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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Total distance between P & Q is ‘Z’ km. If the distance covered along the stream is three times of the total distance and the distance covered against the stream is two times of the total distance. If the time taken to cover the distance along the stream is 10% less than the time taken to cover the distance against the stream. If Suresh cover a distance of 21 km in 1 hour 24 minutes along the stream, then find the twice of the rate of current?

Correct

Answer – 3. 6 kmph
Explanation:
Distance covered along the stream = 3Z
Distance covered against the stream = 2Z
Speed of boat in still water = x kmph
Speed of current = y kmph
21/x+y = 7/5
x + y = 15
3Z/x+y = 90/100 * 2Z/x-y
x – y = 9
x = 12 y = 3 * 2 = 6

Incorrect

Answer – 3. 6 kmph
Explanation:
Distance covered along the stream = 3Z
Distance covered against the stream = 2Z
Speed of boat in still water = x kmph
Speed of current = y kmph
21/x+y = 7/5
x + y = 15
3Z/x+y = 90/100 * 2Z/x-y
x – y = 9
x = 12 y = 3 * 2 = 6

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

L, M, N invested Rs 900, Rs 1600, Rs 700 respectively in a business. After end of the first quarter they invested additional amount in the ratio of 2:5:3. The after end of 2nd quarter L,M,N invested additional amount in the ratio 4:3:4. Again after end of the 3rd quarter they invested additional amount in the ratio 7: 6:7. They invested the whole amount for one year and the profit earned in the business is proportional to the investment and the period of investment. If they had invested additional amount at the end of each quarter in same ratio as they had invested after end of the 1st quarter then find the profit of M at the end of one year if the total profit at the end of the year is 150000.

Correct

Answer – 1. 75000
Explanation:
Sum of investment of L & N is equal to M for first quarter
(L+N) : M
So Profit of M = 150000 *1/2= 75000

Incorrect

Answer – 1. 75000
Explanation:
Sum of investment of L & N is equal to M for first quarter
(L+N) : M
So Profit of M = 150000 *1/2= 75000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Two Vessels P and Q. Both contain 20% Acid. The quantity of Vessel P is 4 times than that of quantity of Vessel Q. Both Vessel mixtures are mixed and form new mixture R and 15 litre of water is added. The final ratio of water to Acid is now 19 : 4. Find the initial quantity of Acid in Vessel Q.

Correct

Answer – 2. 4
Explanation:
4x + 15 / x = 19/4
x = 20
Total Acid = 20l
Acid in Vessel Q = 1/5 * 20 = 4l

Incorrect

Answer – 2. 4
Explanation:
4x + 15 / x = 19/4
x = 20
Total Acid = 20l
Acid in Vessel Q = 1/5 * 20 = 4l

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The ratio of task done by 30 girls to the task done by 25 boys, in the same time period is 5:6. If 9 girls and 10 boys can finish a task in 40/3 days. Then how many girls required to complete the task in 6 days?

Correct

Answer – 3. 12
Explanation:
Ratio of efficiency = 5*5/6 : 6
= 25 : 36
A man can finish the task in 25x days
A woman can finish the task in 36x days
9/36x + 10/25x = 13/40
Time taken by 1 girl = 72 days
72/6 = 12

Incorrect

Answer – 3. 12
Explanation:
Ratio of efficiency = 5*5/6 : 6
= 25 : 36
A man can finish the task in 25x days
A woman can finish the task in 36x days
9/36x + 10/25x = 13/40
Time taken by 1 girl = 72 days
72/6 = 12

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

An LED TV costs 15 times as compared to cost of a Woofer. On each LED TV there is profit of 25%. While the total profit on selling a Woofer and an LED TV is 30%. If there is a profit of Rs 2100 on selling the Woofer then find the total cost price of LED TV and Woofer?

Correct

Answer – 3. Rs 32000
Explanation:
Let CP of Woofer = x
CP of LED TV = 15x
Total SP = 16x * 1.3 = 20.8x
SP of LED TV = 15x * 1.25 = 18.75x
SP of Woofer = 2.05x
Profit = 1.05x = 2100
x = 2000
15x = 30000; 16x = 32000

Incorrect

Answer – 3. Rs 32000
Explanation:
Let CP of Woofer = x
CP of LED TV = 15x
Total SP = 16x * 1.3 = 20.8x
SP of LED TV = 15x * 1.25 = 18.75x
SP of Woofer = 2.05x
Profit = 1.05x = 2100
x = 2000
15x = 30000; 16x = 32000

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The marked price of Kurti and a Leggings are in the ratio 2 : 1. The shopkeeper gives 40% discount on the Kurti. If the total discount on the Kurti and Leggings is 30%, the discount offered on the Leggings is.

