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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhen the price of Finger Millet was increased by 32%, a hostel reduced its consumption in such a way that the expenditure on Finger Millet was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of hostel?
Correct
Answer – 25 kg
Explanation:
Initial Finger Millet per kg cost be Rs. 100
Then, monthly expenditure of the hostel = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of hostel.
X x 132 = 110/100 x 3000
=> X = 25 kg.Incorrect
Answer – 25 kg
Explanation:
Initial Finger Millet per kg cost be Rs. 100
Then, monthly expenditure of the hostel = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of hostel.
X x 132 = 110/100 x 3000
=> X = 25 kg. 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeUsha lent Rs. 16000 partly at the rate of 5% and partly at the rate of 6% per annum SI. The total interest she get after 2 years is Rs. 1640, then in which ratio will Rs. 16000 is to be divided?
Correct
Answer – 1. 7:1
Explanation:
1640 = x*5*2/100 + [16000x]*6*2/100
164000 = 10x + 192000 – 12x
x = 14000
16000 x = 2000
=>14000:2000
=>7:1Incorrect
Answer – 1. 7:1
Explanation:
1640 = x*5*2/100 + [16000x]*6*2/100
164000 = 10x + 192000 – 12x
x = 14000
16000 x = 2000
=>14000:2000
=>7:1 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA wholesale seller buys two Sarees for Rs. 7500. One Saree he sells at a profit of 16% and the other Saree at 14% loss. In the deal, the wholesale seller makes neither any profit nor any loss. What is the difference between the selling price of both the Sarees?
Correct
Answer – 1. Rs. 620
Explanation:
Let the C.P of one Saree is Rs. X
and that of other is Rs. (7500 – X)
According to the data given
C.P = S.P
=> Px(116/100) + (7500X)x(86/100) = 7500
=> 30X = 105000
=> X = 3500
Required difference between selling prices
= Rs. [(3500/100) x 116] – [(4000/100) x 86]
= 40603440
= Rs. 620Incorrect
Answer – 1. Rs. 620
Explanation:
Let the C.P of one Saree is Rs. X
and that of other is Rs. (7500 – X)
According to the data given
C.P = S.P
=> Px(116/100) + (7500X)x(86/100) = 7500
=> 30X = 105000
=> X = 3500
Required difference between selling prices
= Rs. [(3500/100) x 116] – [(4000/100) x 86]
= 40603440
= Rs. 620 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudePooja’s downstream swimming rate is four times of her upstream swimming rate. If she covers 12 km upstream in 2.5 hours, what distance she will cover in 5 hours downstream?
Correct
Answer – 3. 96 km
Explanation:
upstream speed = 12/2.5 = 4.8 km/hr
Downstream speed = 4.8 x 4 = 19.2 km/hr
Distance she covers downstream in 5 hrs = 19.2 x 5 = 96 km.Incorrect
Answer – 3. 96 km
Explanation:
upstream speed = 12/2.5 = 4.8 km/hr
Downstream speed = 4.8 x 4 = 19.2 km/hr
Distance she covers downstream in 5 hrs = 19.2 x 5 = 96 km. 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeRavi rides on a scooty to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 minutes more than that of the first case, what is the total distance travelled by him (in km)?
Correct
Answer – 4. 264 km
Explanation:
Let the distance travelled by Ravi in first case or second case = d km
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hours
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 km.Incorrect
Answer – 4. 264 km
Explanation:
Let the distance travelled by Ravi in first case or second case = d km
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hours
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 km. 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe Agra Express which is running at 48 km per hour crosses another Express train namely Andhra Pradesh Express, having half its length and travelling in opposite direction at 42 km per hour, in twelve seconds. It also covers a Platform in 45 seconds. Find out the length of the Platform?
