**Hello Aspirants**. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in**Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link **To solve Quadratic Equations with the help of Number Line**

**Bank PO Level Questions** :-

**x**^{2}– 1 = 0, y^{2}+ 4y + 3 = 0

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**C. X ≥ Y**

Explanation:

x^{2}= 1

x = ± 1

y^{2}+ 4y + 3 = 0

y^{2}+ y + 3y + 3 = 0

y = -1, -3

Put on number line

-3 -1 -1 1**x**^{2}– 10x + 24 = 0, y^{2}– 14y + 48 = 0

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**D. X ≤ Y**

Explanation:

x^{2}– 10x + 24 = 0

x^{2}– 6x – 4x + 24 = 0

x = 4, 6

y^{2}– 14y + 48 = 0

y^{2}– 6y – 8y + 48 = 0

y = 6, 8

Put on number line

4 6 6 8**2x**^{2}– 13x + 20 = 0, 2y^{2}– 7y + 6 = 0

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**A. X > Y**

Explanation:

2x^{2}– 13x + 20 = 0

2x^{2}– 8x – 5x + 20 = 0

x = 2.5, 4

2y^{2}– 7y + 6 = 0

2y^{2}– 3y – 4y + 6 = 0

y = 1.5, 2

Put on number line

1.5 2 2.5 4**(15/√x) + (9/√x) = 11√x, (√y/4) + (5√y/12)= (1/√y)**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**A. X > Y**

Explanation:

(15/√x) + (9/√x) = 11√x

24/√x = 11√x

x = 24/11 = 2.18

(√y/4) + (5√y/12)= (1/√y)

(8√y/12) = (1/√y)

y = 1.5**x**^{4}– 227 = 398, y^{2}+ 321 = 346

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**E. X = Y or relation cannot be established**

Explanation:

x^{4}– 227 = 398

x^{4}= 625

Take square root on both sides

x^{2}= 25

x = 5, -5

y^{2}+ 321 = 346

y^{2}= 25

y^{2}= 25

y = ±5**x**^{2}+ x – 20 = 0, y^{2}+ y – 30 = 0

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**E. X = Y or relation cannot be established**

Explanation:

x^{2}+ x – 20 = 0

x^{2}+ 5x – 4x + 20 = 0

x = -5, 4

y^{2}+ y – 30 = 0

y^{2}+6y -5y – 30 = 0

y = -6, 5

Put on number line

-6 -5 4 5**x**^{2}– 365 = 364, y – √324 = √81

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**D. X ≤ Y**

Explanation:

x^{2}– 365 = 364

x^{2}= 729

x = ± 27

y – √324 = √81

y – 18 = 9

y = 27

Put on number line

-27 27 27**9x – 15.45 = 54.55 + 4x, √(y+155) – 6 = 7**

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**E. X = Y or relation cannot be established**

Explanation:

9x – 15.45 = 54.55 + 4x

9x – 4x = 54.55 + 15.45

5x = 70 => x= 14

√(y+155) – 6 = 7

√(y+155) = 13

Squaring on both sides

y + 155 = 169

y = 14**x**^{2}+ 11x + 30 = 0, y^{2}+ 7y + 12 = 0

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**B. X < Y**

Explanation:

x^{2}+ 11x + 30 = 0

x^{2}+ 6x + 5x + 30 = 0

x = -6, -5

y^{2}+ 7y + 12 = 0

y^{2}+ 4y + 3y + 12 = 0

y = -4, -3

Put on number line

-6 -5 -4 -3**y**^{2}– x^{2}= 32, y – x = 2

A. X > Y

B. X < Y

C. X ≥ Y

D. X ≤ Y

E. X = Y or relation cannot be established

**B. X < Y**

Explanation:

y^{2}– x^{2}= 32

(y + x)(y – x) = 32

From equation(2) y – x = 2

(y + x)2 = 32

y + x = 16 –(a)

y – x = 2 —(b)

2y = 18 => y = 9

9 – x = 2

x = 7

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