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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Total distance between P & Q is ‘Z’ km. If the distance covered along the stream is three times of the total distance and the distance covered against the stream is two times of the total distance. If the time taken to cover the distance along the stream is 10% less than the time taken to cover the distance against the stream. If Suresh cover a distance of 21 km in 1 hour 24 minutes along the stream, then find the twice of the rate of current?**CorrectAnswer –

**3. 6 kmph**

Explanation:

Distance covered along the stream = 3Z

Distance covered against the stream = 2Z

Speed of boat in still water = x kmph

Speed of current = y kmph

21/x+y = 7/5

x + y = 15

3Z/x+y = 90/100 * 2Z/x-y

x – y = 9

x = 12 y = 3 * 2 = 6IncorrectAnswer –

**3. 6 kmph**

Explanation:

Distance covered along the stream = 3Z

Distance covered against the stream = 2Z

Speed of boat in still water = x kmph

Speed of current = y kmph

21/x+y = 7/5

x + y = 15

3Z/x+y = 90/100 * 2Z/x-y

x – y = 9

x = 12 y = 3 * 2 = 6 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**L, M, N invested Rs 900, Rs 1600, Rs 700 respectively in a business. After end of the first quarter they invested additional amount in the ratio of 2:5:3. The after end of 2nd quarter L,M,N invested additional amount in the ratio 4:3:4. Again after end of the 3rd quarter they invested additional amount in the ratio 7: 6:7. They invested the whole amount for one year and the profit earned in the business is proportional to the investment and the period of investment. If they had invested additional amount at the end of each quarter in same ratio as they had invested after end of the 1st quarter then find the profit of M at the end of one year if the total profit at the end of the year is 150000.**CorrectAnswer –

**1. 75000**

Explanation:

Sum of investment of L & N is equal to M for first quarter

(L+N) : M

So Profit of M = 150000 *1/2= 75000IncorrectAnswer –

**1. 75000**

Explanation:

Sum of investment of L & N is equal to M for first quarter

(L+N) : M

So Profit of M = 150000 *1/2= 75000 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Two Vessels P and Q. Both contain 20% Acid. The quantity of Vessel P is 4 times than that of quantity of Vessel Q. Both Vessel mixtures are mixed and form new mixture R and 15 litre of water is added. The final ratio of water to Acid is now 19 : 4. Find the initial quantity of Acid in Vessel Q.**CorrectAnswer –

**2. 4**

Explanation:

4x + 15 / x = 19/4

x = 20

Total Acid = 20l

Acid in Vessel Q = 1/5 * 20 = 4lIncorrectAnswer –

**2. 4**

Explanation:

4x + 15 / x = 19/4

x = 20

Total Acid = 20l

Acid in Vessel Q = 1/5 * 20 = 4l - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**The ratio of task done by 30 girls to the task done by 25 boys, in the same time period is 5:6. If 9 girls and 10 boys can finish a task in 40/3 days. Then how many girls required to complete the task in 6 days?**CorrectAnswer –

**3. 12**

Explanation:

Ratio of efficiency = 5*5/6 : 6

= 25 : 36

A man can finish the task in 25x days

A woman can finish the task in 36x days

9/36x + 10/25x = 13/40

Time taken by 1 girl = 72 days

72/6 = 12IncorrectAnswer –

**3. 12**

Explanation:

Ratio of efficiency = 5*5/6 : 6

= 25 : 36

A man can finish the task in 25x days

A woman can finish the task in 36x days

9/36x + 10/25x = 13/40

Time taken by 1 girl = 72 days

72/6 = 12 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**An LED TV costs 15 times as compared to cost of a Woofer. On each LED TV there is profit of 25%. While the total profit on selling a Woofer and an LED TV is 30%. If there is a profit of Rs 2100 on selling the Woofer then find the total cost price of LED TV and Woofer?**CorrectAnswer –

**3. Rs 32000**

Explanation:

Let CP of Woofer = x

CP of LED TV = 15x

Total SP = 16x * 1.3 = 20.8x

SP of LED TV = 15x * 1.25 = 18.75x

SP of Woofer = 2.05x

Profit = 1.05x = 2100

x = 2000

15x = 30000; 16x = 32000IncorrectAnswer –

**3. Rs 32000**

Explanation:

Let CP of Woofer = x

CP of LED TV = 15x

Total SP = 16x * 1.3 = 20.8x

SP of LED TV = 15x * 1.25 = 18.75x

SP of Woofer = 2.05x

Profit = 1.05x = 2100

x = 2000

15x = 30000; 16x = 32000 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**The marked price of Kurti and a Leggings are in the ratio 2 : 1. The shopkeeper gives 40% discount on the Kurti. If the total discount on the Kurti and Leggings is 30%, the discount offered on the Leggings is.**CorrectAnswer –

**4. 10%**

Explanation:

Let MP of Kurti = 200

MP of Leggings = 100

New Price of Kurti after discount = 120

Let new price of Leggings = x

120 + x = 70/100 * (100 + 200)

x = 90

Discount = (100-90)/100 * 100 = 10%IncorrectAnswer –

**4. 10%**

Explanation:

Let MP of Kurti = 200

MP of Leggings = 100

New Price of Kurti after discount = 120

Let new price of Leggings = x

120 + x = 70/100 * (100 + 200)

x = 90

Discount = (100-90)/100 * 100 = 10% - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions.Q(7-8). Express “L” & Express “M” are travelling towards each other from stations N & O. Express L left station N at 9:45 am with speed of 54 kmph. After half an hour Express M left station O with a speed of 66 kmph. Station N & O are situated at a distance of “Y” km and both Express met each other at 2:35 pm on the same day.**Find the difference in the original time taken as given above in condition to meet Express L & M and the time taken by Express M to catch Express L if the Express L had started in same direction as that of M. Express M had started 2 hrs after Express L while going in same direction.

