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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe time taken for covering a distance of ‘Y’ Km by downstream is equal to ‘Y18’ by covering upstream. Upstream speed is less than 6 kmph than that of down stream. If the speed of the boat in still water is 15 kmph. What is the value of ‘Y’.
Correct
Answer – 3. 54
Explanation:
Sd = 15+a = 15
Su = 15a = 12
x/Sd = x18/Su
x = 54Incorrect
Answer – 3. 54
Explanation:
Sd = 15+a = 15
Su = 15a = 12
x/Sd = x18/Su
x = 54 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeL,M,N started a business at the initial capital in the ratio of 2:3:4. At the end of sixth month, L invests amount such that his initial capital become equal to M’s initial investment. M’s annual profit is 3000. What is the total profit?
Correct
Answer – 2. 9500
Explanation:
L : M : N = 2 : 3 : 4
= (2 × 6) + (3 × 6) : 3 × 12 : 4 × 12
= (12 + 18) : 36 : 48
= 30 : 36 : 48
= 5 : 6 : 8
M’s annual profit is 3000 = 3000/6 = 500
Total profit = 500 × 19 = 9500Incorrect
Answer – 2. 9500
Explanation:
L : M : N = 2 : 3 : 4
= (2 × 6) + (3 × 6) : 3 × 12 : 4 × 12
= (12 + 18) : 36 : 48
= 30 : 36 : 48
= 5 : 6 : 8
M’s annual profit is 3000 = 3000/6 = 500
Total profit = 500 × 19 = 9500 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeA dealer sells a remote controlled car and a remote controlled bike at 20% and 30% profit. Total profit earned by him is Rs. 140. The Cost price of remote controlled car is 50 less than cost price of remote controlled bike. Find the cost price of remote controlled bike.
Correct
Answer – 3. 300
Explanation:
Cost price of remote controlled car = x
Cost price of remote controlled bike = x – 50
= (x – 50) × 20/100 + x × 30/100 = 140
= (20x – 1000 + 30x)/100 = 140
= 50x – 1000 = 140 × 100
= 50x – 1000 = 14000
= x = 15000/50 = 300Incorrect
Answer – 3. 300
Explanation:
Cost price of remote controlled car = x
Cost price of remote controlled bike = x – 50
= (x – 50) × 20/100 + x × 30/100 = 140
= (20x – 1000 + 30x)/100 = 140
= 50x – 1000 = 140 × 100
= 50x – 1000 = 14000
= x = 15000/50 = 300 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeA Vessel contain Lime and water in 7:1. Onetenth of mixture is taken out and 3 litre water is added. Finally in the Vessel Lime and water are in the ratio is 6:1. Find the initial quantity of the mixture.
Correct
Answer – 4. 160
Explanation:
Lime and Water = 7x : 1x
1/10 is taken out = 7 – 0.7 : 1 – 0.10
Lime and Water = 6.3x : 0.9x
Add 3 litres of water and after that the ratio is 6 : 1
= 6.3x/0.9x + 3 = 6/1
= 6.3x = 6 × 0.9x + 3
X = 18/0.9; X = 20
Initial quantity of Lime and Water
= 7x : 1x = 7 × 20 : 1 × 20 = 140 : 20Incorrect
Answer – 4. 160
Explanation:
Lime and Water = 7x : 1x
1/10 is taken out = 7 – 0.7 : 1 – 0.10
Lime and Water = 6.3x : 0.9x
Add 3 litres of water and after that the ratio is 6 : 1
= 6.3x/0.9x + 3 = 6/1
= 6.3x = 6 × 0.9x + 3
X = 18/0.9; X = 20
Initial quantity of Lime and Water
= 7x : 1x = 7 × 20 : 1 × 20 = 140 : 20 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeSri spends 36% on food. Remaining ¼th on EMI for Education loan and ⅜th on EMI for Home loan. What is the difference between the amount paid to EMI for Education loan and EMI for Home loan is 1200. What is the total savings of Sri?
Correct
Answer – 4. 3600
Explanation:
Food = 36x
EMI for Education loan = 16x
EMI for Home loan = 24x
Difference between the amount paid to EMI for Education loan and EMI for Home loan
= 24x – 16x = 1200
= 8x = 1200
= x = 1200/8 = 150
X = 150
Savings = Income – Expenditure
= 100 – 36 – 16 24 = 24
Savings is 24x = 24 × 150 = 3600Incorrect
Answer – 4. 3600
Explanation:
Food = 36x
EMI for Education loan = 16x
EMI for Home loan = 24x
Difference between the amount paid to EMI for Education loan and EMI for Home loan
= 24x – 16x = 1200
= 8x = 1200
= x = 1200/8 = 150
X = 150
Savings = Income – Expenditure
= 100 – 36 – 16 24 = 24
Savings is 24x = 24 × 150 = 3600 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitudex² – 23x + 132 = 0
y² – 30y + 216 = 0Correct
Answer – 4. X ≤ Y
Explanation:
x² – 23x + 132 = 0
x = 12, 11
y² – 30x + 216 = 0
y = 12, 18Incorrect
Answer – 4. X ≤ Y
Explanation:
x² – 23x + 132 = 0
x = 12, 11
y² – 30x + 216 = 0
y = 12, 18 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitudex² + 20x + 91 = 0
y² + 32y + 247 = 0Correct
Answer – 3. X ≥ Y
Explanation:
x² + 20x + 91 = 0
x = 13, 7
y² + 32y + 247 = 0
y = 13, 19Incorrect
Answer – 3. X ≥ Y
Explanation:
x² + 20x + 91 = 0
x = 13, 7
y² + 32y + 247 = 0
y = 13, 19 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitudex² – 31x + 240 = 0
y² – 30y + 221 = 0Correct
Answer – 5. X = Y or relation cannot be established
x² – 31x + 240 = 0
x = 15, 16
y² – 30y + 221 = 0
y = 13, 17Incorrect
Answer – 5. X = Y or relation cannot be established
x² – 31x + 240 = 0
x = 15, 16
y² – 30y + 221 = 0
y = 13, 17 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude798 654 554 ? 454 438
Correct
Answer – 4. 490
Explanation :
12^2 10^2, 8^2Incorrect
Answer – 4. 490
Explanation :
12^2 10^2, 8^2 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative Aptitude13 15 26 ? 328 1650
Correct
Answer – 3. 84
Explanation :
* 1 + 2
* 2 – 4
* 3 + 6Incorrect
Answer – 3. 84
Explanation :
* 1 + 2
* 2 – 4
* 3 + 6
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