Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in **Quadratic Equations** which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

Follow the link **To solve Quadratic Equations with the help of Number Line**

**You have to solve equation I and II ,Give answer
A) If X > Y
B) If X < Y
C) If X ≥ Y
D) If X ≤ Y
E) If X = Y or cannot be established**

**I.5/x – 4/y = -2**

**II.2/x + 3/y = 13**

Answer –**1)If X>Y**

**Explanation :**

5u-4v = -2………*3 =>15u-12v = -6

2u+3v = 13……..*4 => 8u+12v = 52

Solve this eq

23u = 46

U=2, v=3

X=1/2,y=1/3

1/2 > 1/3….x > y

**I.4X**^{2 }+ 4X – 3= 0

**II.14Y**^{2 }– 17Y + 5 = 0

Answer –**4)If X≤ Y**

**Explanation :**

(2X-1)(2X+3) =0

X=1/2, -3/2

(2Y-1)(7Y-5) =0

Y = 1/2, 5/7

5/7, ½, ½, -3/2 => YYXX

Y≥X

**I.2X**^{2 }– 17X + 36= 0

**II.Y**^{2}= 16

Answer –**3)If X≥ Y**

**Explanation :**

(2X-9)(X-4) =0

X=9/2, 4

Y = ±4

9/2, 4,4,-4 => XXYY

X≥Y

**I.6X**^{2 }+ 19X + 15= 0

**II.3Y**^{2 }+ 11Y + 10 = 0

Answer –**3)If X≥ Y**

**Explanation :**

(3X+5)(2X+3) = 0

X=-5/3, -3/2

(Y+2)(3Y+5) =0

Y = -2, -5/3

-3/2, -5/3, -5/3, -2 => XXYY

X≥ Y

**I.4X**^{2 }+ 19X + 21= 0

**II.2Y**^{2 }– 23Y + 63 = 0

Answer –**1)If X>Y**

**Explanation :**

(4x+7)(x+3) = 0

X =-7/4, -3

(2y+9)(y+7) = 0

Y = -9/2, -7

-7/4,-3, -9/2,-7 => xxyy

x>y

**I.3X**^{2 }– 19X + 28= 0

**II.4Y**^{2 }– 29Y + 45 = 0

Answer –**5)If X=Y or cannot be established**

**Explanation :**

(x-4)(3x-7) =0

X=4,7/3

(y-5)(4y-9) =0

Y=5,9/4

5,4,7/3,9/4 => yxyx

**I.X**^{2 }= 5625

**II.Y =**^{3}√421875

Answer –**4)If X≤ Y**

**Explanation :**

X=±75

Y =75

x≤y

**I.8X**^{2 }+ 22X + 15= 0

**II.4Y**^{2 }+ 16Y + 15 = 0

Answer –**3)If X≥ Y**

**Explanation :**

(4x+5)(2x+3) =0

X=-5/4, -3/2

(2y+5)(2xy+3) =0

y=-5/2, -3/2

-5/4,-3/2,-3/2,-5/3 => xxyy

X≥Y

**I.8X**^{2 }+ 10X + 3= 0

**II.5Y**^{2 }– 8Y + 3 = 0

Answer – 2)If X<Y

**Explanation :**

(2X+1)(4X+3) =0

X= -1/2, -3/4

(5Y-3)(Y-1) =0

Y=1, 3/5

3/5, 1, -1/2, -3/4

YYXX => Y>X

**I.3X + 2Y – 9= 0**

**II.4Y – 15Y – 65 = 0**

Answer –**1)If X>Y**

**Explanation :**

45X+30Y = 135

8X-30Y=130

53X=265

X=5, Y= -3

X>Y

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