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SBI PO Previous Year Question Paper
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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeQ (1-5) Each of the following question below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
Find the value of zx-xy?
Statement 1: xy – zx = 10
Statement 2: zx – yz = 3.5Correct
Answer -1) If the data in statement 1 alone is sufficient to answer the question while the data in statement 2 alone is not sufficient to answer the question.
Explanation –
xy-zx = 10
Therefore, zx-xy = -10Incorrect
Answer -1) If the data in statement 1 alone is sufficient to answer the question while the data in statement 2 alone is not sufficient to answer the question.
Explanation –
xy-zx = 10
Therefore, zx-xy = -10 -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeQ (1-5) Each of the following question below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
Find the area of isosceles triangle?
Statment1. If the Length of base and height is increased by 3 and 8 respectively, the hypotenuse becomes 25.
Statement2. Hypotenuse is 12√2.Correct
Answer – 1) If the data in statement 1 alone is sufficient to answer the question while the data in statement 2 alone is not sufficient to answer the question.
Explanation
Initial length of base is 12 and height is 12 (since isosceles triangle)
(12+3)2 + (12+8)2 = 252Incorrect
Answer – 1) If the data in statement 1 alone is sufficient to answer the question while the data in statement 2 alone is not sufficient to answer the question.
Explanation
Initial length of base is 12 and height is 12 (since isosceles triangle)
(12+3)2 + (12+8)2 = 252 -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeQ (1-5) Each of the following question below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
Find the average of 5 consecutive even numbers.
Statement 1. The difference of fifth number and first number is 8.
Statement 2 The sum of the first two numbers is 6 more than the fifth number.Correct
Answer -2) If the data in statement 2 alone is sufficient to answer the question while data in statement 1 alone is not sufficient to answer the question.
Explanation –
Statement 1 difference between consecutive first even number and fifth even number is always 8
From statement2 Let the numbers are x,x+2,x+4,x+6,x+8
x+x+2 = (x+8) + 6
2x + 2 = x+14
X =12Incorrect
Answer -2) If the data in statement 2 alone is sufficient to answer the question while data in statement 1 alone is not sufficient to answer the question.
Explanation –
Statement 1 difference between consecutive first even number and fifth even number is always 8
From statement2 Let the numbers are x,x+2,x+4,x+6,x+8
x+x+2 = (x+8) + 6
2x + 2 = x+14
X =12 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeQ (1-5) Each of the following question below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
Salary of A and B is in the ratio 4:3 and expenditure is in the ratio 5:4. What is the ratio of their saving ?
Statement 1 A’s saving is 25% of his salary.
Statement 2 A’s salary is Rs. 1250 and expenditure of B is Rs. 440.Correct
Answer – 3) If the data either in statement 1 alone or in statement 2 alone is sufficient to answer the question.
Explanation –
From Statement 1
Let A’s salary = 4x
And A’s expenditure = 5y
A’s saving = 4x-5y
Also, A’s saving = 25% of 4x = x
x = 4x – 5y
3x = 5y
Statement 2
A’s salary 4x = 1250
X = 1250 / 4
B’s expenditure 4y = 440
Y = 440/ 4Incorrect
Answer – 3) If the data either in statement 1 alone or in statement 2 alone is sufficient to answer the question.
Explanation –
From Statement 1
Let A’s salary = 4x
And A’s expenditure = 5y
A’s saving = 4x-5y
Also, A’s saving = 25% of 4x = x
x = 4x – 5y
3x = 5y
Statement 2
A’s salary 4x = 1250
X = 1250 / 4
B’s expenditure 4y = 440
Y = 440/ 4 -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeQ (1-5) Each of the following question below consists of a question and two statements numbered 1 and 2 are given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.
What is the son’s present age?
Statement 1 Son’s age is one-fifth of the age of his father.
Statement 2 Five years ago the father’s age was fifteen times the son’s age at that time.Correct
Answer – 5) If the data in both the statements 1 and 2 together are necessary to answer the question.
Explanation –
From statement 1
let father’s present age = 5x
Son’s present age = x
From statement 2
(5x-5) = 15 × (x- 5)
X = 7Incorrect
Answer – 5) If the data in both the statements 1 and 2 together are necessary to answer the question.
Explanation –
From statement 1
let father’s present age = 5x
Son’s present age = x
From statement 2
(5x-5) = 15 × (x- 5)
X = 7 -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections- Q (6-10): Each question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –
Quantity 1: A and B invested in a scheme offering simple interest of 10% per annum in the ratio 3:2. A invested for 9 months whereas B invested for 11 months. Find five times of the ratio of interest obtained by A and B?
Quantity 2: If 4x – 9y = 2x + 5y and 9x – 14y = 42, Find the value of x?Correct
Answer -1) Quantity1 >Quantity 2
Explanation –
Qty 1 — (3×9)/ (2×11) = 27/22 = (1+ 5/22)
Five times of the ratio = 5 × (1+ 5/22) = 5 + 25/22 = 6+ 3/22
Qty 2 – 4x – 9y = 2x+5y
2x = 14y
9x -14y =42
7x = 42
X = 6Incorrect
Answer -1) Quantity1 >Quantity 2
Explanation –
Qty 1 — (3×9)/ (2×11) = 27/22 = (1+ 5/22)
Five times of the ratio = 5 × (1+ 5/22) = 5 + 25/22 = 6+ 3/22
Qty 2 – 4x – 9y = 2x+5y
2x = 14y
9x -14y =42
7x = 42
X = 6 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections- Q (6-10): Each question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –
Quantity 1 –A alone can do a work in 10 hours whereas B alone can do the same piece of work 15 hours, find the time taken by C and D together to finish the same work, given that the efficiency of A is 90% of the efficiency of C and Efficiency of B is 80% of the efficiency of D.
