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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions. Q(1 – 5).Study the following Line graph and answer the following questions.
Line graph represents the % of population participated in a competition

Note: Total Population = Men Population + Women Population

80% of Men participated, and the Women population is 2800 in New Delhi in the year 2016. If the number of participants participated in the competition is 5250. Then the number of Women participated is?

Correct

Answer – 1) 1890
Explanation:
Participated persons = 5250
Total population = 7000
7000 = M+W
M = 4200
80% participated = 4200*80/100 = 3360
3360+women participated = 5250
Women = 1890

Incorrect

Answer – 1) 1890
Explanation:
Participated persons = 5250
Total population = 7000
7000 = M+W
M = 4200
80% participated = 4200*80/100 = 3360
3360+women participated = 5250
Women = 1890

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions. Q(1 – 5).Study the following Line graph and answer the following questions.
Line graph represents the % of population participated in a competition

Note: Total Population = Men Population + Women Population

In Jaipur the population in 2016 to 2018 is increased by 1200, but the number of participants participated is same as in those years. If Men population in both the years is equal and is 5600. 80% of Women participated in the year 2016 and 70% women participated in the year 2018 then what is the ratio of number of Men participated in the year 2016 to the number of Men participated in the year 2018?

Correct

Answer – 2) 8:7
Explanation:
x *80/100 = (x+1200)*70/100
x = 8400
Population in 2016 = 8400 and 2018 =9600
In 2016: 8400 = M+W; in 2018: 9600= M+W
In 2016: 8400 = 5600+W; in 2018: 9600= 5600+W
In 2016 W = 2800; in 2018 W = 4000
In 2016 Women participated = 2240
In 2018 Women participated = 2800
In 2016 Men participated = 4480
In 2018 Men participated = 3920
Ratio = 8:7

Incorrect

Answer – 2) 8:7
Explanation:
x *80/100 = (x+1200)*70/100
x = 8400
Population in 2016 = 8400 and 2018 =9600
In 2016: 8400 = M+W; in 2018: 9600= M+W
In 2016: 8400 = 5600+W; in 2018: 9600= 5600+W
In 2016 W = 2800; in 2018 W = 4000
In 2016 Women participated = 2240
In 2018 Women participated = 2800
In 2016 Men participated = 4480
In 2018 Men participated = 3920
Ratio = 8:7

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions. Q(1 – 5).Study the following Line graph and answer the following questions.
Line graph represents the % of population participated in a competition

Note: Total Population = Men Population + Women Population

In Pune, the total population in the years 2016 and 2018 are 8400 and 9200 respectively. If the sum of the Men participants in 2016 and 2018 together is 8280 and if Men are 55% of the total population in 2018 and 70% Women in 2018 participated then the number of Men participated in the year 2016 is?

Correct

Answer – 2) 3358
Explanation:
Total population in 2016: 8400 = Men + women participants = 8400*65/100 = 5460
Men participated + Women participated = 5460
Total population in 2018: 9200 = Men + women participants = 9200*85/100 = 7820
Men participated + Women participated = 7820
Men participated in (2016+2018) = 8280
Women participated in (2016+2018) =13280-8280 = 5000
In 2018: Women population=9200*45/100 = 4140
Women participated in 2018 = 4140*70/100 = 2898
Women participated in 2016 = 5000-2898 = 2102
Men participated in 2016= 5460-2102 = 3358

Incorrect

Answer – 2) 3358
Explanation:
Total population in 2016: 8400 = Men + women participants = 8400*65/100 = 5460
Men participated + Women participated = 5460
Total population in 2018: 9200 = Men + women participants = 9200*85/100 = 7820
Men participated + Women participated = 7820
Men participated in (2016+2018) = 8280
Women participated in (2016+2018) =13280-8280 = 5000
In 2018: Women population=9200*45/100 = 4140
Women participated in 2018 = 4140*70/100 = 2898
Women participated in 2016 = 5000-2898 = 2102
Men participated in 2016= 5460-2102 = 3358

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions. Q(1 – 5).Study the following Line graph and answer the following questions.
Line graph represents the % of population participated in a competition

Note: Total Population = Men Population + Women Population

In Ahmedabad Men Population in the year is 2016 is 4000. If 20% of Men didn’t participate. The number of Women participated is 2120. The number of women in the year 2016 in Ahmedabad is?

