Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample in **Time and Distance **with Explanation, which is common for all the IBPS,SBI,SSC and other competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Questions Penned by Yogit

**A car after travelling 100 km from point A meets with an accident and then proceeds at 3/4 of its original speed and arrives at the point B 90 minutes late. If the car meets the accident 60 km further on, it would have reached 15 minutes sooner. Find the original speed of the train?**

a) 60km/hr

b) 80km/hr

c) 100km/hr

d) 120km/hr

e) None of theseAnswer –**b) 80km/hr**

**Explanation :**

let distance between A and B be D km and real speed of the car be S km/hr

First time car takes 90 minutes more and second time car takes 75 minutes more than scheduled time.

So, T1 – T2 = 15/60 = 100

15/60 = [100/s + (D -100)/(3s/4)] – [160/s + (D – 160)/(3s/4)]

Solve this D will be cancelled and S comes out to be 80km/hr**A boy goes to school from his home at a speed of 4 km/hr and returns at a speed of 6 km/hr. If in total he took 5 hours in going and coming back, the distance between his house and school?**

a) 8km

b) 10km

c) 12km

d) 14km

e) None of theseAnswer –**c) 12km**

**Explanation :**

5 = d/4 + d/6 (d is the distance between school and home)**A police officer is 110 meter behind a thief. The officer runs 21 meters and thief runs 14 meters in a minute. In what time the officer will catch the thief ?**

a) 15.3/7 minutes

b) 15.5/7 minutes

c) 15.1/7 minutes

d) 16.3/7 minutes

e) None of theseAnswer –**b) 15.5/7 minutes**

**Explanation :**

let the thief covers x more distance before get caught, so officer have to cover 110+x in the same time in which thief covers x distance ,

x/14 = (110 +x)/21, x = 220 so time = 330/21 = 110/7 = 15.5/7 minutes**Two trains P and Q are separated by 220 km on a straight line. One train starts at 8 am from one station A towards B at 40 km/hr and another train starts from B towards A at 9 am at 60 km/hr. At what time will both train will meet?**

a) 10:00 am

b) 10:30 am

c) 10:48 am

d) 11:00 am

e) None of theseAnswer –**c) 10:48 am**

**Explanation :**

In one hour first train will cover 40 km, so distance between them remains only 180. Now

x/40 = (180 –x)/60, we get x = 72, so time = 72/40 = 1 hour 48 minutes

so both will meet at 10:48 am**Two girls begin together to write out a book containing 900 lines. The first girl starts with the first line, writing at a speed of 150 lines per hour and the second girl starts writing from the last line at the rate of 200 lines per hour. At which line will they meet?**

a) 384^{th}line

b) 386^{th}line

c) 389^{th}line

d) 400^{th}line

e) None of theseAnswer –**b) 386**^{th}line

**Explanation :**

Solve this question as analogous to distance method,

At some x page they will meet, so

x/150 = (900 – x)/200, we get x = 385.7 = 386^{th}line (approx.)**Two women start walking towards each other at same time from two points separated by 84 km. First women walks at 5km/hr and second walks at 2 km/hr in the first hour, 2.5 km/hr in second hour, 3 km/hr in third hour and so on. Find the approximate time after which both women will meet?**

a) 8hr

b) 9hr

c) 10hr

d) 11hr

e) None of theseAnswer –**b) 9hr**

**Explanation :**

Let after T time both women meet each other, so distance travelled by first women is 5T and second women forms an AP, so

distance = (T/2)*[4 + (T -1)1/2]

so, 5T + (T/2)*[4 + (T -1)1/2] = 84, solve for T, u will get T = 9 hrs

take √2073 = 45 (approx.)**Two places are A and B are 200 kms from each other. A train leaves from A for B at the same time another train leaves B for A. The two trains meet at the end of 8 hours. If the train travelling from A to B travels 10km/hr faster than the other. Find the speed of the faster train?**

a) 15 km/hr

b) 16 km/hr

c) 17.5 km/hr

d) 18 km/hr

e) None of theseAnswer –**c) 17.5 km/hr**

**Explanation :**

speed of trains = s + 10 and s km/hr. At some P distance from A both train will meet. So,

8 = P/(s +10) = (200 – P)/s

Solve both equation, we get s = 7.5 so faster train speed 17.5 km/hr**Two bullets are fired at an interval of 15 minutes but a car approaching the place of firing hears the second bullet after 14 minutes. Speed of sound is 330 meters per second. Find the speed of the car?**

a) 80km/hr

b) 82km/hr

c) 85km/hr

d) 90km/hr

e) None of theseAnswer –**c) 85km/hr**

**Explanation :**

distance travels by sound in one minute is equal to the distance travels by car in 14 minutes i.e. 60*330 = s*14*60

s = (330/14)*(18/5) = 85km/hr (approx.)**A truck driving on a highway passed a man walking at the rate of 12km/hr in the same direction. He could see the truck for 2 minutes and up to 500 meters. Find the speed of the truck?**

a) 27km/hr

b) 30km/hr

c) 32km/hr

d) 42km/hr

e) None of theseAnswer –**a) 27km/hr**

**Explanation :**

500 = (s – 12*5/18)*2*60

s = 27km/hr**Excluding stoppages the speed of bus is 60 km/hr and including stoppages it average speed becomes 48km/hr. For how much time the bus stops.**

a) 10 min

b) 12 min

c) 14 min

d) 16 min

e) None of theseAnswer –**b) 12 min**

**Explanation :**

Due to stoppages bus covers 12 km less. To cover 12km with 60km/hr speed it takes 12min

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