Quantity 2 –Pipe P alone can fill a tank in 9 hours and Pipe Q alone can fill the same tank in 12 hours. Find the time taken when both pipe open together can fill the tank?Correct
Answer -5) Quantity 1 = Quantity 2 or no relation can be established.
Explanation
Qty 1 (Time taken by A) × (Efficiency of A) = (Time Taken by C) ×( Efficiency of C)
10×90% = T × 100%
Time taken by C = 9 hours
Similarly, Time taken by B × Efficiency of B = Time taken by D × Efficiency of D
15 × 80% = T × 100%
Time taken by D = 12 hours
Let the total work = LCM of 9 and 12
Total work = 36units
Per hour work by C = 36/9 = 4 units
Per hour work by D = 36/12 = 3 units
Time taken by C and D together = 36/7 hours
Qty 2 – Let the capacity of tank is LCM of 9 and 12
Capacity of tank = 36units
Tank filled per hour by P = 36/9 = 4 units
Tank filled per hour by Q = 36/12 = 3 units
Time taken by P and Q together to fill the tank = 36/7 hoursIncorrect
Answer -5) Quantity 1 = Quantity 2 or no relation can be established.
Explanation
Qty 1 (Time taken by A) × (Efficiency of A) = (Time Taken by C) ×( Efficiency of C)
10×90% = T × 100%
Time taken by C = 9 hours
Similarly, Time taken by B × Efficiency of B = Time taken by D × Efficiency of D
15 × 80% = T × 100%
Time taken by D = 12 hours
Let the total work = LCM of 9 and 12
Total work = 36units
Per hour work by C = 36/9 = 4 units
Per hour work by D = 36/12 = 3 units
Time taken by C and D together = 36/7 hours
Qty 2 – Let the capacity of tank is LCM of 9 and 12
Capacity of tank = 36units
Tank filled per hour by P = 36/9 = 4 units
Tank filled per hour by Q = 36/12 = 3 units
Time taken by P and Q together to fill the tank = 36/7 hours -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections- Q (6-10): Each question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –
Quantity 1: Find the quantity of water, if after mixing it with 2 liter of milk and selling it at CP milkman saves 15%.
Quantity 2: Find the quantity of water in a glass of wine and water mixed in the ratio 1:3 respectively, the capacity of glass is 1200 ml.Correct
Answer – 5) Quantity 1 = Quantity 2 or no relation can be established.
Explanation –
Qty 1– Let the cost of 2 liter of milk is Rs. 20
For 15% profit selling price = Rs. 23
Hence, 2300 ml in sold at Rs. 23
300ml of water is mixed
Qty 2 –Quantity of water = ¼ ×1200 = 300mlIncorrect
Answer – 5) Quantity 1 = Quantity 2 or no relation can be established.
Explanation –
Qty 1– Let the cost of 2 liter of milk is Rs. 20
For 15% profit selling price = Rs. 23
Hence, 2300 ml in sold at Rs. 23
300ml of water is mixed
Qty 2 –Quantity of water = ¼ ×1200 = 300ml -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections- Q (6-10): Each question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –
Quantity 1: Smith scored 3500 runs in 30 test matches, but he batted in 80% of the innings. Find the average score of Smith per inning in which he batted. (Each test match has 2 innings)
Quantity 2: Find the Strike rate of Smith when he scored 100runs in 135 balls. (Strike Rate = (Run scored / Balls) × 100Correct
Answer – 3) Quantity 1 < Quantity 2
Explanation –
Qty 1 – Runs scored = 3500
Total innings in 30 tests = 60
Innings in which he batted = 80% of 60 = 48
Average score = 3500/48 = 73 aprox
Qty 2
Strike rate = (100/135) ×100 = 74% aproxIncorrect
Answer – 3) Quantity 1 < Quantity 2
Explanation –
Qty 1 – Runs scored = 3500
Total innings in 30 tests = 60
Innings in which he batted = 80% of 60 = 48
Average score = 3500/48 = 73 aprox
Qty 2
Strike rate = (100/135) ×100 = 74% aprox -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections- Q (6-10): Each question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –
Quantity 1 Find the value of x when, x/5 + x – 6/5 =0
Quantity 2 Find the values of y when 3y2 -4y+1 = 0Correct
Answer – 2) Quantity 1 ≥ Quantity 2
Explanation –
Qty 1 = 6x/5 = 6/5
X = 1
Quantity 2 3y2 -4y+1 = 0
3y2 – 3y –y + 1 = 0
3y(y-1) – 1 (y-1) = 0
(3y-1) (y-1) = 0
Y = 1/3, 1Incorrect
Answer – 2) Quantity 1 ≥ Quantity 2
Explanation –
Qty 1 = 6x/5 = 6/5
X = 1
Quantity 2 3y2 -4y+1 = 0
3y2 – 3y –y + 1 = 0
3y(y-1) – 1 (y-1) = 0
(3y-1) (y-1) = 0
Y = 1/3, 1
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