Correct

Answer – 1) 3600
Explanation:
Men =4000
participated = 3200
Men participated +Women participated = 3200+2120 = 5320
Total population = 5320*100/70 = 7600
Women = 7600-4000 =3600

Incorrect

Answer – 1) 3600
Explanation:
Men =4000
participated = 3200
Men participated +Women participated = 3200+2120 = 5320
Total population = 5320*100/70 = 7600
Women = 7600-4000 =3600

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions. Q(1 – 5).Study the following Line graph and answer the following questions.
Line graph represents the % of population participated in a competition

Note: Total Population = Men Population + Women Population

In Ahmedabad, total population in the years 2016 and 2018 are 7600 and 8400 respectively. The number of Women participants in the year 2016 and in the year 2018 is equal, and Men in 2018 are 55% of the total population in 2018 and 70% Women in 2018 participated then the number of Men participated in the year 2016 is?

Correct

Answer – 3) 2674
Explanation:
In 2016:
Men + women = 7600
participants = 5320 = Men participated + Women participated
In 2018:
Men + women = 8400 Women = 45% of 8400 = 3780
Participants = 6720 = Men participated + Women participated
Women participated = 3780*70/100 = 2646
Then Men participated in 2016 = 5320-2646 = 2674

Incorrect

Answer – 3) 2674
Explanation:
In 2016:
Men + women = 7600
participants = 5320 = Men participated + Women participated
In 2018:
Men + women = 8400 Women = 45% of 8400 = 3780
Participants = 6720 = Men participated + Women participated
Women participated = 3780*70/100 = 2646
Then Men participated in 2016 = 5320-2646 = 2674

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

David invested Rs. 80,000 with rate of interest at 20 p.c.p.a. The interest was compounded half yearly for first year and in the next year it was compounded yearly. What will be the total interest earned at the end of two years?

Correct

Answer – 3) Rs. 36,160
Explanation:
First year = 80,000(1+10/100)^2 = 96800
Second year = 96800(1+20/100) = 116160
Interest = 116160-80000= 36160

Incorrect

Answer – 3) Rs. 36,160
Explanation:
First year = 80,000(1+10/100)^2 = 96800
Second year = 96800(1+20/100) = 116160
Interest = 116160-80000= 36160

Ravi sold a smartphone for Rs. 30,000. Had he offered a discount of 10% on the selling price(SP), he would have earned a profit of 35%. What is the cost price?

Rohini invested Rs X on SI at the rate of 12% for 4 years, and he invested Rs (X+200) at 10% CI for 2 years. The total interest obtained is Rs 4320. Find the average amount (in Rs) invested by Rohini?

Correct

Answer – 2) 6300
Explanation:
Simple interest is ,
SI * 100= P *12 *4
SI = 48P/100
In compound interest , total interest will be
(P+200) * 21/100
According to the questions ,
48P/100 + (P+200)*21/100= 4320
P=6200
So P+200=6400
Total investment = 6200 + 6400= 12600
Average Investment = 12600/2 = 6300

Incorrect

Answer – 2) 6300
Explanation:
Simple interest is ,
SI * 100= P *12 *4
SI = 48P/100
In compound interest , total interest will be
(P+200) * 21/100
According to the questions ,
48P/100 + (P+200)*21/100= 4320
P=6200
So P+200=6400
Total investment = 6200 + 6400= 12600
Average Investment = 12600/2 = 6300

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Mahesh rows to the place 80 km away and back in 20 hours. He finds that he can row 8 km downstream in the same time as 4 km upstream. The speed of the boat in stillwater is

Correct

Answer – 1) 9 kmph
Explanation:
If Mahesh moves 8 km downstream in X hours
Downstream speed = 8/X kmph
upstream speed = 4/X kmph
Now 80/(8/X) + 80/(4/X)=20
X=2/3
downstream Speed = 8/(2/3)= 12 kmph
upstream Speed = 4/(2/3)= 6 kmph
Rate of the stream = (12+6)/2= 9 kmph

Incorrect

Answer – 1) 9 kmph
Explanation:
If Mahesh moves 8 km downstream in X hours
Downstream speed = 8/X kmph
upstream speed = 4/X kmph
Now 80/(8/X) + 80/(4/X)=20
X=2/3
downstream Speed = 8/(2/3)= 12 kmph
upstream Speed = 4/(2/3)= 6 kmph
Rate of the stream = (12+6)/2= 9 kmph

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