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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeIf a man estimates his loss as 25% of the selling price, then his loss % is
Correct
Explanation:
Loss = CP – SP= (25/100) * SP
So CP= (125/100)*SP
So loss% = loss/CP * 100
So loss% = [(25/100) * SP]/[(125/100)*SP] * 100 = 20%Incorrect
Explanation:
Loss = CP – SP= (25/100) * SP
So CP= (125/100)*SP
So loss% = loss/CP * 100
So loss% = [(25/100) * SP]/[(125/100)*SP] * 100 = 20% 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeThere is 40% increase to an amount in 4 years at simple interest. Find the compound interest earned at Rs 8000 after 3 years at same rate of interest.
Correct
Explanation:
SI = AP = 40/100 * P
So 40/100 * P = P *4*r/100
So r = 10%
A at CI = 8000 [1 + 10/100]^{3} =10648
So CI = 10648 – 8000 =2648Incorrect
Explanation:
SI = AP = 40/100 * P
So 40/100 * P = P *4*r/100
So r = 10%
A at CI = 8000 [1 + 10/100]^{3} =10648
So CI = 10648 – 8000 =2648 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude10 chairs are made by 2 men, 3 women and 4 children together in 10 days. If working capabilities of a man, a woman and a child are in the ratio 5 : 4 : 2, then 16 such chairs will be made by 6 men, 4 women and 7 children in
Correct
Explanation:
Ratio of work= 1/5 : 1/4 : 1/2 = 4 : 5 : 10
So 4 men = 5 women = 10 children
4 men = 10 children so 2 men = 5 children and 6 men = 15 children
5 women = 6 children so 3 women =10 children
So 2 men + 3 women + 4children = 15 children
And 6 men + 4 women + 7 children = 30 children
Now 15 children can make 10 chairs in 10 days, so 30 children can make 16 chairs in x days. Solve x =8 daysIncorrect
Explanation:
Ratio of work= 1/5 : 1/4 : 1/2 = 4 : 5 : 10
So 4 men = 5 women = 10 children
4 men = 10 children so 2 men = 5 children and 6 men = 15 children
5 women = 6 children so 3 women =10 children
So 2 men + 3 women + 4children = 15 children
And 6 men + 4 women + 7 children = 30 children
Now 15 children can make 10 chairs in 10 days, so 30 children can make 16 chairs in x days. Solve x =8 days 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA man takes 5 hours 30 minutes in walking a distance and riding back to starting place. He could walk both ways in 7 hours 15 minutes. The time taken by him to ride back both ways is
Correct
Explanation:
We have a shortcut for this:
Ride both ways is = 5 hours 30 minutes – (7 hours 15 minutes – 5 hours 30 minutes)
= 5 hours 30 minutes – 1hr 45 minutesIncorrect
Explanation:
We have a shortcut for this:
Ride both ways is = 5 hours 30 minutes – (7 hours 15 minutes – 5 hours 30 minutes)
= 5 hours 30 minutes – 1hr 45 minutes 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe straight line 2x + 3y = 12 passes through
Correct
Explanation:
Put y = 0 in equation, we get x = 3
Put x = 0 in equation, we get y = 4
See the figure, which quadrants the line is passing through.Incorrect
Explanation:
Put y = 0 in equation, we get x = 3
Put x = 0 in equation, we get y = 4
See the figure, which quadrants the line is passing through. 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeIf tan (2α + 45) = cot 3α where (2α + 45) and 3α are acute angles, then the value of α is
Correct
Explanation
Cot 3 α = tan (90 – 3 α)
So (2 α + 45) = (90 – 3 α)
Solve, α = 9Incorrect
Explanation
Cot 3 α = tan (90 – 3 α)
So (2 α + 45) = (90 – 3 α)
Solve, α = 9 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeABC is an isosceles triangle with AB = AC. A circle through B touching AC at the middle point intersects AB at P. Then AP : AB is
Correct
Explanation:
AB = AC = 2x
AQ = QC = x
AB is a secant
So AP * AB = AQ^2
AP * 2x = x^2
AP = x/2
So AP/AB = x/2*2x = 1/4Incorrect
Explanation:
AB = AC = 2x
AQ = QC = x
AB is a secant
So AP * AB = AQ^2
AP * 2x = x^2
AP = x/2
So AP/AB = x/2*2x = 1/4 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeIn the following figure, AB be diameter of a circle whose centre is at O. Find the measure of angle CBE in degrees.
Correct
Explanation:
Angle EOB = 18 – 150 = 30
OE and OB are radius, so ar equal which means that angle OEB =angle OBE
So in triangle EOB
30 + angle OEB + angle OBE = 180
angle OEB =angle OBE
solve, so angle OEB =angle OBE = 75
angle OBE = 75, so angle EBC=180 – 75Incorrect
Explanation:
Angle EOB = 18 – 150 = 30
OE and OB are radius, so ar equal which means that angle OEB =angle OBE
So in triangle EOB
30 + angle OEB + angle OBE = 180
angle OEB =angle OBE
solve, so angle OEB =angle OBE = 75
angle OBE = 75, so angle EBC=180 – 75 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeIf x = [a + (a^{2} + b^{3})^{1/2}]^{1/3} + [a – (a^{2} + b^{3})^{1/2}]^{1/3}, then the value of x^{3} + 3bx =
Correct
Explanation:
Cube both sides gives
x^{3} = [a + (a^{2} + b^{3})^{1/2}] + [a – (a^{2} + b^{3})^{1/2}] + 3 {[a + (a^{2} + b^{3})^{1/2}]^{1/3} * [a – (a^{2} + b^{3})^{1/2}]^{1/3}} {[a + (a^{2} + b^{3})^{1/2}]^{1/3} + [a – (a^{2} + b^{3})^{1/2}]^{1/3}}x
So x^{3} = 2a + 3(a^{2} – a^{2} – b ^{3})^{1/3} * x
So x^{3} = 2a + (3bx)Incorrect
Explanation:
Cube both sides gives
x^{3} = [a + (a^{2} + b^{3})^{1/2}] + [a – (a^{2} + b^{3})^{1/2}] + 3 {[a + (a^{2} + b^{3})^{1/2}]^{1/3} * [a – (a^{2} + b^{3})^{1/2}]^{1/3}} {[a + (a^{2} + b^{3})^{1/2}]^{1/3} + [a – (a^{2} + b^{3})^{1/2}]^{1/3}}x
So x^{3} = 2a + 3(a^{2} – a^{2} – b ^{3})^{1/3} * x
So x^{3} = 2a + (3bx) 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA and B invested in a business as Rs 2000 and Rs 3000 respectively. After 6 months, both added Rs 1000 each to their investments. What is the difference in the shares of both, if after a year a total of Rs 13,200 is obtained as profit?
Correct
Explanation:
2000*6 + 3000*6 : 3000*6 + 4000*6
5 : 7
So difference = 2/12 * 13200 = 2200Incorrect
Explanation:
2000*6 + 3000*6 : 3000*6 + 4000*6
5 : 7
So difference = 2/12 * 13200 = 2200
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