Hello Aspirants.

Welcome to Online Reasoning Section in AffairsCloud.com. Here we are creating question sample in **Coding and Decoding**, which is common for all competitive exams. We have included Some questions that are repeatedly asked in bank exams!!!

**Directions (1 – 5): Study the following information carefully and answer the questions given below. **

There is 3*5 matrix which can produce signals which in turn help in the illumination of some bulbs. The row of the matrix are denoted by $, & and * from bottom to top and the columns are denoted by the alphabets P, Q, R, S and T from left to right.

$ row contains number which are consecutive multiple of 7, staring from 28 (from left to right).

& row contains numbers which are consecutive multiple of 11, starting from 11 (from left to right).

* row contains number which are consecutive multiple of 13, starting from 13 (from left to right).

The matrix helps in producing signals which can be either a single string of number X- or two-line string X and Y.

There are 4 lights A, B, C and D. Based on the outcome of the strings mentioned above one of the light blinks.

**Condition for blink:**

1. If the outcome is below 85, then A will blink

2. If outcome range is 85-110, then B blinks

3. If outcome range is 111-210, then C blinks

4. If outcome is greater than 210, then D blinks

**For outcome of the string:**

1. If the string has all even numbers, then outcome of the string is obtained by adding all the numbers.

2. If an odd number is followed by an even number then the one’s places of all the two-digit numbers are deleted and, tenth place are multiplied to get the outcome

3. If the string contains 2 prime number, then the tenth’s place is deleted from each of the two-digit number and remaining number are multiplied.

4. If no above logic is followed, then simple outcome is addition of the numbers.

**If X = *R &S *P *T, then which bulb blink?**

1) D

2) B

3) A

4) C

5) Either C or DAnswer –**3) A**

**Solution:**

For matrix formation:

There is 3 × 5 matrix.

The row of the matrix are denoted by $, & and * from bottom to top and the columns are denoted by the alphabets P, Q, R, S and T from left to right.

**X = *R &S *P *T**

X = 39 44 13 65

Condition 2 is applicable here: If an odd number is followed by an even number then the one’s places of all the two-digit numbers are deleted and, tenth place are multiplied to get the outcome

X = 3 × 4 × 1 × 6 = 72

As the outcome is below 85, hence bulb A will blink.**If X = $P $R *S &Q, then which bulb blink?**

1) D

2) B

3) A

4) C

5) Either A or BAnswer –**4) C**

**Solution:**

**X = $P $R *S &Q**

X = 28 42 52 22

Condition 1 is applicable here: If the string has all even numbers, then outcome of the string is obtained by adding all the numbers.

X = 28 + 42 + 52 + 22 = 144

As the outcome of the string is between 111 – 210, hence bulb C will blink.**If X = *P &T &P $Q, then which bulb blink?**

1) D

2) B

3) A

4) C

5) Either A or BAnswer –**3) A**

**Solution:**

X = *P &T &P $Q

X = 13 55 11 35

Condition 3 is applicable here: If the string contains 2 prime number, then the tenth’s place is deleted from each of the two-digit number and remaining number are multiplied.

X = 3 × 5 × 1 × 5 = 75

As the outcome is below 85, hence bulb A will blink.**If X = $P *Q $S &R, then which bulb blink?**

1) D

2) B

3) A

4) C

5) Either C or DAnswer –**4) C**

**Solution:**

X = $P *Q $S &R

X = 28 26 49 33

Condition 4 is applicable here: If no above logic is followed, then simple outcome is addition of the numbers.

X = 28 + 26 + 49 + 33 = 136

As the outcome of the string is between 111 – 210, hence bulb C will blink.**If X = $T *S $S *T, then which bulb blink?**

1) D

2) B

3) A

4) C

5) Either C or DAnswer –**1) D**

**Solution:**

**X = $T *S $S *T**

X = 56 52 49 65

Condition 4 is applicable here: If no above logic is followed, then simple outcome is addition of the numbers.

X = 56 + 52 + 49 + 65 = 222

As the outcome of the string is greater than 210, hence bulb D will blink.

**(Direction 6 – 10): Read the following information carefully and answer the questions that follow:**

In a certain code language,

“Regular fitness sound health” is coded as “J&10 X&15 X#4 P&1”

“Proove gear what times” is coded as “[email protected] D#4 Z&4 J&4”

“Health problems increasing daily” is coded as “J&5 R&11 X&15 R*0”

“Wireless telephone physical group” is coded as “D&3 J#10 D*9 F&7”

**What is the code for word ‘solution’?**

1) [email protected]

2) R#1

3) R*0

4) J!17

5) None of theseAnswer –**3) R*0**

**Solution:**

**Logic:**

Number – Subtract the position of 2nd alphabet from right end with 2nd alphabet from left end.

Symbol – Symbol is coded according to number of vowels in the word:

# – 3

@ – 1

* – 4

! – 5

& – 2

Alphabet – Position of 3rd alphabet from right end. Add same number to it to get the alphabet

For example – Wireless

**Number**– Position of ‘I’ in English alphabet = 9

Position of ‘S’ in English alphabet = 19

Subtract 19 – 9 = 10

Symbol – Number of vowels in ‘wireless’ = 3

Symbol – #

Alphabet – 3rd alphabet from right end = O

Position of ‘E’ = 5

5 + 5 = 10

Alphabet – J

Hence, ‘wireless’ is coded as ‘J#10’.

Hence, the code for word ‘solution’ is ‘R*0’.**Which of the following is the code for ‘phone call’?**

1) R&5 [email protected]

2) [email protected] B!12

3) D*6 B!11

4) D&6 [email protected]

5) None of these**‘B#1’ is the code for which of the following?**

1) Spherical

2) Physical

3) Education

4) Important

5) Cannot be determinedAnswer –**4) Important**

**Solution:**

Hence, ‘B#1’ is the code for ‘important’.**What is the code for ‘delete data’?**

1) K#12 B#14

2) [email protected] B*14

3) J#15 [email protected]

4) J#15 B&19

5) None of theseAnswer –**4) J#15 B&19**

Hence, code for ‘delete data’ is ‘J#15 B&19’.**What is the code for ‘parenting’?**

1) R!12

2) R#13

3) E%12

4) R*13

5) [email protected]Answer –**2) R#13**

Hence, code for ‘parenting’ is ‘R#13’.

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