CorrectAnswer –

**1. 49 hours 45 minutes**

Explanation:

Their relative speed = 54+66=120 kmph

In first half an hour Express “L” run=1/2 * 54=27 Km

Both Express meet 2:35 so they Take time meet after “M” left

2:35-(9:45+30 minutes)=4 hours 20 minutes

In 4 hours 20 minutes (4+20/60=13/3 hr) they run,

120 *13/3=520 km

So total distance = 520+27=547 km

In 2 hours, L goes 54 *2=108 m

In same direction M will cross the distance =547+108=655 km

In 655 km, they will take the time = 655/12=54 hours 35 minutes

So difference of time =54 hours 35 minutes – 4 hours 50 minutes = 49 hours 45 minutesIncorrectAnswer –

**1. 49 hours 45 minutes**

Explanation:

Their relative speed = 54+66=120 kmph

In first half an hour Express “L” run=1/2 * 54=27 Km

Both Express meet 2:35 so they Take time meet after “M” left

2:35-(9:45+30 minutes)=4 hours 20 minutes

In 4 hours 20 minutes (4+20/60=13/3 hr) they run,

120 *13/3=520 km

So total distance = 520+27=547 km

In 2 hours, L goes 54 *2=108 m

In same direction M will cross the distance =547+108=655 km

In 655 km, they will take the time = 655/12=54 hours 35 minutes

So difference of time =54 hours 35 minutes – 4 hours 50 minutes = 49 hours 45 minutes - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative AptitudeDirections.Q(7-8). Express “L” & Express “M” are travelling towards each other from stations N & O. Express L left station N at 9:45 am with speed of 54 kmph. After half an hour Express M left station O with a speed of 66 kmph. Station N & O are situated at a distance of “Y” km and both Express met each other at 2:35 pm on the same day.

**What is the ratio of relative speed of both the Express while travelling towards the same direction and while travelling towards opposite directions?**CorrectAnswer –

**3. 1:10**

Explanation:

(66-54):(66+54)

= 1 : 10IncorrectAnswer –

**3. 1:10**

Explanation:

(66-54):(66+54)

= 1 : 10 - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Inlet Pipe P takes 3 minutes more to fill the container than two inlet pipes P & Q opened together to fill it. Second inlet pipe Q takes 64/3 minutes more to fill container than two inlet pipes P & Q opened together to fill it. When will the container be full if both the pipes are opened simultaneously.**CorrectAnswer –

**3. 8 minutes**

Explanation:

1/x = 1/(x + 3) + 3/(3x + 64)

1/x = [ 3x + 64 + 3(x + 3) ] ÷ [(x + 3)(3x + 64) ]

1/x = [ 3x + 64 + 3x + 9 ] ÷ [ 3x² + 64x + 9x + 192 ]

1/x = (6x + 73) ÷ (3x² + 73x + 192)

3x² + 73x + 192 = 6x² + 73x

3x² = 192

x² = 64

x = 8 or -8

So, x = 8 minutesIncorrectAnswer –

**3. 8 minutes**

Explanation:

1/x = 1/(x + 3) + 3/(3x + 64)

1/x = [ 3x + 64 + 3(x + 3) ] ÷ [(x + 3)(3x + 64) ]

1/x = [ 3x + 64 + 3x + 9 ] ÷ [ 3x² + 64x + 9x + 192 ]

1/x = (6x + 73) ÷ (3x² + 73x + 192)

3x² + 73x + 192 = 6x² + 73x

3x² = 192

x² = 64

x = 8 or -8

So, x = 8 minutes - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**The length, breadth and height of a room are in the ratio 8:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased?**CorrectAnswer –

**5. 90%**

Explanation:

Let length, breadth and height of the room be 8, 3, 1 unit respectively.

Area of walls = 2(l+b)xh = 2(8+3)x1 = 22 sq. unit.

Now, length, breadth and height of room will become 3.5, 6 and 2 respectively.

Area of walls = 2(l+b)xh = 2(4+6)x2 = 40 sq. unit.

% Increase in the area of walls = (40-22)/20 *100 = 90%.IncorrectAnswer –

**5. 90%**

Explanation:

Let length, breadth and height of the room be 8, 3, 1 unit respectively.

Area of walls = 2(l+b)xh = 2(8+3)x1 = 22 sq. unit.

Now, length, breadth and height of room will become 3.5, 6 and 2 respectively.

Area of walls = 2(l+b)xh = 2(4+6)x2 = 40 sq. unit.

% Increase in the area of walls = (40-22)/20 *100 = 90%.

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