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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
Each student in the universities either participates in any one of the sports or don’t participate in any sports.
What is the sum of the number of students, who participate in Hockey from University P & Q to the number of students who participate in Cricket from the same Universities.?
Correct
Answer – 5) 300
Explanation:
University P:
10x = 120
X = 12; Cricket – 7x, Hockey – 3x
University Q:
9x = 180
X = 20; Cricket – 4x, Hockey – 5x
Number students, who participate in Hockey from University P & Q = 36 + 100 = 136
Number students, who participate in Cricket from University P & Q = 84 + 80 = 164
Difference = 164 + 136 = 300Incorrect
Answer – 5) 300
Explanation:
University P:
10x = 120
X = 12; Cricket – 7x, Hockey – 3x
University Q:
9x = 180
X = 20; Cricket – 4x, Hockey – 5x
Number students, who participate in Hockey from University P & Q = 36 + 100 = 136
Number students, who participate in Cricket from University P & Q = 84 + 80 = 164
Difference = 164 + 136 = 300 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
Each student in the universities either participates in any one of the sports or don’t participate in any sports.
Number of students who participate in Hockey match from University R is what percentage of total number of students of University T.
Correct
Answer – 1) 20%
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Hockey match from University R = 4x = 60
Number of students of University T = 300
% = (60/300) * 100 = 20%Incorrect
Answer – 1) 20%
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Hockey match from University R = 4x = 60
Number of students of University T = 300
% = (60/300) * 100 = 20% 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
Each student in the universities either participates in any one of the sports or don’t participate in any sports.
The total number of students who participated in Hockey match from University U is 4/9th those who participated in Cricket from University R. What is the number of students participated in Hockey from University U?
Correct
Answer – 4) 20
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Cricket from University R = 3x = 45
Total number of students who participated in Hockey match from University U
= 4/9 * (Cricket from University R)
= 4/9 * 45 = 20Incorrect
Answer – 4) 20
Explanation:
Students participated in match from University R = 330 – 225 = 105
7x = 105; x = 15
Cricket from University R = 3x = 45
Total number of students who participated in Hockey match from University U
= 4/9 * (Cricket from University R)
= 4/9 * 45 = 20 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
Each student in the universities either participates in any one of the sports or don’t participate in any sports.
What is the approximate average of total number students who participated in Hockey from all the Universities?
Correct
Answer – 3. 69
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
347/5 = 69Incorrect
Answer – 3. 69
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
347/5 = 69 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections:(Q.15) Read the given data and answer the following question.
Each student in the universities either participates in any one of the sports or don’t participate in any sports.
What is the sum of total number of students who participated in Cricket from all Universities to the total number of students who participated in Hockey from all Universities?
Correct
Answer – 2) 650
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 + 303 = 650Incorrect
Answer – 2) 650
Explanation:
Total number students who participated in Hockey from all the Universities = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Cricket from all the Universities = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 + 303 = 650 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(610): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.
Total Number of Students = 600
Total number of students who are selected from course A and E together is how much greater than the total number of students who are selected from course B and F together?
Correct
Answer – 2) 36
Explanation:
course A and E = 18 + 15 = 33%
course B and F = 12 + 15 = 27%
6% of 600 = 36Incorrect
Answer – 2) 36
Explanation:
course A and E = 18 + 15 = 33%
course B and F = 12 + 15 = 27%
6% of 600 = 36 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(610): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.
Total Number of Students = 600
If the total number of students is increased by 30% in June 2018 as compared to May 2018 then the total number of students will participate in June 2018 is
Correct
Answer – 5) 780
Explanation:
130/100 * 600 = 780Incorrect
Answer – 5) 780
Explanation:
130/100 * 600 = 780 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(610): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.
Total Number of Students = 600
Find the central angle of total number of students who are selected from course D?
Correct
Answer – 1) 79.2°
Explanation:
Central angle = 22/100 * 360 = 79.2°Incorrect
Answer – 1) 79.2°
Explanation:
Central angle = 22/100 * 360 = 79.2° 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(610): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.
Total Number of Students = 600
Find the average number of students who are selected from course A, B, C and D together?
Correct
Answer – 2) 105
Explanation:
(70/4*100) * 600 = 105Incorrect
Answer – 2) 105
Explanation:
(70/4*100) * 600 = 105 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections Q.(610): Pie chart given below shows the total number of students who are selected for a competition in a University from five different courses in May 2018. Study the data carefully and answer the following questions.
Total Number of Students = 600
Find the ratio between the total number of students who are selected from course B and D together to the total number of students who are selected from course A and C together?
Correct
Answer – 2) 17 : 18
Explanation:
Ratio = 34 : 36 => 17:18Incorrect
Answer – 2) 17 : 18
Explanation:
Ratio = 34 : 36 => 17:18
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