# IBPS Clerk 2018 Prelims: Quants Test Day 10

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions:(Q.1-5) Read the given data and answer the following question.**Each student in the universities either participates in any one of the sports or don’t participate in any sports.

**What is the sum of the number of students, who participate in Hockey from University P & Q to the number of students who participate in Cricket from the same Universities.?**CorrectAnswer –

**5) 300**

Explanation:

University P:

10x = 120

X = 12; Cricket – 7x, Hockey – 3x

University Q:

9x = 180

X = 20; Cricket – 4x, Hockey – 5x

Number students, who participate in Hockey from University P & Q = 36 + 100 = 136

Number students, who participate in Cricket from University P & Q = 84 + 80 = 164

Difference = 164 + 136 = 300IncorrectAnswer –

**5) 300**

Explanation:

University P:

10x = 120

X = 12; Cricket – 7x, Hockey – 3x

University Q:

9x = 180

X = 20; Cricket – 4x, Hockey – 5x

Number students, who participate in Hockey from University P & Q = 36 + 100 = 136

Number students, who participate in Cricket from University P & Q = 84 + 80 = 164

Difference = 164 + 136 = 300 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions:(Q.1-5) Read the given data and answer the following question.**Each student in the universities either participates in any one of the sports or don’t participate in any sports.

**Number of students who participate in Hockey match from University R is what percentage of total number of students of University T.**CorrectAnswer –

**1) 20%**

Explanation:

Students participated in match from University R = 330 – 225 = 105

7x = 105; x = 15

Hockey match from University R = 4x = 60

Number of students of University T = 300

% = (60/300) * 100 = 20%IncorrectAnswer –

**1) 20%**

Explanation:

Students participated in match from University R = 330 – 225 = 105

7x = 105; x = 15

Hockey match from University R = 4x = 60

Number of students of University T = 300

% = (60/300) * 100 = 20% - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions:(Q.1-5) Read the given data and answer the following question.**Each student in the universities either participates in any one of the sports or don’t participate in any sports.

**The total number of students who participated in Hockey match from University U is 4/9th those who participated in Cricket from University R. What is the number of students participated in Hockey from University U?**CorrectAnswer –

**4) 20**

Explanation:

Students participated in match from University R = 330 – 225 = 105

7x = 105; x = 15

Cricket from University R = 3x = 45

Total number of students who participated in Hockey match from University U

= 4/9 * (Cricket from University R)

= 4/9 * 45 = 20IncorrectAnswer –

**4) 20**

Explanation:

Students participated in match from University R = 330 – 225 = 105

7x = 105; x = 15

Cricket from University R = 3x = 45

Total number of students who participated in Hockey match from University U

= 4/9 * (Cricket from University R)

= 4/9 * 45 = 20 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**Directions:(Q.1-5) Read the given data and answer the following question.**

**What is the approximate average of total number students who participated in Hockey from all the Universities?**CorrectAnswer –

**3. 69**

Explanation:

Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347

347/5 = 69IncorrectAnswer –

**3. 69**

Explanation:

Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347

347/5 = 69 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**Directions:(Q.1-5) Read the given data and answer the following question.**

**What is the sum of total number of students who participated in Cricket from all Universities to the total number of students who participated in Hockey from all Universities?**CorrectAnswer –

**2) 650**

Explanation:

Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347

Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303

Difference = 347 + 303 = 650IncorrectAnswer –

**2) 650**

Explanation:

Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347

Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303

Difference = 347 + 303 = 650 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.**Total Number of Students = 600

**Total number of students who are selected from course A and E together is how much greater than the total number of students who are selected from course B and F together?**CorrectAnswer –

**2) 36**

Explanation:

course A and E = 18 + 15 = 33%

course B and F = 12 + 15 = 27%

6% of 600 = 36IncorrectAnswer –

**2) 36**

Explanation:

course A and E = 18 + 15 = 33%

course B and F = 12 + 15 = 27%

6% of 600 = 36 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.**Total Number of Students = 600

**If the total number of students is increased by 30% in June 2018 as compared to May 2018 then the total number of students will participate in June 2018 is**CorrectAnswer –

**5) 780**

Explanation:

130/100 * 600 = 780IncorrectAnswer –

**5) 780**

Explanation:

130/100 * 600 = 780 - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.**Total Number of Students = 600

**Find the central angle of total number of students who are selected from course D?**CorrectAnswer –

**1) 79.2°**

Explanation:

Central angle = 22/100 * 360 = 79.2°IncorrectAnswer –

**1) 79.2°**

Explanation:

Central angle = 22/100 * 360 = 79.2° - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative AptitudeTotal Number of Students = 600

**Find the average number of students who are selected from course A, B, C and D together?**CorrectAnswer –

**2) 105**

Explanation:

(70/4*100) * 600 = 105IncorrectAnswer –

**2) 105**

Explanation:

(70/4*100) * 600 = 105 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative AptitudeTotal Number of Students = 600

**Find the ratio between the total number of students who are selected from course B and D together to the total number of students who are selected from course A and C together?**CorrectAnswer –

**2) 17 : 18**

Explanation:

Ratio = 34 : 36 => 17:18IncorrectAnswer –

**2) 17 : 18**

Explanation:

Ratio = 34 : 36 => 17:18

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