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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeAn article is sold at a discount of 4% making a profit of 20%. What would have been the profit percent if the article was sold without discount?
Correct
Explanation:
Let MP = Rs 100
at 4% discount gives: SP = Rs 96,
Now profit = 20%
so CP = (100/120) * 96 = 80
No discount given means SP = MP = 100
So Profit% when no discount = [(100-80)/80]*100Incorrect
Explanation:
Let MP = Rs 100
at 4% discount gives: SP = Rs 96,
Now profit = 20%
so CP = (100/120) * 96 = 80
No discount given means SP = MP = 100
So Profit% when no discount = [(100-80)/80]*100 -
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA vessel is full of milk. 10 litres of milk is taken out and replaced by water. Again the process is followed and now 15 litres of the mixture is replaced by water. After this the final ratio of milk to water becomes 4 : 5. What is the capacity of vessel in litres?
Correct
Explanation:
let x litres initially
after 2 steps , milk left = x [1 – (15/x)]^2
and total is x we know
now milk to water is 4 : 5, so milk to total becomes 4 : (4+5) = 4 : 9
so [ x [1 – (15/x)]^2 ] / x = 4/9
x got cancelled
so [1 – (15/x)]^2 = 4/9[1 – (15/x)] = 2/3
Solve, x = 45 litresIncorrect
Explanation:
let x litres initially
after 2 steps , milk left = x [1 – (15/x)]^2
and total is x we know
now milk to water is 4 : 5, so milk to total becomes 4 : (4+5) = 4 : 9
so [ x [1 – (15/x)]^2 ] / x = 4/9
x got cancelled
so [1 – (15/x)]^2 = 4/9[1 – (15/x)] = 2/3
Solve, x = 45 litres -
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA, B, and C invested Rs 3000, Rs 3500 and Rs 4000 in a business. After 8 months they all added Rs 500 to their investments. In what respective ratio they will get the profits after a year?
Correct
Explanation:
A : B : C
3000*8 + 3500*4 : 3500*8 + 4000*4 : 4000*8 + 4500*4
30*8 + 35*4 : 35*8 + 40*4 : 40*8 + 45*4
30*2 + 35 : 35*2 + 40 : 40*2 + 45
6*2 + 6 : 7*2 + 8 : 8*2 + 9
12 + 6 : 14 + 8 : 16 + 9
18 : 22 : 25Incorrect
Explanation:
A : B : C
3000*8 + 3500*4 : 3500*8 + 4000*4 : 4000*8 + 4500*4
30*8 + 35*4 : 35*8 + 40*4 : 40*8 + 45*4
30*2 + 35 : 35*2 + 40 : 40*2 + 45
6*2 + 6 : 7*2 + 8 : 8*2 + 9
12 + 6 : 14 + 8 : 16 + 9
18 : 22 : 25 -
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeHow many 3 digits numbers are there which end with digit 6 (repetition not allowed)?
Correct
Explanation:
Repetition not allowed:
For a number to be 3 digit, 1st digit should be from 1 to 9, so 9 choices for 1st digit, but 6 can not be at 1st place because it is fixed at 3rd. so 8 choices
For 2nd digit, 0 can also come, so 10 choices BUT 6 and the digit which came at first place are excluded, so 8 choices
For 3rd digit, only 1 choice is there which is 6
So total = 8*8*1 = 64 numbersIncorrect
Explanation:
Repetition not allowed:
For a number to be 3 digit, 1st digit should be from 1 to 9, so 9 choices for 1st digit, but 6 can not be at 1st place because it is fixed at 3rd. so 8 choices
For 2nd digit, 0 can also come, so 10 choices BUT 6 and the digit which came at first place are excluded, so 8 choices
For 3rd digit, only 1 choice is there which is 6
So total = 8*8*1 = 64 numbers -
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe ratio of B’s present age and A’s age 2 years hence is 5 : 6. If twice B’s present age is 10 more than A’s age 8 years after, what is the ratio of present ages of A and B?
