolates. Find the number of chocolates she can buy?
Correct
Answer – 1. 20
Explanation:
Let the total amount be 200 {L.C.M of 40 and 50}
chocolate C.P. = 200/50 = 4
wafer C.P = 200/40 = 5
Remaining Money after petrol = [200 – 200×10%] = 180
Remaining money after buying wafers = [180 – 20×5] = 80
So number of chocolates she can buy = 80/4 = 20Incorrect
Answer – 1. 20
Explanation:
Let the total amount be 200 {L.C.M of 40 and 50}
chocolate C.P. = 200/50 = 4
wafer C.P = 200/40 = 5
Remaining Money after petrol = [200 – 200×10%] = 180
Remaining money after buying wafers = [180 – 20×5] = 80
So number of chocolates she can buy = 80/4 = 20 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeIn a box, there are 9 blue, 6 white and some black pencils. A pencil is randomly selected and the probability that the pencil is black is ¼. Find the total number of pencils in the box?
Correct
Answer – 3. 20
Explanation:
Total probability = 1
Given probability of black pencils = 1/4
=> Probability of blue and white pencils = 1 – 1/4 = 3/4
But, given blue + white pencils = 9 + 6 = 15
Hence,
3/4 —– 15
1 —– ?
=> 15 x 4/3 = 20.
Hence, total number of pencils in the box = 20.Incorrect
Answer – 3. 20
Explanation:
Total probability = 1
Given probability of black pencils = 1/4
=> Probability of blue and white pencils = 1 – 1/4 = 3/4
But, given blue + white pencils = 9 + 6 = 15
Hence,
3/4 —– 15
1 —– ?
=> 15 x 4/3 = 20.
Hence, total number of pencils in the box = 20. 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude5, 3, 4, 10, 44, ?
Correct
Answer – 5. 360
Explanation:
5*0.5 + 0.5 = 3
3*1 + 1 = 4
4*2 + 2 = 10
10*4 + 4 = 44
44*8 + 8 = 360Incorrect
Answer – 5. 360
Explanation:
5*0.5 + 0.5 = 3
3*1 + 1 = 4
4*2 + 2 = 10
10*4 + 4 = 44
44*8 + 8 = 360 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude8, 7, 13, 38, 151, ?
Correct
Answer – 3. 754
Explanation:
8*1 – 1 = 7
7*2 – 1 = 13
13*3 – 1 = 38
38*4 – 1 = 151
151*5 – 1 = 754Incorrect
Answer – 3. 754
Explanation:
8*1 – 1 = 7
7*2 – 1 = 13
13*3 – 1 = 38
38*4 – 1 = 151
151*5 – 1 = 754 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude√(58% of 1450) – 12% of 650 + √4356= x
Correct
Answer – 2. 17
Explanation:
√841 – 78 + 66 = 29 – 78 + 66 = 11Incorrect
Answer – 2. 17
Explanation:
√841 – 78 + 66 = 29 – 78 + 66 = 11 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude16 * 28 – 18% of 1150 = ?
Correct
Answer – 4. 241
Explanation:
448 – 207 = 241Incorrect
Answer – 4. 241
Explanation:
448 – 207 = 241 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeAn express train travelling with a speed of 60 kmph catches goods train travelling in the same direction and then leaves it 120m behind in 18 seconds. The speed of the goods train is
Correct
Answer – 3. 36 kmph
Explanation:
Speed of the express train = 60 km/hr = 60 x 5/18 = 50/3 m/s
Let the speed of the goods train = x m/s
Then, the difference in the speed is given by
50/3 − x = 120/18
=> x = 10 m/s
=> 10 x 18/5 = 36 km/hrIncorrect
Answer – 3. 36 kmph
Explanation:
Speed of the express train = 60 km/hr = 60 x 5/18 = 50/3 m/s
Let the speed of the goods train = x m/s
Then, the difference in the speed is given by
50/3 − x = 120/18
=> x = 10 m/s
=> 10 x 18/5 = 36 km/hr
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