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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

When the price of Finger Millet was increased by 32%, a hostel reduced its consumption in such a way that the expenditure on Finger Millet was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of hostel?

Correct

Answer – 25 kg
Explanation:
Initial Finger Millet per kg cost be Rs. 100
Then, monthly expenditure of the hostel = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of hostel.
X x 132 = 110/100 x 3000
=> X = 25 kg.

Incorrect

Answer – 25 kg
Explanation:
Initial Finger Millet per kg cost be Rs. 100
Then, monthly expenditure of the hostel = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of hostel.
X x 132 = 110/100 x 3000
=> X = 25 kg.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Usha lent Rs. 16000 partly at the rate of 5% and partly at the rate of 6% per annum SI. The total interest she get after 2 years is Rs. 1640, then in which ratio will Rs. 16000 is to be divided?

A wholesale seller buys two Sarees for Rs. 7500. One Saree he sells at a profit of 16% and the other Saree at 14% loss. In the deal, the wholesale seller makes neither any profit nor any loss. What is the difference between the selling price of both the Sarees?

Correct

Answer – 1. Rs. 620
Explanation:
Let the C.P of one Saree is Rs. X
and that of other is Rs. (7500 – X)
According to the data given
C.P = S.P
=> Px(116/100) + (7500-X)x(86/100) = 7500
=> 30X = 105000
=> X = 3500
Required difference between selling prices
= Rs. [(3500/100) x 116] – [(4000/100) x 86]
= 4060-3440
= Rs. 620

Incorrect

Answer – 1. Rs. 620
Explanation:
Let the C.P of one Saree is Rs. X
and that of other is Rs. (7500 – X)
According to the data given
C.P = S.P
=> Px(116/100) + (7500-X)x(86/100) = 7500
=> 30X = 105000
=> X = 3500
Required difference between selling prices
= Rs. [(3500/100) x 116] – [(4000/100) x 86]
= 4060-3440
= Rs. 620

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Pooja’s downstream swimming rate is four times of her upstream swimming rate. If she covers 12 km upstream in 2.5 hours, what distance she will cover in 5 hours downstream?

Correct

Answer – 3. 96 km
Explanation:
upstream speed = 12/2.5 = 4.8 km/hr
Downstream speed = 4.8 x 4 = 19.2 km/hr
Distance she covers downstream in 5 hrs = 19.2 x 5 = 96 km.

Incorrect

Answer – 3. 96 km
Explanation:
upstream speed = 12/2.5 = 4.8 km/hr
Downstream speed = 4.8 x 4 = 19.2 km/hr
Distance she covers downstream in 5 hrs = 19.2 x 5 = 96 km.

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Ravi rides on a scooty to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 minutes more than that of the first case, what is the total distance travelled by him (in km)?

Correct

Answer – 4. 264 km
Explanation:
Let the distance travelled by Ravi in first case or second case = d km
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hours
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 km.

Incorrect

Answer – 4. 264 km
Explanation:
Let the distance travelled by Ravi in first case or second case = d km
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hours
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 km.

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The Agra Express which is running at 48 km per hour crosses another Express train namely Andhra Pradesh Express, having half its length and travelling in opposite direction at 42 km per hour, in twelve seconds. It also covers a Platform in 45 seconds. Find out the length of the Platform?

Correct

Answer – 2. 400 m
Explanation:
Let the length of the Agra Express = L m
Speed of Agra Express = 48 kmph
Now the length of the Andhra Pradesh Express = L/2 m
Speed of Andhra Pradesh Express = 42 kmph
Let the length of the Platform = X m
Distance = L + L/2 = 3L/2
Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite)
Time = 12 seconds
=> 3L/2 x 25 = 12
=> L = 200 m
Now it covers the Platform in 45 sec
=> distance = X + 200
Time = 45 s
Speed = 48 x5/18 = 40/3 m/s
=> X + 200/(40/3) = 45
=> X = 600 – 200 = 400 m
Hence, the length of the Platform = 400 m.

Incorrect

Answer – 2. 400 m
Explanation:
Let the length of the Agra Express = L m
Speed of Agra Express = 48 kmph
Now the length of the Andhra Pradesh Express = L/2 m
Speed of Andhra Pradesh Express = 42 kmph
Let the length of the Platform = X m
Distance = L + L/2 = 3L/2
Relative speed = 48 + 42 = 90 kmph = 90 x 5/18 = 25 m/s(opposite)
Time = 12 seconds
=> 3L/2 x 25 = 12
=> L = 200 m
Now it covers the Platform in 45 sec
=> distance = X + 200
Time = 45 s
Speed = 48 x5/18 = 40/3 m/s
=> X + 200/(40/3) = 45
=> X = 600 – 200 = 400 m
Hence, the length of the Platform = 400 m.

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The ratio of efficiencies of Prince, Queen and Rose is 2 : 3 : 4. While Prince and Rose work on alternate days and Queen work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1800. Find the amount of each person(respectively).

Correct

Answer – 2. 300, 900, 600
Explanation:
Ratio of efficiencies of Prince, Queen and Rose = 2 : 3 : 4
From the given data,
Number of working days of Prince, Queen, Rose = 5 : 10 : 5
Hence, ratio of amount of Prince, Queen, Rose = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Prince, Queen, Rose = 300, 900 and 600.

Incorrect

Answer – 2. 300, 900, 600
Explanation:
Ratio of efficiencies of Prince, Queen and Rose = 2 : 3 : 4
From the given data,
Number of working days of Prince, Queen, Rose = 5 : 10 : 5
Hence, ratio of amount of Prince, Queen, Rose = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Prince, Queen, Rose = 300, 900 and 600.

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A container can be filled by two pipes P and Q in 60 and 40 minutes respectively. How many minutes will it take to fill the container from empty state if Q is used for half the time and P and Q fill it together for the other half?

Correct

Answer – 4. 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutes

Incorrect

Answer – 4. 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutes

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

In a mug, there is a mixture of honey and sugar solution in the ratio 4 : 5. If it is filled with an additional 8 litre of honey, the mug would be full and ratio of honey and sugar solution would become 6 : 5. Find the capacity of the mug?

Correct

Answer – 4. 44 l
Explanation:
Let the capacity of the mug be ‘X’ litres.
Quantity of honey in the mixture before adding honey = 4/9 (X – 8)
After adding honey, quantity of honey in the mixture = 6/11 P.
6X/11 – 8 = 4/9(X – 8)
10X = 792 – 352 => X = 44.
The capacity of the mug is 44 l

Incorrect

Answer – 4. 44 l
Explanation:
Let the capacity of the mug be ‘X’ litres.
Quantity of honey in the mixture before adding honey = 4/9 (X – 8)
After adding honey, quantity of honey in the mixture = 6/11 P.
6X/11 – 8 = 4/9(X – 8)
10X = 792 – 352 => X = 44.
The capacity of the mug is 44 l

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

In a building, the length of a corridor exceeds its breadth by 25 m. The area of the corridor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. What is the sum of the length and the breadth of the corridor?

Correct

Answer – 4. 145 m
Explanation:
Let the breadth of corridor be ‘b’ m.
Then, length of the corridor is ‘l = (b + 25)’
Area of the rectangular corridor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Sum = 85 + 60 = 145

Incorrect

Answer – 4. 145 m
Explanation:
Let the breadth of corridor be ‘b’ m.
Then, length of the corridor is ‘l = (b + 25)’
Area of the rectangular corridor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Sum = 85 + 60 = 145

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