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Question 1 of 15

1. Question

1 points

Category: Quantitative Aptitude

How many words can be made out of the letters of the word REVIEW such that all vowels occur together?

Correct

Explanation:
We have R V W and EIE
So 4! For these 4 letters (take EIE as single letter because they are to be taken together)
Now arrangement of EIE is 3!/2! = 3(divided by 2! Because E occurs twice)
So total 4! * 3

Incorrect

Explanation:
We have R V W and EIE
So 4! For these 4 letters (take EIE as single letter because they are to be taken together)
Now arrangement of EIE is 3!/2! = 3(divided by 2! Because E occurs twice)
So total 4! * 3

Question 2 of 15

2. Question

1 points

Category: Quantitative Aptitude

A town having population of 1,50,000 has 60% males and rest females. If 80% of males and 70% of females are literate, then what is the total number of illiterates in the town?

Correct

Explanation:
Males = (60/100)*1,50,000 = 90,000 so females = 60,000
Male illiterates = (20/100)*90,000 = 18,000
Female illiterates = (30/100)* 60,000 = 18,000
Total 18+18

Incorrect

Explanation:
Males = (60/100)*1,50,000 = 90,000 so females = 60,000
Male illiterates = (20/100)*90,000 = 18,000
Female illiterates = (30/100)* 60,000 = 18,000
Total 18+18

Question 3 of 15

3. Question

1 points

Category: Quantitative Aptitude

How many 4 digit numbers are there which contain 2 as there last digit?

Correct

Explanation:
For last digit we have only one choice i.e 2
And it is not given that 2 can be repeated or not, so we will take that it can be repeated.
So 9 choices for 1st digit (1-9) [0 cannot come at first place to make it four digit]
10 choices for 2nd digit (0-9), and also 10 choices for 3rd digit (0-9)
So total ways = 9*10*10

Incorrect

Explanation:
For last digit we have only one choice i.e 2
And it is not given that 2 can be repeated or not, so we will take that it can be repeated.
So 9 choices for 1st digit (1-9) [0 cannot come at first place to make it four digit]
10 choices for 2nd digit (0-9), and also 10 choices for 3rd digit (0-9)
So total ways = 9*10*10

Question 4 of 15

4. Question

1 points

Category: Quantitative Aptitude

√3969 – √2704 = x – √2916

Correct

Explanation:
√3969 – √2704 = x – √2916
63 – 52 = x – 54

Incorrect

Explanation:
√3969 – √2704 = x – √2916
63 – 52 = x – 54

Question 5 of 15

5. Question

1 points

Category: Quantitative Aptitude

25% of 540 + 54% of 360 = ?

Correct

Explanation:
25% of 540 + 54% of 360 = ?
540/4 + 194.4

Incorrect

Explanation:
25% of 540 + 54% of 360 = ?
540/4 + 194.4

Question 6 of 15

6. Question

1 points

Category: Quantitative Aptitude

Two solutions consists of 3 ingredients A, B, and C. Solution 1 contains A, B, and C in the ratio 1 : 2 : 3 and solution 2 contains A, B, and C in the ratio 2 : 3 : 4. Both solutions are mixed in the ratio 7 : 12. What is the percentage of B in the final solution?

Correct

Explanation:
Ratio of B to A+C in 1st solution = 2 : (1+3) = 1 : 2
Ratio of B to A+C in 2nd solution = 3 : (2+4) = 1 : 2
They are mixed in ratio 7 : 12
So ratio of B to (A+C) in final solution = 1/3 * 7 + 1/3 * 12 : 2/3 * 7 + 2/3 * 12 = 1 : 2
So, percentage of B = 1/(1+2) * 100 = 100/3 %

Incorrect

Explanation:
Ratio of B to A+C in 1st solution = 2 : (1+3) = 1 : 2
Ratio of B to A+C in 2nd solution = 3 : (2+4) = 1 : 2
They are mixed in ratio 7 : 12
So ratio of B to (A+C) in final solution = 1/3 * 7 + 1/3 * 12 : 2/3 * 7 + 2/3 * 12 = 1 : 2
So, percentage of B = 1/(1+2) * 100 = 100/3 %

Question 7 of 15

7. Question

1 points

Category: Quantitative Aptitude

If an item is sold at 2/5th of its actual selling price, the profit made is 10%. Now if the same item is sold at 40% less than the actual selling price, what will be the profit%/loss%?

Correct

Explanation:
C.P. S.P.
Profit is 10%. So,
(2/5 S.P. – C.P.)/C.P. * 100 = 20
This gives S.P. = 11/4 C.P.
Now product sold at 40% less S.P. i.e. 60/100 or 6/10 of S.P.
Profit/loss% = (6/10 S.P. – C.P.)/C.P. * 100
Put S.P. = 11/4 C.P. and find the final answer

Incorrect

Explanation:
C.P. S.P.
Profit is 10%. So,
(2/5 S.P. – C.P.)/C.P. * 100 = 20
This gives S.P. = 11/4 C.P.
Now product sold at 40% less S.P. i.e. 60/100 or 6/10 of S.P.
Profit/loss% = (6/10 S.P. – C.P.)/C.P. * 100
Put S.P. = 11/4 C.P. and find the final answer

Question 8 of 15

8. Question

1 points

Category: Quantitative Aptitude

Given the radius of sphere as 12 cm and cost of painting its surface as Rs 20 per square cm. Now if the radius of sphere and its cost both are increased by 10% and 25% respectively, then what will be the percentage increase in the total cost of painting per square cm?

