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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.

Each student in the universities either participates in any one of the sports or don’t participate in any sports.

What is the sum of the number of students, who participate in Hockey from University P & Q to the number of students who participate in Cricket from the same Universities.?

Correct

Answer – 5) 300
Explanation:
University P:
10x = 120
X = 12; Cricket – 7x, Hockey – 3x
University Q:
9x = 180
X = 20; Cricket – 4x, Hockey – 5x
Number students, who participate in Hockey from University P & Q = 36 + 100 = 136
Number students, who participate in Cricket from University P & Q = 84 + 80 = 164
Difference = 164 + 136 = 300

Incorrect

Answer – 5) 300
Explanation:
University P:
10x = 120
X = 12; Cricket – 7x, Hockey – 3x
University Q:
9x = 180
X = 20; Cricket – 4x, Hockey – 5x
Number students, who participate in Hockey from University P & Q = 36 + 100 = 136
Number students, who participate in Cricket from University P & Q = 84 + 80 = 164
Difference = 164 + 136 = 300

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.

Each student in the universities either participates in any one of the sports or don’t participate in any sports.

Number of students who participate in Hockey match from University R is what percentage of total number of students of University T.

Correct

Answer – 1) 20%
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Hockey match from University R = 4x = 60
Number of students of University T = 300
% = (60/300) * 100 = 20%

Incorrect

Answer – 1) 20%
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Hockey match from University R = 4x = 60
Number of students of University T = 300
% = (60/300) * 100 = 20%

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.

Each student in the universities either participates in any one of the sports or don’t participate in any sports.

The total number of students who participated in Hockey match from University U is 4/9th those who participated in Cricket from University R. What is the number of students participated in Hockey from University U?

Correct

Answer – 4) 20
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Cricket from University R = 3x = 45
Total number of students who participated in Hockey match from University U
= 4/9 * (Cricket from University R)
= 4/9 * 45 = 20

Incorrect

Answer – 4) 20
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Cricket from University R = 3x = 45
Total number of students who participated in Hockey match from University U
= 4/9 * (Cricket from University R)
= 4/9 * 45 = 20

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.

Each student in the universities either participates in any one of the sports or don’t participate in any sports.

What is the approximate average of total number students who participated in Hockey from all the Universities?

Correct

Answer – 3. 69
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
347/5 = 69

Incorrect

Answer – 3. 69
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
347/5 = 69

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.

Each student in the universities either participates in any one of the sports or don’t participate in any sports.

What is the sum of total number of students who participated in Cricket from all Universities to the total number of students who participated in Hockey from all Universities?

Correct

Answer – 2) 650
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 + 303 = 650

Incorrect

Answer – 2) 650
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 + 303 = 650

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.

Total Number of Students = 600

Total number of students who are selected from course A and E together is how much greater than the total number of students who are selected from course B and F together?

Correct

Answer – 2) 36
Explanation:
course A and E = 18 + 15 = 33%
course B and F = 12 + 15 = 27%
6% of 600 = 36

Incorrect

Answer – 2) 36
Explanation:
course A and E = 18 + 15 = 33%
course B and F = 12 + 15 = 27%
6% of 600 = 36

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.

Total Number of Students = 600

If the total number of students is increased by 30% in June 2018 as compared to May 2018 then the total number of students will participate in June 2018 is

Correct

Answer – 5) 780
Explanation:
130/100 * 600 = 780

Incorrect

Answer – 5) 780
Explanation:
130/100 * 600 = 780

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.

Total Number of Students = 600

Find the central angle of total number of students who are selected from course D?

Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.

Total Number of Students = 600

Find the average number of students who are selected from course A, B, C and D together?

Directions Q.(6-10): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.

Total Number of Students = 600

Find the ratio between the total number of students who are selected from course B and D together to the total number of students who are selected from course A and C together?