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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The face value of 6 in 24568 is

Correct

Explanation:
Face value of 2 in 24568 is 2, 4 in 24568 is 4 and so on
Place value of 2 in 24568 is 20000, of 4 is 4000 and so on.

Incorrect

Explanation:
Face value of 2 in 24568 is 2, 4 in 24568 is 4 and so on
Place value of 2 in 24568 is 20000, of 4 is 4000 and so on.

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Rs 9404 is divided among A, B, and C, so that if the amounts being invested at 4% simple interest, the amounts received after 2, 3 and 4 yrs by A, B, and C respectively is equal. Find the share of A?

Correct

Explanation:
9404 will be divided in ratio –
1/[100+rt1] : 1/[100+rt2] : 1/[100+rt3]
1/[100+4*2] : 1/[100+4*3] : 1/[100+4*4]
1/108 : 1/112 : 1/116
= 812 : 783 : 756
So A gets 812/(812+783+756) * 9404

Incorrect

Explanation:
9404 will be divided in ratio –
1/[100+rt1] : 1/[100+rt2] : 1/[100+rt3]
1/[100+4*2] : 1/[100+4*3] : 1/[100+4*4]
1/108 : 1/112 : 1/116
= 812 : 783 : 756
So A gets 812/(812+783+756) * 9404

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

A and B are pipes such that A can empty the tank in 40 minutes and B can fill in 15 minutes. The tank is full of water and pipe A is opened. If after 10 minutes, pipe B is also opened, then in how much total time the tank will be full again?

Correct

Explanation:
Emptying pipe A is opened first for 10 minutes, so in 10 minutes the part of tank it has emptied is (1/40)*10 = 1/4
Now filling pipe is also opened, now since only 1/4 of the tank is empty so 1/4 is only to be filled by both pipes, let it take now x minutes, so
(1/15 – 1/40)*x = 1/4
Solve, x= 6
So total = 10+6 = 16 minutes [total time is asked – 10 minutes when emptying pipe was only opened, 6 minutes when both were operating.]

Incorrect

Explanation:
Emptying pipe A is opened first for 10 minutes, so in 10 minutes the part of tank it has emptied is (1/40)*10 = 1/4
Now filling pipe is also opened, now since only 1/4 of the tank is empty so 1/4 is only to be filled by both pipes, let it take now x minutes, so
(1/15 – 1/40)*x = 1/4
Solve, x= 6
So total = 10+6 = 16 minutes [total time is asked – 10 minutes when emptying pipe was only opened, 6 minutes when both were operating.]

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

How many 3 digits numbers have exactly the digit 2 repeated two times in the number?

Correct

Explanation:
0 cannot be placed at first digit to make it a 3 digit number.
3 cases:
Case 1: 2 is placed at first and second place
1 choice (2) for the first and second place, 9 choices for the 3rd digit (0-9 except 2)
So numbers = 1*1*9 = 9
Case 2: 2 is placed at first and third place
1 choice (2) for the first and third place, 9 choices for the 2nd digit (0-9 except 2)
So numbers = 1*9*1 = 9
Case 3: 2 is placed at second and third place
1 choice (2) for the second and third place, 8 choices for the 1st digit (1-9 except 2)
So numbers = 8*1*1 = 8
So total numbers = 9+9+8

Incorrect

Explanation:
0 cannot be placed at first digit to make it a 3 digit number.
3 cases:
Case 1: 2 is placed at first and second place
1 choice (2) for the first and second place, 9 choices for the 3rd digit (0-9 except 2)
So numbers = 1*1*9 = 9
Case 2: 2 is placed at first and third place
1 choice (2) for the first and third place, 9 choices for the 2nd digit (0-9 except 2)
So numbers = 1*9*1 = 9
Case 3: 2 is placed at second and third place
1 choice (2) for the second and third place, 8 choices for the 1st digit (1-9 except 2)
So numbers = 8*1*1 = 8
So total numbers = 9+9+8

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

32% of a number added to 26% of 150 becomes equal to 17 times seven. What is the number?

A job that can be completed by 3 men and 18 women in 10 days will be completed by 5 men and 30 women in how many days?

Correct

Explanation:
3m + 18w = 10 D
Or 3(1m + 6w) = 10D
Or 1m + 6w = 30D
So 5(1m + 6w) = 30/5
Or 5m + 30w = 6D

Incorrect

Explanation:
3m + 18w = 10 D
Or 3(1m + 6w) = 10D
Or 1m + 6w = 30D
So 5(1m + 6w) = 30/5
Or 5m + 30w = 6D

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

The average of the ages of 3 friends A, B, and C was 27 years before 3 years ago. If the average of the ages of B and C was 20 years 5 years ago, what is the present age of A?

Correct

Explanation:
Sum of ages of A+B+C 3 yrs ago = 27*3 = 81
So after 3 yrs, i.e. at present their total = 81 + 3*3 = 90
Similarly sum of present age of B&C = 20*2 +5*2 = 50
So present age of A = 90-50

Incorrect

Explanation:
Sum of ages of A+B+C 3 yrs ago = 27*3 = 81
So after 3 yrs, i.e. at present their total = 81 + 3*3 = 90
Similarly sum of present age of B&C = 20*2 +5*2 = 50
So present age of A = 90-50

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A mixture contains A and B in the ratio 2 : 3. 10 litres of mixture is replaced by 8 litres of A and the new ratio becomes 10 : 11 respectively. What is the amount of A present in the original mixture?

Correct

Explanation:
A = 2x, B = 3x
After 10 litres draw out:
A = 2x – (2/5)*10 = 2x – 4 , B = 3x – (3/5)*10 = 3x – 6
After 8 l of A put back, A = (2x – 4) + 8 = 2x +4
So (2x+2)/(3x-6) = 10/11
Solve, x = 13
So A = 2x = 2*13

Incorrect

Explanation:
A = 2x, B = 3x
After 10 litres draw out:
A = 2x – (2/5)*10 = 2x – 4 , B = 3x – (3/5)*10 = 3x – 6
After 8 l of A put back, A = (2x – 4) + 8 = 2x +4
So (2x+2)/(3x-6) = 10/11
Solve, x = 13
So A = 2x = 2*13

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

HCF and LCM of two numbers is 3 and 297 respectively and the sum of these two numbers is 60. Find the sum of the reciprocals of these numbers.

Correct

Explanation:
x + y = 60, xy = 3*297 = 891
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 60/891

Incorrect

Explanation:
x + y = 60, xy = 3*297 = 891
sum of reciprocals = 1/x + 1/y = (x+y)/xy = 60/891

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

8 years hence Angad will be twice as old as Bharat and also 8 years ago, Bharat’s age was one-fourth that of Angad. The present age of Angad is

Correct

Explanation:
Angad = A, Bharat = B
Let B’s age 8 yrs ago = x, then A’s age = 4x
After (8+8) = 16 years:
(4x+16) = 2 * (x+8)
Solve, x = 8
A’s present age = 4x+8 = 40

Incorrect

Explanation:
Angad = A, Bharat = B
Let B’s age 8 yrs ago = x, then A’s age = 4x
After (8+8) = 16 years:
(4x+16) = 2 * (x+8)
Solve, x = 8
A’s present age = 4x+8 = 40