Correct

Explanation:
Surface area of square is 4ᴨr^{2}
Radius increases by 15%, so by successive increase formula
surface area changes by 10+10+((10*10)/100) = 21%
Total cost of painting = Surface area of sphere * Cost
So again by successive increase formula
change in cost of painting will be = 21+25+((21*25)/100)

Incorrect

Explanation:
Surface area of square is 4ᴨr^{2}
Radius increases by 15%, so by successive increase formula
surface area changes by 10+10+((10*10)/100) = 21%
Total cost of painting = Surface area of sphere * Cost
So again by successive increase formula
change in cost of painting will be = 21+25+((21*25)/100)

Question 9 of 15

9. Question

1 points

Category: Quantitative Aptitude

25 men are employed for a work which needs to be completed in 40 days. But after 24 days, it was found that only one third of the work was completed. Now in order to complete the work 4 days earlier, how many extra men needed to be employed?

Correct

Explanation:
4 days earlier the work is to be completed, this means in (40-4) = 36 days
After 24 days, the meaning work is to be completed in (36-24) = 12 days
Remaining work = 1 – 1/3 = 2/3
Let x extra men are to be employed. So,
25 * 24 * 2/3 = (x+25) * 12 * 1/3
Solve, x = 75

Incorrect

Explanation:
4 days earlier the work is to be completed, this means in (40-4) = 36 days
After 24 days, the meaning work is to be completed in (36-24) = 12 days
Remaining work = 1 – 1/3 = 2/3
Let x extra men are to be employed. So,
25 * 24 * 2/3 = (x+25) * 12 * 1/3
Solve, x = 75

Question 10 of 15

10. Question

1 points

Category: Quantitative Aptitude

50 articles were bought at the marked price of 45 articles. If the articles are now sold by giving 1% discount, what is the profit percent made?

Correct

Explanation:
Let MP of 1 article = Re 1
CP of 50 articles = MP of 45 articles = Rs 45
MP of 50 articles = Rs 50
So after discount of 1%, SP of 50 articles = 99/100 * 50 = Rs 49.5
So profit% = (49.5 – 45)/45 * 100

Incorrect

Explanation:
Let MP of 1 article = Re 1
CP of 50 articles = MP of 45 articles = Rs 45
MP of 50 articles = Rs 50
So after discount of 1%, SP of 50 articles = 99/100 * 50 = Rs 49.5
So profit% = (49.5 – 45)/45 * 100

Question 11 of 15

11. Question

1 points

Category: Quantitative Aptitude

There are 2 pipes A and B such that A fills the cistern in 4 hrs and B empties the cistern in 2 hrs. First the pipe A was opened and after 1 hour B was also opened. In how much total time will the cistern get empty?

Correct

Explanation:
After 1 hr, cistern filled by A + B is 1/4 -1/2 = -1/4
This means after 1/4th of cistern filled in 1 hr, in next 1 hr, 1/4 gets empty

So 1 + 1

Incorrect

Explanation:
After 1 hr, cistern filled by A + B is 1/4 -1/2 = -1/4
This means after 1/4th of cistern filled in 1 hr, in next 1 hr, 1/4 gets empty

So 1 + 1

Question 12 of 15

12. Question

1 points

Category: Quantitative Aptitude

20 men can complete a work in 56 days. 10 men started the work and after working for 20 days it was realized that the work will not get completed on time. After this how many persons are needed to be employed to complete the work in 20 more days?

Average age of 4 persons in a group is 25 years. One of then left the group and in his place a man aged at 31 came due to which the average age increased by 1. What is the age of the person who left the group?

Correct

Explanation:
(a+b+c+d)/4 = 25, so a+b+c+d = 100
Let d left the group and e aged 31 came so (a+b+c+e)/4 = 26 and a+b+c+31 = 104
Solve, and find d’s age.

Incorrect

Explanation:
(a+b+c+d)/4 = 25, so a+b+c+d = 100
Let d left the group and e aged 31 came so (a+b+c+e)/4 = 26 and a+b+c+31 = 104
Solve, and find d’s age.

Question 14 of 15

14. Question

1 points

Category: Quantitative Aptitude

The incomes of 2 persons A and B is in the ratio 3 : 4. Their expenditures are in the ratio 4 : 7 respectively. If both save Rs 20,000, then what is A’s income?

Correct

Explanation:
Incomes 3x and 4x
Expenditures 4y and 7y
So 3x – 4y = 20000
And 4x – 7y = 20000
Solve both equations, x = 12,000
So A’s income = 3*12000

Incorrect

Explanation:
Incomes 3x and 4x
Expenditures 4y and 7y
So 3x – 4y = 20000
And 4x – 7y = 20000
Solve both equations, x = 12,000
So A’s income = 3*12000

Question 15 of 15

15. Question

1 points

Category: Quantitative Aptitude

A can contains 120 litres solution of water and salt in which there is 70% of salt. The solution is now evaporated to take out salt. If after some time it was found that the salt is now 80% in the solution, then what was the amount of water evaporated up to that time?

Correct

Explanation:
In 120 litres solution, salt = 70/100 * 120 = 84 l, so water = 36 l
Suppose x litres of water evaporated.
So now the solution becomes (120-x) litres and water becomes (36-x) litres.
In this (120-x) litres, 20% is water.
So 20/100 (120-x) = 36-x
Solve, x = 15

Incorrect

Explanation:
In 120 litres solution, salt = 70/100 * 120 = 84 l, so water = 36 l
Suppose x litres of water evaporated.
So now the solution becomes (120-x) litres and water becomes (36-x) litres.
In this (120-x) litres, 20% is water.
So 20/100 (120-x) = 36-x
Solve, x = 15