Correct
Explanation:
B/(A+2) = 5/6, so 6B – 5A = 10
Also 2B = (A+8) +10, so 2B – A = 18
Solve, both equations, A = 22, B= 20
So required ratio is 22/20Incorrect
Explanation:
B/(A+2) = 5/6, so 6B – 5A = 10
Also 2B = (A+8) +10, so 2B – A = 18
Solve, both equations, A = 22, B= 20
So required ratio is 22/20 -
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeSolution A has 33 1/3% water and rest milk. If 10 litres of water is added to it, then percentage of milk will become 40%. What was the initial weight of solution A?
Correct
Explanation:
100/3% water is present
After 10 litres of water added, milk is 40% so milk is 60%
Then
[(100/3*100) * x] + 10 = (60/100) * (x+10)
Solve, x = 15Incorrect
Explanation:
100/3% water is present
After 10 litres of water added, milk is 40% so milk is 60%
Then
[(100/3*100) * x] + 10 = (60/100) * (x+10)
Solve, x = 15 -
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeIn a class of 96 students, ratio of number of boys to girls is 5 : 3. Among the boys ratio of number of sports persons to non-sports persons is 7 : 5. If the ratio of total sports persons to total non-sports persons in class is 2 : 1, find the ratio of number of girls of sports persons to non-sports persons.
Correct
Explanation:
Boys in class = (5/8)*96 = 60, so girls = 96-60=36
Among boys, spots persons = (7/12)*60 = 35, so non-sports persons = 60-35 = 25
Total sports person in class = 2/(2+1) * 96 = 64, so non-sports persons = 96-64 = 32
So among girls sports person = 64-35=29, non-sports = 32-25 = 7
So ratio = 29 : 7Incorrect
Explanation:
Boys in class = (5/8)*96 = 60, so girls = 96-60=36
Among boys, spots persons = (7/12)*60 = 35, so non-sports persons = 60-35 = 25
Total sports person in class = 2/(2+1) * 96 = 64, so non-sports persons = 96-64 = 32
So among girls sports person = 64-35=29, non-sports = 32-25 = 7
So ratio = 29 : 7 -
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe speed of the stream is 6 km/hr and speed of the boat in still water is 9 km/hr. If a boat takes 70 hrs to travel downstream from point A to B and coming back to point C midway between A and B, the what is the total distance travelled by the boat?
Correct
Explanation:
Downstream speed = 9+6 = 15
Upstream speed = 9-6 = 3
Let the distance from A to B is x km
downstream distance = x, upstream distance is half of x because boat goes half way upstream, then
x/15 + (x/2)/3 = 70
solve, x = 300
so boat covered 300 + 300/2Incorrect
Explanation:
Downstream speed = 9+6 = 15
Upstream speed = 9-6 = 3
Let the distance from A to B is x km
downstream distance = x, upstream distance is half of x because boat goes half way upstream, then
x/15 + (x/2)/3 = 70
solve, x = 300
so boat covered 300 + 300/2 -
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeWhat is the HCF of 2/3, 6/15, 4/5, 8/21?
Correct
Explanation:
HCF will be HCF of numerators/LCM of denominators
So HCF = (HCF of 2,6,4,8)/(LCM of 3,15, 5, 21)
= 2/105Incorrect
Explanation:
HCF will be HCF of numerators/LCM of denominators
So HCF = (HCF of 2,6,4,8)/(LCM of 3,15, 5, 21)
= 2/105 -
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeFind the least number which when divided by 3, 5, 10 and 12 leaves a remainder 4 but leaves no remainder when same number is divided by 23.
Correct
Explanation:
LCM(3, 5, 10, 12) = 60
So the number will be somewhat = 60x + 4
This number leaves no remainder when divided by 23, so x = 3 to get (60x+4) fully divided by 23
So number = 60*3 + 4Incorrect
Explanation:
LCM(3, 5, 10, 12) = 60
So the number will be somewhat = 60x + 4
This number leaves no remainder when divided by 23, so x = 3 to get (60x+4) fully divided by 23
So number = 60*3 + 4
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