Welcome to Online Quants Test in AffairsCloud.com. We are starting IBPS PO Prelim 2016 Course and we are creating sample questions in Quants section, type of which will be asked in IBPS PO 2016 !!!

Directions (1 – 5): The pie chart below shows the year wise sales of mobile phones made by companies P and Q.

The table shows the ratio of sales of mobile phones made by companies P and Q resp. during the given period:

Year

Ratio

P

Q

2006

3

7

2007

7

18

2008

2

3

2009

4

1

2010

11

9

2011

7

3

For company P the sale in 2007 is what percentage of the sales in 2008?

Correct

Explanation:
For P
Sales in 2007 = (7/25)*(10/100)* 3,25,000
Sales in 2008 = (2/5)*(16/100)* 3,25,000
Required% = Sales in 2007/ Sales in 2008 * 100

Incorrect

Explanation:
For P
Sales in 2007 = (7/25)*(10/100)* 3,25,000
Sales in 2008 = (2/5)*(16/100)* 3,25,000
Required% = Sales in 2007/ Sales in 2008 * 100

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions (1 – 5): The pie chart below shows the year wise sales of mobile phones made by companies P and Q.

The table shows the ratio of sales of mobile phones made by companies P and Q resp. during the given period:

Year

Ratio

P

Q

2006

3

7

2007

7

18

2008

2

3

2009

4

1

2010

11

9

2011

7

3

If 40% of the sales by ‘P’ in the years 2007, and 2010 are sold at discount, how many mobile phones are sold by P without discount in these 2 years together?

Correct

Explanation:
In 2007 + 2010 + 2011 = [(7/25)*(10/100) + (11/20)*(20/100)] * 325000 = (69/500)*325000
So without discount = (60/100)* (69/500)*325000

Incorrect

Explanation:
In 2007 + 2010 + 2011 = [(7/25)*(10/100) + (11/20)*(20/100)] * 325000 = (69/500)*325000
So without discount = (60/100)* (69/500)*325000

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions (1 – 5): The pie chart below shows the year wise sales of mobile phones made by companies P and Q.

The table shows the ratio of sales of mobile phones made by companies P and Q resp. during the given period:

Year

Ratio

P

Q

2006

3

7

2007

7

18

2008

2

3

2009

4

1

2010

11

9

2011

7

3

If company Q gets a profit of Rs 240 on each mobile phone sold during 2008, then find its profit in the year 2008?

Correct

Explanation:
By Q, sold in 2008 = (3/5)*(16/100)*325000 = 3120
So profit = 3120*240 = 748,800 = 74.88 lakhs

Incorrect

Explanation:
By Q, sold in 2008 = (3/5)*(16/100)*325000 = 3120
So profit = 3120*240 = 748,800 = 74.88 lakhs

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions (1 – 5): The pie chart below shows the year wise sales of mobile phones made by companies P and Q.

The table shows the ratio of sales of mobile phones made by companies P and Q resp. during the given period:

Year

Ratio

P

Q

2006

3

7

2007

7

18

2008

2

3

2009

4

1

2010

11

9

2011

7

3

For company Q the ratio of the sales in the year 2006 to that in 2011 is?

Mixture A contains 75% milk and mixture B contains 90% milk. A milkman takes some mixture from mixture A and mixes it with four times the amount of mixture from mixture B. What is the percentage of milk in the new mixture?

Correct

Explanation:
Let x from A, 4x form B
So milk from A = (75/100)*x, milk from B = (90/100)*4x
So milk in new mixture is (75x/100) + (360x/100) = 4.35x
Total mixture in third is x+4x = 5x
So % of milk is (4.35x/5x)*100

Incorrect

Explanation:
Let x from A, 4x form B
So milk from A = (75/100)*x, milk from B = (90/100)*4x
So milk in new mixture is (75x/100) + (360x/100) = 4.35x
Total mixture in third is x+4x = 5x
So % of milk is (4.35x/5x)*100

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

5 men started the work and worked for 4 days. Now they are replaced by 12 women where 1 man can do as much work as 2 women do in 1 day. If the works gets completed in a total of 10 days, in how many days 7 women can complete the entire work?