Correct

Answer – 4. 10%
Explanation:
Let MP of Kurti = 200
MP of Leggings = 100
New Price of Kurti after discount = 120
Let new price of Leggings = x
120 + x = 70/100 * (100 + 200)
x = 90
Discount = (100-90)/100 * 100 = 10%

Incorrect

Answer – 4. 10%
Explanation:
Let MP of Kurti = 200
MP of Leggings = 100
New Price of Kurti after discount = 120
Let new price of Leggings = x
120 + x = 70/100 * (100 + 200)
x = 90
Discount = (100-90)/100 * 100 = 10%

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions.Q(7-8). Express “L” & Express “M” are travelling towards each other from stations N & O. Express L left station N at 9:45 am with speed of 54 kmph. After half an hour Express M left station O with a speed of 66 kmph. Station N & O are situated at a distance of “Y” km and both Express met each other at 2:35 pm on the same day.

Find the difference in the original time taken as given above in condition to meet Express L & M and the time taken by Express M to catch Express L if the Express L had started in same direction as that of M. Express M had started 2 hrs after Express L while going in same direction.

Correct

Answer – 1. 49 hours 45 minutes
Explanation:
Their relative speed = 54+66=120 kmph
In first half an hour Express “L” run=1/2 * 54=27 Km
Both Express meet 2:35 so they Take time meet after “M” left
2:35-(9:45+30 minutes)=4 hours 20 minutes
In 4 hours 20 minutes (4+20/60=13/3 hr) they run,
120 *13/3=520 km
So total distance = 520+27=547 km
In 2 hours, L goes 54 *2=108 m
In same direction M will cross the distance =547+108=655 km
In 655 km, they will take the time = 655/12=54 hours 35 minutes
So difference of time =54 hours 35 minutes – 4 hours 50 minutes = 49 hours 45 minutes

Incorrect

Answer – 1. 49 hours 45 minutes
Explanation:
Their relative speed = 54+66=120 kmph
In first half an hour Express “L” run=1/2 * 54=27 Km
Both Express meet 2:35 so they Take time meet after “M” left
2:35-(9:45+30 minutes)=4 hours 20 minutes
In 4 hours 20 minutes (4+20/60=13/3 hr) they run,
120 *13/3=520 km
So total distance = 520+27=547 km
In 2 hours, L goes 54 *2=108 m
In same direction M will cross the distance =547+108=655 km
In 655 km, they will take the time = 655/12=54 hours 35 minutes
So difference of time =54 hours 35 minutes – 4 hours 50 minutes = 49 hours 45 minutes

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions.Q(7-8). Express “L” & Express “M” are travelling towards each other from stations N & O. Express L left station N at 9:45 am with speed of 54 kmph. After half an hour Express M left station O with a speed of 66 kmph. Station N & O are situated at a distance of “Y” km and both Express met each other at 2:35 pm on the same day.

What is the ratio of relative speed of both the Express while travelling towards the same direction and while travelling towards opposite directions?

Inlet Pipe P takes 3 minutes more to fill the container than two inlet pipes P & Q opened together to fill it. Second inlet pipe Q takes 64/3 minutes more to fill container than two inlet pipes P & Q opened together to fill it. When will the container be full if both the pipes are opened simultaneously.

The length, breadth and height of a room are in the ratio 8:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased?

Correct

Answer – 5. 90%
Explanation:
Let length, breadth and height of the room be 8, 3, 1 unit respectively.
Area of walls = 2(l+b)xh = 2(8+3)x1 = 22 sq. unit.
Now, length, breadth and height of room will become 3.5, 6 and 2 respectively.
Area of walls = 2(l+b)xh = 2(4+6)x2 = 40 sq. unit.
% Increase in the area of walls = (40-22)/20 *100 = 90%.

Incorrect

Answer – 5. 90%
Explanation:
Let length, breadth and height of the room be 8, 3, 1 unit respectively.
Area of walls = 2(l+b)xh = 2(8+3)x1 = 22 sq. unit.
Now, length, breadth and height of room will become 3.5, 6 and 2 respectively.
Area of walls = 2(l+b)xh = 2(4+6)x2 = 40 sq. unit.
% Increase in the area of walls = (40-22)/20 *100 = 90%.

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