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Question 1 of 10
1. Question
1 pointsCategory: Quantitative Aptitude1, 2, 10, 123, 3940,?
Correct
Answer : 5.None
Solution:
1*0.5*2 +1 = 2
2*1*4+2 =10
10*1.5*8+ 3 = 123
123*2*16+4 = 3940
3940*2*32+5 = 315205Incorrect
Answer : 5.None
Solution:
1*0.5*2 +1 = 2
2*1*4+2 =10
10*1.5*8+ 3 = 123
123*2*16+4 = 3940
3940*2*32+5 = 315205 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThe average three numbers x,y,z is A and xy+yz+zx= 0 then the average of a², b², and c² is?
Correct
Answer : 4. 3A²
Solution:
x+y+z = 3A
(x+y+z)² = 9A² = x² +y²+ z² + 2(xy+yz+zx)
average = 3A²Incorrect
Answer : 4. 3A²
Solution:
x+y+z = 3A
(x+y+z)² = 9A² = x² +y²+ z² + 2(xy+yz+zx)
average = 3A² 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA bank gave loan of Rs. X to Sudha at 20% CI compounded annually for 2 years. While the bank gave Rs. X2000 to Suresh at same interest rate but compounded half yearly for 2 years. If Sudha repays Rs. 2639 more than Suresh then what is the loan taken by Suresh?
Correct
Answer : 1. 10,000
Solution:
2639 = x(1.2)^2 – (x2000)(1.1)^4
x =12000
suresh = 10000Incorrect
Answer : 1. 10,000
Solution:
2639 = x(1.2)^2 – (x2000)(1.1)^4
x =12000
suresh = 10000 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeSum of Ages of Charan,Chetan and Chandu is 72. Sum of the age of Charan and twice the age of Chetan is 71 and Sum of the age of Chetan and thrice the age of Chandu is 99. Then who among the following is the eldest?
Correct
Answer : 3. Chandu
Solution:
Charan+Chetan+Chandu = 72
Charan+2Chetan = 71
Chetan+3Chandu = 99
Charan =23 Chetan =24 Chandu =25Incorrect
Answer : 3. Chandu
Solution:
Charan+Chetan+Chandu = 72
Charan+2Chetan = 71
Chetan+3Chandu = 99
Charan =23 Chetan =24 Chandu =25 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeA smaller triangle is having three sides. Another big triangle is having sides exactly twice the sides of the smaller triangle. Then what is the ratio of Area of Smaller triangle to Area of the Bigger triangle?
Correct
Answer : 2. 1:4
Solution:
Smaller triangle sides = a, b, c
Area= √s(sa) (sb) (sc);
s=a+b+c/2
= √(a+b+c)(b+ca)(a+c b)(a+bc)/4
Bigger triangle =2a, 2b, 2c
Area = √(a+b+c)(b+ca)(a+c b)(a+bc)
Ratio = 1:4Incorrect
Answer : 2. 1:4
Solution:
Smaller triangle sides = a, b, c
Area= √s(sa) (sb) (sc);
s=a+b+c/2
= √(a+b+c)(b+ca)(a+c b)(a+bc)/4
Bigger triangle =2a, 2b, 2c
Area = √(a+b+c)(b+ca)(a+c b)(a+bc)
Ratio = 1:4 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA and B started a business by investing Rs. 10,000 and Rs. 12,000. But they decided that one who manages the business will get 10% of the profit as extra. A was assigned to manage business. After few months due to personal reasons A handed over the business to the B.At the end of the year in a profit of Rs.9900 if A got Rs. 4380 in total, Then how many does B managed the business?
Correct
Answer : 4. 8 months
Solution:
10% of profit = 990
remaining 8910 is divided in the ratio of 5:6
A’ share = 4380 = 990*x/12 + 5/11*8910
x = 4 months
B = 8 monthsIncorrect
Answer : 4. 8 months
Solution:
10% of profit = 990
remaining 8910 is divided in the ratio of 5:6
A’ share = 4380 = 990*x/12 + 5/11*8910
x = 4 months
B = 8 months 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeBujji sell watch at a loss of 5%. If he had sold it for Rs. 225 more he would have gained 10%. What will be gain if he sells the watch at Rs.1800?
Correct
Answer : 5. None
Solution:
SP = Cp*95/100
SP+225 = CP*110/100
SP = 1425
CP = 1500
If sold at 1800 profit %=20%Incorrect
Answer : 5. None
Solution:
SP = Cp*95/100
SP+225 = CP*110/100
SP = 1425
CP = 1500
If sold at 1800 profit %=20% 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeBharat went to market with certain money. With that money he can buy either 80 Apples or 140 Mangoes. He bought 70 Mangoes and some Apples by this he was left out with 15% of the money he brought. Then how many Apples did he purchase?
Correct
Answer : 4. 28
Solution:
x= 80A = 140 M
x*85/100 = 70M+N*A
85/100*140M = 70M+ N*140M/80
N =28Incorrect
Answer : 4. 28
Solution:
x= 80A = 140 M
x*85/100 = 70M+N*A
85/100*140M = 70M+ N*140M/80
N =28 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeAjay starts driving from P to Q which are 300 Km apart at 8:00 AM. After one hour Anil starts driving from Q to P. If Anil is x% faster than Ajay they meet at 11:00 AM, then what is the speed of Ajay?
Correct
Answer : 5. Cannot be determined
Incorrect
Answer : 5. Cannot be determined

Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA man can row a distance of 4 km upstream in 15 min and returns in 10 min. If the speed of the stream is doubled then how much time it take to row the same distance up stream?
Correct
Answer : 2. 20 min
Solution:
15/60 = 4/SR
SR = 16
10/60 = 4/S+R
S+R = 24
S =20 R =4
if stream double = 8
then = 4km / 208 = 20 minIncorrect
Answer : 2. 20 min
Solution:
15/60 = 4/SR
SR = 16
10/60 = 4/S+R
S+R = 24
S =20 R =4
if stream double = 8
then = 4km / 208 = 20 min
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