Correct

Explanation:
Given 1 m = 2w, so 12 women = 6 men
Let 1 man do work in x days, so 1 man’s 1 day work = 1/x, so 5 men 1 day’s work = (1/x)*5
And since they did work for 4 days, so there work becomes (5/x)* 4 = 20/x
Now total work completed in 10 days, this mean that 12 women or 6 men did in (10-4) = 6 days
So similarly as above, 1 man’s 1 day work = 1/x, so 6 men 1 day’s work = (1/x)*6
And since they did work for 6 days, so there work becomes (6/x)* 6 = 36/x
So (20/x) + (36/x) = 1
Solve, x = 56
1 man do work in 56 days, so 1 woman in 2*56 days, and 7 women in (2*56)/7

Incorrect

Explanation:
Given 1 m = 2w, so 12 women = 6 men
Let 1 man do work in x days, so 1 man’s 1 day work = 1/x, so 5 men 1 day’s work = (1/x)*5
And since they did work for 4 days, so there work becomes (5/x)* 4 = 20/x
Now total work completed in 10 days, this mean that 12 women or 6 men did in (10-4) = 6 days
So similarly as above, 1 man’s 1 day work = 1/x, so 6 men 1 day’s work = (1/x)*6
And since they did work for 6 days, so there work becomes (6/x)* 6 = 36/x
So (20/x) + (36/x) = 1
Solve, x = 56
1 man do work in 56 days, so 1 woman in 2*56 days, and 7 women in (2*56)/7

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

The incomes of 2 persons A and B is in the ratio 4 : 5. Their expenditures are in the ratio 2 : 3 respectively. If both save Rs 50,000, then what is B’s income?

Correct

Explanation:
Incomes 4x and 5x
Expenditures 2y and 3y
So 4x – 2y = 50000
And 5x – 3y = 50000
Solve both equations, x = 25,000
So B’s income = 5*25000

Incorrect

Explanation:
Incomes 4x and 5x
Expenditures 2y and 3y
So 4x – 2y = 50000
And 5x – 3y = 50000
Solve both equations, x = 25,000
So B’s income = 5*25000

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

The radius of sphere is 16 cm and cost of painting its surface Rs 50 per square cm. Suppose the radius of sphere and its cost are increased by 5% and 10% respectively. What will be the percentage increase in the total cost of painting per square cm?

Correct

Explanation:
Surface area of square is 4ᴨr^{2}
Radius increases by 5%, so by successive increase formula
surface area changes by 5+5+((5*5)/100) = 10.25%
Total cost of painting = Surface area of sphere * Cost
So again by successive increase formula
change in cost of painting will be = 10.25+10+((10.25*10)/100)

Incorrect

Explanation:
Surface area of square is 4ᴨr^{2}
Radius increases by 5%, so by successive increase formula
surface area changes by 5+5+((5*5)/100) = 10.25%
Total cost of painting = Surface area of sphere * Cost
So again by successive increase formula
change in cost of painting will be = 10.25+10+((10.25*10)/100)

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

2 pipes A and B are such that A fills the bucket in 8 hrs and B empties the bucket in 4 hrs. If pipe A is opened first and after 2 hours B is also opened, in how much total time (in hours) will the bucket get empty?

Correct

Explanation:
In 2 hrs, bucket filled by A is 2 * 1/8 = 1/4
After 2 hrs, bucket filled by A + B in 1 hr is 1/8 -1/4 = -1/8
This means after 2 hrs, 1/4th is full, now in next 1 hr 1/8 out of 1/4th already filled gets empty, so now 1/4 – 1/8 = 1/8 bucket is filled, in next 1 hr (A+B) empties this 1/8 too
So total 2 + 1 + 1

Incorrect

Explanation:
In 2 hrs, bucket filled by A is 2 * 1/8 = 1/4
After 2 hrs, bucket filled by A + B in 1 hr is 1/8 -1/4 = -1/8
This means after 2 hrs, 1/4th is full, now in next 1 hr 1/8 out of 1/4th already filled gets empty, so now 1/4 – 1/8 = 1/8 bucket is filled, in next 1 hr (A+B) empties this 1/8 too
So total 2 + 1 + 1