# IBPS Clerk Main: Reasoning Day 1

Hello Aspirants,

Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Reasoning section, type of which will be asked in IBPS Clerk Main Exam.

Stratus – IBPS Clerk Course 2015

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Directions (1 – 5): Answer the questions on the basis of the information given below.
A number arrangement machine when given an input of numbers, rearranges them following a particular rule in each step. The following is an illustration of input and steps of rearrangement.
Input: cat all vat ultra rat over hat eager
Step I: ultra cat all vat rat over hat eager
Step II: ultra over cat all vat rat hat eager
Step III: ultra over eager cat all vat rat hat
Step IV: ultra over eager all cat vat rat hat
Step V: ultra over eager all cat hat vat rat
Step VI: ultra over eager all cat hat rat vat
This is the final arrangement and step VI is the last step for this input.

1. Which step is the last step of the given input?
Input : as bat ink wind east dust open king

A) VIII
B) VII
C) IV
D) V
E) VI
D) V
Explanation:

See the last step, first the words starting with vowels are placed, then starting with consonants
Input: as bat ink wind east dust open king
Step I: open as bat ink wind east dust king
Step II: open ink as bat wind east dust king
Step III: open ink east as bat wind dust king
Step IV: open ink east as bat dust wind king
Step V: open ink east as bat dust king wind

2. In 1st question, in step IV, what is the position of ‘bat’ from the right end?
A) 2nd
B) 3rd
C) 4th
D) 5th
E) 6th
C) 4th
Explanation:

Step IV: open ink east as bat dust wind king

3. Step 2 of an input is ‘under over cone ask visk rest east husk ’, what will be definitely be the step 1?
A) under cone over ask visk rest east husk
B) under cone ask over visk rest east husk
C) under cone ask visk rest east over husk
D) under cone ask visk rest east husk over
E) Cannot be determined
E) Cannot be determined
Explanation:

The previous step cannot be determined.

4. What should be the last step of the following input?
Input: more fan inch each purse oat joker utility

A) utility oat inch each fan joker more purse
B) utility oat inch each fan more purse joker
C) utility oat inch purse each joker more fan
D) utility oat inch each joker fan more purse
E) None of these
A) utility oat inch each fan joker more purse
Explanation:

For this there is no need to write all steps
Last step is ‘utility oat inch each fan joker more purse’
1st all vowels, and then consonants

5. In above question, what is the fourth step?
A) utility oat inch each more purse joker fan
B) utility oat inch each fan more purse joker
C) utility oat inch more fan each purse joker
D) utility oat inch each more fan purse joker
E) None of these
D) utility oat inch each more fan purse joker
Explanation:

Input: more fan inch each purse oat joker utility
Step I: utility more fan inch each purse oat joker
Step II: utility oat more fan inch each purse joker
Step III: utility oat inch more fan each purse joker
Step IV: utility oat inch each more fan purse joker

Directions (6-10): In all the questions that follow, relationship between different elements is shown in the statements. The statements are followed by two conclusions. Give answer accordingly.
(A) only 1st follows
(B) only 2nd follows
(C) either 1st or 2nd
(D) neither 1st nor 2nd
(E) both 1st and 2nd

1. Statements: P > A ≤ L, M ≤ A, I ≤ B = M
Conclusions:
I. L ≥ I
II. L = I
(A) only 1st follows
Explanation:

L ≥ A ≥ M ≥ I
So L ≥ I

2. Statements: B < W ≤ E, L > E < K, W ≥ M
Conclusions:
I. K > W
II. L > M
(E) both 1st and 2nd
Explanation:

K > E ≥ W , so K > W
L > E ≥ W ≥ M so L > M

3. Statements: K > M ≥ Z, P = M, Q > K
Conclusions:
I. Q > P
II. Z < Q
(E) both 1st and 2nd
Explanation:

Q > K > M = P, so Q > P
Z < K < Q, so Z < Q

4. Statements: Q ≥ E > K, E > F < A, P > Q
Conclusions:
I. P > A
II. Q > F
(B) only 2nd follows
Explanation:

P > Q ≥ E > F < A, so relation cant be determined between P and A Q ≥ E > F, so Q > F

5. Statements: Q ≥ S ≥ J, J < P, P > E
Conclusions:
I. E > S
II. S ≥ E
(C) either 1st or 2nd
Explanation:

E < P > J ≤ S, so relation cant be determined between E and S, so either E is greater than S or is less than and equal to S

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