Correct
Answer – 2. 400 m
Explanation:
Let the length of the Agra Express = L m
Speed of Agra Express = 48 kmph
Now the length of the Andhra Pradesh Express = L/2 m
Speed of Andhra Pradesh Express = 42 kmph
Let the length of the Platform = X m
Distance = L + L/2 = 3L/2
Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite)
Time = 12 seconds
=> 3L/2 x 25 = 12
=> L = 200 m
Now it covers the Platform in 45 sec
=> distance = X + 200
Time = 45 s
Speed = 48 x5/18 = 40/3 m/s
=> X + 200/(40/3) = 45
=> X = 600 – 200 = 400 m
Hence, the length of the Platform = 400 m.Incorrect
Answer – 2. 400 m
Explanation:
Let the length of the Agra Express = L m
Speed of Agra Express = 48 kmph
Now the length of the Andhra Pradesh Express = L/2 m
Speed of Andhra Pradesh Express = 42 kmph
Let the length of the Platform = X m
Distance = L + L/2 = 3L/2
Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite)
Time = 12 seconds
=> 3L/2 x 25 = 12
=> L = 200 m
Now it covers the Platform in 45 sec
=> distance = X + 200
Time = 45 s
Speed = 48 x5/18 = 40/3 m/s
=> X + 200/(40/3) = 45
=> X = 600 – 200 = 400 m
Hence, the length of the Platform = 400 m. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe ratio of efficiencies of Prince, Queen and Rose is 2 : 3 : 4. While Prince and Rose work on alternate days and Queen work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1800. Find the amount of each person(respectively).
Correct
Answer – 2. 300, 900, 600
Explanation:
Ratio of efficiencies of Prince, Queen and Rose = 2 : 3 : 4
From the given data,
Number of working days of Prince, Queen, Rose = 5 : 10 : 5
Hence, ratio of amount of Prince, Queen, Rose = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Prince, Queen, Rose = 300, 900 and 600.Incorrect
Answer – 2. 300, 900, 600
Explanation:
Ratio of efficiencies of Prince, Queen and Rose = 2 : 3 : 4
From the given data,
Number of working days of Prince, Queen, Rose = 5 : 10 : 5
Hence, ratio of amount of Prince, Queen, Rose = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Prince, Queen, Rose = 300, 900 and 600. 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA container can be filled by two pipes P and Q in 60 and 40 minutes respectively. How many minutes will it take to fill the container from empty state if Q is used for half the time and P and Q fill it together for the other half?
Correct
Answer – 4. 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutesIncorrect
Answer – 4. 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutes 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIn a mug, there is a mixture of honey and sugar solution in the ratio 4 : 5. If it is filled with an additional 8 litre of honey, the mug would be full and ratio of honey and sugar solution would become 6 : 5. Find the capacity of the mug?
Correct
Answer – 4. 44 l
Explanation:
Let the capacity of the mug be ‘X’ litres.
Quantity of honey in the mixture before adding honey = 4/9 (X – 8)
After adding honey, quantity of honey in the mixture = 6/11 P.
6X/11 – 8 = 4/9(X – 8)
10X = 792 – 352 => X = 44.
The capacity of the mug is 44 lIncorrect
Answer – 4. 44 l
Explanation:
Let the capacity of the mug be ‘X’ litres.
Quantity of honey in the mixture before adding honey = 4/9 (X – 8)
After adding honey, quantity of honey in the mixture = 6/11 P.
6X/11 – 8 = 4/9(X – 8)
10X = 792 – 352 => X = 44.
The capacity of the mug is 44 l 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIn a building, the length of a corridor exceeds its breadth by 25 m. The area of the corridor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. What is the sum of the length and the breadth of the corridor?
Correct
Answer – 4. 145 m
Explanation:
Let the breadth of corridor be ‘b’ m.
Then, length of the corridor is ‘l = (b + 25)’
Area of the rectangular corridor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Sum = 85 + 60 = 145Incorrect
Answer – 4. 145 m
Explanation:
Let the breadth of corridor be ‘b’ m.
Then, length of the corridor is ‘l = (b + 25)’
Area of the rectangular corridor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Sum = 85 + 60 = 145
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