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A person sold 2 articles in 60000 each, on which he gained 20% profit and 20% loss. Find the difference of cost prices.

Correct

Answer – 1. 25000
Explanation:
CP of the article(20% Profit)= 60000 * 100/120 = 50000
CP of the article(20% loss)= 60000 * 100/80 = 75000
Difference = 75000 – 50000 = 25000

Incorrect

Answer – 1. 25000
Explanation:
CP of the article(20% Profit)= 60000 * 100/120 = 50000
CP of the article(20% loss)= 60000 * 100/80 = 75000
Difference = 75000 – 50000 = 25000

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

If 2 is added to the numerator and 3 is added to the denominator, then the ratio become 1/3. Also, the difference between the denominator and the numerator is 17. If the denominator is greater than the numerator then find the fraction.

Correct

Answer – 1. 7/24
Explanation:
X + 2 / Y + 3 = ⅓ —(1)
Y – X = 17 —(2)
From (1) and (2)
X = 7, Y =24

Incorrect

Answer – 1. 7/24
Explanation:
X + 2 / Y + 3 = ⅓ —(1)
Y – X = 17 —(2)
From (1) and (2)
X = 7, Y =24

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

The ratio of upstream speed and the speed of the boat in still water is 5:6. The speed of the boat is 30 km/h. Find the speed of the stream.

Correct

Answer – 5. 5 kmph
Explanation:
Upstream speed = 25 kmph
Boat in still water = 30 kmph
Downstream Speed = 30 * 2 – 25 = 35 kmph
Speed of stream = ½(35-25) = 5 kmph

Incorrect

Answer – 5. 5 kmph
Explanation:
Upstream speed = 25 kmph
Boat in still water = 30 kmph
Downstream Speed = 30 * 2 – 25 = 35 kmph
Speed of stream = ½(35-25) = 5 kmph

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The difference between the present ages of Arun and Kiran is 9 years. After 7 years, Kiran’s age is twice of Arun’s age. What will be Kiran’s age after 4 years?

Correct

Answer – 1. 15
Explanation:
Let the present ages of Kiran and Arun be K & A
K – A = 9 years ………..(1)
After 7 years, K + 7 = 2(A + 7)
K + 7 = 2A + 14
K – 2A = 7 …………(2)
From (1) & (2),
=> A = 2 years
=> K = 9 + 2 = 11 years
Required, age of Kiran after 4 years = 11 + 4 = 15 years.

Incorrect

Answer – 1. 15
Explanation:
Let the present ages of Kiran and Arun be K & A
K – A = 9 years ………..(1)
After 7 years, K + 7 = 2(A + 7)
K + 7 = 2A + 14
K – 2A = 7 …………(2)
From (1) & (2),
=> A = 2 years
=> K = 9 + 2 = 11 years
Required, age of Kiran after 4 years = 11 + 4 = 15 years.

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Two persons Kishore and Lalit enter into a business by investing their sum in the ratio of 7 : 9. After 7 months, Lalit leaves the business. After eleven month, if total profit is Rs. 2460, what is the profit share of Lalit (in Rs)?

Correct

Answer – 2. Rs. 1107

Incorrect

Answer – 2. Rs. 1107

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Manoj spends 23% of an amount of money on LIC policy, 33% on accommodation, 19% on children’s education and 16% on recreation. He deposits the remaining amount of Rs. 504 in bank. How much amount does he spend on accommodation and LIC policy together?

Correct

Answer – 4. Rs. 3136
Explanation:
Let total amount = Rs. x
Total expenditure = (23 + 33 + 19 + 16)% of x = 91%of x
Remaining money = (100 – 91)% of x = 9% of x
But given in the question that,
9% of x = 504
9x/100 = 504
=> x = 50400/9
=> x = Rs. 5600
Required money spent on accommodation & LIC = 23 + 33 %
= 56% of 5600
= 56 x 5600/100 = 56 x 56 = Rs. 3136

Incorrect

Answer – 4. Rs. 3136
Explanation:
Let total amount = Rs. x
Total expenditure = (23 + 33 + 19 + 16)% of x = 91%of x
Remaining money = (100 – 91)% of x = 9% of x
But given in the question that,
9% of x = 504
9x/100 = 504
=> x = 50400/9
=> x = Rs. 5600
Required money spent on accommodation & LIC = 23 + 33 %
= 56% of 5600
= 56 x 5600/100 = 56 x 56 = Rs. 3136

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Ajay works twice as fast as Bharat. If Bharat can complete a work in 18 days independently, the number of days in which Ajay and Bharat can together finish the work is:

Correct

Answer – 2. 6 days
Explanation:
Ratio of rates of working of Ajay and Bharat =2:1. So, ratio of times taken =1:2
Therefore, Ajay’s 1 day’s work=1/9
Bharat’s 1 day’s work=1/18
(Ajay+Bharat)’s 1 day’s work= 1/9 + 1/18 = 1/6
so, Ajay and Bharat together can finish the work in 6 days

Incorrect

Answer – 2. 6 days
Explanation:
Ratio of rates of working of Ajay and Bharat =2:1. So, ratio of times taken =1:2
Therefore, Ajay’s 1 day’s work=1/9
Bharat’s 1 day’s work=1/18
(Ajay+Bharat)’s 1 day’s work= 1/9 + 1/18 = 1/6
so, Ajay and Bharat together can finish the work in 6 days

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

A, B, C, D, E and F are six consecutive odd numbers and their average is 52. What is the product of C and F?

Correct

Answer – 4. 2907
Explanation:
Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers.
Given that their average is 52
Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6
6x + 30 = 312
x = 47
So Product = 51 × 57 = 2907

Incorrect

Answer – 4. 2907
Explanation:
Let x, x+2, x+4, x+6, x+8 and x+10 are six consecutive odd numbers.
Given that their average is 52
Then, x + x+2 + x+4 + x+6 + x+8 + x+10 = 52×6
6x + 30 = 312
x = 47
So Product = 51 × 57 = 2907

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

A Car and a truck travels from same point to Q to P. Total time taken is 6 hours 30 minutes. Speed of the car is 80 kmph. Distance between P to Q is 200 km. Find the speed of truck.

Correct

Answer – 4. 50 kmph
Explanation:
Total time taken = 13/2 hours
Time taken by car = 200/80 = 5/2 hours
Time taken by truck = 4 hours
Speed of truck = 200/4 = 50 kmph

Incorrect

Answer – 4. 50 kmph
Explanation:
Total time taken = 13/2 hours
Time taken by car = 200/80 = 5/2 hours
Time taken by truck = 4 hours
Speed of truck = 200/4 = 50 kmph

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