IBPS Clerk Main: Quants Day 9

Hello Aspirants,

Welcome to Online Quant Section in AffairsCloud.com. We are starting IBPS Clerk course 2015 and we are creating sample questions in Quantitative Aptitude section, type of which will be asked in IBPS Clerk Main Exam.

Stratus – IBPS Clerk Course 2015 

• IBPS Clerk Daily Test Questions
• IBPS Clerk Practice Test Questions

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1. A cube of side 8 feet is to be painted from outside. The cost of paint is Rs 36.50 per kg. If 16 square feet are covered by 1 kg, then what is the cost of painting the cube?
   A) Rs 832
   B) Rs 876
   C) Rs 782
   D) Rs 924
   E) Rs 856
   
   Answer & Explanation

   B) Rs 876
   Explanation:
   Surface area of cube = 6a² = 6*8² = 384 sq. feet
   So quantity of paint required = (384/16) = 24 kg
   So cost of painting = 36.50*24
   
   
2. The students of section A and section B have average weights of 30 kg and 45 kg respectively. Find the average weight of both the sections together such that the number of students in the sections A and B is in the ratio 9 : 1.
   A) 34.5 kg
   B) 36 kg
   C) 33 kg
   D) 31.5 kg
   E) 32 kg
   
   Answer & Explanation

   D) 31.5 kg
   Explanation:
   Students in A section = 9x, students in B section = x
   So total weight of students of A section = 30*9x = 270x
   And total weight of students of B section = 45*x = 45x
   So average weight of both sections = [(270x+45x)/(9x+x)]
   
   
3. There are 3 machines A, B and C which produce paper sheets. The ratio of the rates of A, B, and C is 3 : 4 : 5. They all produced 400 sheets in which A worked for 6 days, B for 8 days and C worked for 10 days. How many sheets would have been produced if A’s rate get doubled and B’s rate get tripled?
   A) 750
   B) 728
   C) 590
   D) 630
   E) 910
   
   Answer & Explanation

   B) 728
   Explanation:
   Let their rates be 3x, 4x, 5x resp.
   Then 3x*6 + 4x*8 + 5x*10 = 400
   Solve, x = 4
   Then if A’s rate get doubled and B’s rate get tripled:
   A’s becomes 3x*2 = 6x, B’s become = 4x*3 = 12x
   So they will produce now – 6x*6 + 12x*8 + 5x*10 = 182x = 182*4
   
   
   
4. The average of the ages of a man and his only son exceeds the average of the ages of his wife and his son by 25%. The age of his son is 30 years less than the age of his wife whose age is 10 years less than his age. Find the age of his son.
   A) 5
   B) 10
   C) 15
   D) 20
   E) 25
   
   Answer & Explanation

   A) 5
   Explanation:
   Man, son and wife
   [(M+S)/2] = (125/100)* [(W+S)/2]
   Also S = W – 30 and W = M – 10
   Solve the three equations to find S
   
   
5. P varies directly with the square of Q when R is a constant and inversely with R when Q is constant. When Q = 12 and R = 8, then P = 36. Find P when Q = 24 and R = 16.
   A) 96
   B) 68
   C) 48
   D) 72
   E) 86
   
   Answer & Explanation

   D) 72
   Explanation:
   Let k be constant of proportionality,
   If P directly varies with Q², then P = k Q²
   And if P inversely varies with R, then P = k/R
   So in all P = k*Q²/R
   When Q = 12 and R = 8, then P = 36
   So 36 = k*12²/8
   Solve, k = 2
   Now when Q = 24 and R = 16,
   P = 2*24²/16
   
   
6. x² – 5x + 6 = 0, 2y² – 25y + 63 = 0
   A) x > y
   B) x < y
   C) x ≥ y
   D) x ≤ y
   E) x = y or relationship cannot be determined
   
   Answer & Explanation

   B) x < y
   Explanation:
   x² – 5x + 6 = 0
   Gives x = 2, 3
   2y² – 25y + 63 = 0
   2y² – 18y – 7y + 63 = 0
   Gives y = 7/2, 9
   Put on number line
   2       3        7/2         9
   
   
7. 2x² + 3x – 14 = 0, 3y² – 10y – 25 = 0
   A) x > y
   B) x < y
   C) x ≥ y
   D) x ≤ y
   E) x = y or relationship cannot be determined
   
   Answer & Explanation

   E) x = y or relationship cannot be determined
   Explanation:
   2x² + 3x – 14 = 0
   2x² + 4x – 7x – 14 = 0
   Gives x = -7/2, 2
   3y² – 10y – 25 = 0
   3y² – 15y + 5y – 25 = 0
   Gives y = -5/3, 5
   Put on number line
   -7/2          -5/3          2             5
   
   
8. 2x² – x – 3 = 0, 3y² + 8y + 5 = 0
   A) x > y
   B) x < y
   C) x ≥ y
   D) x ≤ y
   E) x = y or relationship cannot be determined
   
   Answer & Explanation

   C) x ≥ y
   Explanation:
   2x² – x – 3 = 0
   2x² + 2x – 3x – 3 = 0
   Gives, x = -1, 3/2
   3y² + 8y + 5 = 0
   3y² + 3y + 5y + 5 = 0
   Gives y = -1, -5/3
   Put on number line
   -5/3         -1         3/2
   
   
9. 3x² + 10x – 8 = 0, 6y² – 13y + 6 = 0
   A) x > y
   B) x < y
   C) x ≥ y
   D) x ≤ y
   E) x = y or relationship cannot be determined
   
   Answer & Explanation

   D) x ≤ y
   Explanation:
   3x² + 10x – 8 = 0
   3x² + 12x – 2x – 8 = 0
   Gives, x = -4, 2/3
   6y² – 13y + 6 = 0
   6y² – 9y – 4y + 6 = 0
   Gives, y = 2/3, 3/2
   Put on number line
   -4     2/3       3/2
   
   
10. 4x² + 17x – 15 = 0, 3y² + 17y + 10 = 0
    A) x > y
    B) x < y
    C) x ≥ y
    D) x ≤ y
    E) x = y or relationship cannot be determined
    
    Answer & Explanation

    E) x = y or relationship cannot be determined
    Explanation:
    4x² + 17x – 15 = 0
    4x² + 20x – 3x – 15 = 0
    Gives, x = -5, 3/4
    3y² + 17y + 10 = 0
    3y² + 15y + 2y + 10 = 0
    Gives, y = -5, -2/3
    Put on number line
    -5      -2/3         3/4