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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeA basket contains 2 Red marbles, 5 Pink marbles and ‘A’ Blue marbles. One marble is drawn at random and the probability of the Pink marble is 5/9. What is the value of ‘A”
Correct
Answer – 2) 2
Explanation:
Red = 2 , Pink = 5, Blue = A
Possible outcome 5C1=5
Total outcome = 9C1=9
So 2+5+A=9
A=2Incorrect
Answer – 2) 2
Explanation:
Red = 2 , Pink = 5, Blue = A
Possible outcome 5C1=5
Total outcome = 9C1=9
So 2+5+A=9
A=2 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeRam invests a certain sum in Pearl Scheme offering SI at 5% pa for 4 years. He further invests the amount obtained from Pearl Scheme into Gold Scheme offering CI at 10 pa (compounded annually) for 2 years. If the interest obtained from Gold Scheme was Rs 378, then what was the sum invested in Pearl Scheme?
Correct
Answer – 4) 1500
Explanation:
Let the principal for Pearl Scheme be P
Then SI = (P*5*4)/100 = P/5
Amount = P + P/5 = 6P/5
Now CI @10 % for 2 years on 6P/5 is 378
CI =21 % of 6P/5= 378
P = (378 x5x100)/(21 x6)=Rs 1500Incorrect
Answer – 4) 1500
Explanation:
Let the principal for Pearl Scheme be P
Then SI = (P*5*4)/100 = P/5
Amount = P + P/5 = 6P/5
Now CI @10 % for 2 years on 6P/5 is 378
CI =21 % of 6P/5= 378
P = (378 x5x100)/(21 x6)=Rs 1500 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA running track of a toy train is in the form of circle whose inner circumference is 396 m and the outer circumference is 528 m. Find the width of the track .
Correct
Answer – 1) 21m
Explanation:
Inner circumference of the track =396 m
2πr = 396
r = 63
Outer circumference of the track =528 m
2πR = 528
R = 84 m
Width of the track = 8463= 21 mIncorrect
Answer – 1) 21m
Explanation:
Inner circumference of the track =396 m
2πr = 396
r = 63
Outer circumference of the track =528 m
2πR = 528
R = 84 m
Width of the track = 8463= 21 m 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA watercraft, whose speed is 16 kmph in still water, goes 63 km downstream and comes back in 8 hours. In what time does the motor cover the distance of 70 km upstream?
Correct
Answer – 1) 5 hours
Explanation:
Let the speed of the current – X kmph
63/(16+X) + 63/(16X)=8
X = 2 kmph.
Required time = 70/(162) = 5 hoursIncorrect
Answer – 1) 5 hours
Explanation:
Let the speed of the current – X kmph
63/(16+X) + 63/(16X)=8
X = 2 kmph.
Required time = 70/(162) = 5 hours 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe ratio of present age of Arun to Balu is 9:10. Eight years ago the ratio of 1/7 of Arun’s age at that time to ¼ of Balu’s age at that time was 1:2. Eight years hence what will be the ratio of Arun’s age to Balu’s age?
Correct
Answer – 2) 11:12
Explanation:
[1/7 (9x8)]/[1/4(10x8)]=1/2
x=4
Hence Arun’s age = 9×4=36
So Arun’s age 8 years hence = 36+8 = 44
Balu’s age 8 years hence = 10 x4+8 = 48
Required ratio = 44/48 = 11:12Incorrect
Answer – 2) 11:12
Explanation:
[1/7 (9x8)]/[1/4(10x8)]=1/2
x=4
Hence Arun’s age = 9×4=36
So Arun’s age 8 years hence = 36+8 = 44
Balu’s age 8 years hence = 10 x4+8 = 48
Required ratio = 44/48 = 11:12 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe ten’s digit of a three digit number X is 3. If the digits of X are interchanged and the number thus formed as 396 more than the previous one. The sum of unit digit and hundred digit is 14, then what is the twice of that number?
Correct
Answer – 5) 1078
Explanation:
Unit digit’s = X
Hundred’s digit =14X
Original number
=(14X) * 100 +3 *10 +X=143099X
New number after interchanging the digits
=100 X +3 *10 +14X=99X+44
99X +441430+99X=396
X=9
Hundred’s digit = 149 = 5
Required number = 539
Twice of that number = 1078Incorrect
Answer – 5) 1078
Explanation:
Unit digit’s = X
Hundred’s digit =14X
Original number
=(14X) * 100 +3 *10 +X=143099X
New number after interchanging the digits
=100 X +3 *10 +14X=99X+44
99X +441430+99X=396
X=9
Hundred’s digit = 149 = 5
Required number = 539
Twice of that number = 1078 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudePopulation of a city increased by 5% from 2016 to 2017 and by 25% from 2017 to 2018. If the population of the city was 480 in 2016, what was its population in 2018 ?
Correct
Answer – 3) 630
Explanation:
X=480 * 105/100 * 125/100
X=630Incorrect
Answer – 3) 630
Explanation:
X=480 * 105/100 * 125/100
X=630 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeRavi has 20% investment from his monthly salary. If expenditure on grocery is 25% of overall expenditure and his total expenditure except grocery is Rs 3600 then find his monthly investment?
Correct
Answer – 4) 1200
Explanation:
Monthly salary =Rs X
investment =20X/100= Rs X/5
Remaining salary = Rs (XX/5)=Rs 4X/5
(4X/5 * 75/100)=3600
3X/5=3600
So X/5=3600/3= Rs 1200= investmentIncorrect
Answer – 4) 1200
Explanation:
Monthly salary =Rs X
investment =20X/100= Rs X/5
Remaining salary = Rs (XX/5)=Rs 4X/5
(4X/5 * 75/100)=3600
3X/5=3600
So X/5=3600/3= Rs 1200= investment 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA man rows to place 80 km away and back in 20 hours. He finds that he can row 8 km downstream in the same time as 4 km upstream. The speed of the boat in still water is
Correct
Answer – 5) 9 kmph
Explanation:
The downstream speed = 8/X kmph
The upstream speed = 4/X kmph
80/(8/X) + 80/(4/X)=20
X=2/3
Speed downstream = 8/(2/3) = 12kmph
Speed upstream =4/(2/3) = 6 kmph
Speed of boat in still water =(12+6)/2= 9 kmphIncorrect
Answer – 5) 9 kmph
Explanation:
The downstream speed = 8/X kmph
The upstream speed = 4/X kmph
80/(8/X) + 80/(4/X)=20
X=2/3
Speed downstream = 8/(2/3) = 12kmph
Speed upstream =4/(2/3) = 6 kmph
Speed of boat in still water =(12+6)/2= 9 kmph 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeSuresh marks a watch 40% above cost price and gives 25% discount to customer. If Suresh pays Rs 840 for the watch, what is the cost price?
Correct
Answer – 1) 800
Explanation:
Profit % = 4025 – (40*25)/100 = 5%
840 *100=CP(100+5)
X=800Incorrect
Answer – 1) 800
Explanation:
Profit % = 4025 – (40*25)/100 = 5%
840 *100=CP(100+5)
X=800
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