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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhat number must be added or subtracted from numerator and denominator of fraction 17/24, so that it becomes equal to 1 : 2?
Correct
Explanation:
(17x)/(24x) = 1/2
Solve, x= 10Incorrect
Explanation:
(17x)/(24x) = 1/2
Solve, x= 10 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeA and B invests in a business. A contributes 1/4th of the total capital for 15 months and B received 2/3rd of the profit. For how long did B invested in the business?
Correct
Explanation:
A contributes 1/4 for 15 monthe, so B contributes 3/4 for x months, so ratio of profit is
(1/4)*15 : (3/4)*x
= 5 : x
Now B got 2/3 of y (y = total profit)
So x/(5+x) * y = 2/3 * y
So x/(5+x) = 2/3
Solve, x = 10Incorrect
Explanation:
A contributes 1/4 for 15 monthe, so B contributes 3/4 for x months, so ratio of profit is
(1/4)*15 : (3/4)*x
= 5 : x
Now B got 2/3 of y (y = total profit)
So x/(5+x) * y = 2/3 * y
So x/(5+x) = 2/3
Solve, x = 10 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeThe sum of 5% of a number and 4% of other number is 2/3 of the sum of 6% of the first number and 8% of second. The ratio of first number to second number is
Correct
Explanation:
5x + 4y = (2/3) * (6x + 8y)
15x + 12y = 12x + 16y
3x = 4y
So x/y = 4/3Incorrect
Explanation:
5x + 4y = (2/3) * (6x + 8y)
15x + 12y = 12x + 16y
3x = 4y
So x/y = 4/3 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeRs 2550 is to be paid back in 2 equal installments in 2 years. If the rate of interest offered is 4% per annum compounded annually, what is each installment?
Correct
Explanation:
2550 ={ x/[1 + 4/100] } + { x/[1 + 4/100]^2 }
So 2550 = x [1/ (26/25) + 1/ (26/25)^2]
2550 = x [ 25/26 + 625/676]
2550 = x [(650+625)/676]
2 = x/676
Solve, x = 1352Incorrect
Explanation:
2550 ={ x/[1 + 4/100] } + { x/[1 + 4/100]^2 }
So 2550 = x [1/ (26/25) + 1/ (26/25)^2]
2550 = x [ 25/26 + 625/676]
2550 = x [(650+625)/676]
2 = x/676
Solve, x = 1352 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude2 chairs are sold for same amount such that one is at a loss of 20% and other at profit of 44%. If both the chairs were bought for Rs 1008, what is the cost price of the one sold at loss?
Correct
Explanation:
CP : x and 1008x
SPs are same
So (80/100) * x = (144/100) * (1008x)
Solve, x= 648Incorrect
Explanation:
CP : x and 1008x
SPs are same
So (80/100) * x = (144/100) * (1008x)
Solve, x= 648 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeA person is able to buy 500 g more sugar for Rs 36 when price of sugar reduced by 20%. What is the original price of sugar per kilogram?
Correct
Explanation:
Suppose original price of sugar is x, so quantity bought for Rs 36 = 36/x
Now price reduced by 20%, so price = (80/100)*x = 0.8x, so now quantity bought for Rs 36 = 36/0.8x which should be 500 g (1/2 kg) more than 36/x
So 36/0.8x = 36/x + 1/2
Solve, x = 18Incorrect
Explanation:
Suppose original price of sugar is x, so quantity bought for Rs 36 = 36/x
Now price reduced by 20%, so price = (80/100)*x = 0.8x, so now quantity bought for Rs 36 = 36/0.8x which should be 500 g (1/2 kg) more than 36/x
So 36/0.8x = 36/x + 1/2
Solve, x = 18 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeWhat are the factors of (6√3 x^{2} – 47x + 5√3)?
Correct
Explanation:
6√3 x^{2} – 47x + 5√3
6√3 x^{2} – 45x – 2x + 5√3
3√3x (2x – 5√3) – (2x – 5√3)
(2x – 5√3) (3√3x – 1)Incorrect
Explanation:
6√3 x^{2} – 47x + 5√3
6√3 x^{2} – 45x – 2x + 5√3
3√3x (2x – 5√3) – (2x – 5√3)
(2x – 5√3) (3√3x – 1) 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA work can be completed by 3 men or 4 women in 22 days, then the same work can be completed by 5 men and 8 women in
Correct
Explanation:
3men………4women
5men………….8women
Cross multiply and add: 3*8 + 4*5 = 24 + 20 = 44
So days = 22*3*4/44 = 6Incorrect
Explanation:
3men………4women
5men………….8women
Cross multiply and add: 3*8 + 4*5 = 24 + 20 = 44
So days = 22*3*4/44 = 6 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeHow many 3 digit numbers are there in which the digit 6 occur only once?
Correct
Explanation:
If 6 is at first place, then 9 choices (0,1,2,3,4,5,7,8,9) each for 2nd and 3rd digits, so numbers – 9*9 = 81.
If 6 is at second place, then 9 choices (0,1,2,3,4,5,7,8,9) for 3rd digit, and 8 choices for 1st digit (1,2,3,4,5,7,8,9) numbers – 9*8 = 72.
If 6 is at third place, then 9 choices (0,1,2,3,4,5,7,8,9) for 2nd digit, and 8 choices for 1st digit (1,2,3,4,5,7,8,9) numbers – 9*8 = 72.
So total – 81+72+72 = 225Incorrect
Explanation:
If 6 is at first place, then 9 choices (0,1,2,3,4,5,7,8,9) each for 2nd and 3rd digits, so numbers – 9*9 = 81.
If 6 is at second place, then 9 choices (0,1,2,3,4,5,7,8,9) for 3rd digit, and 8 choices for 1st digit (1,2,3,4,5,7,8,9) numbers – 9*8 = 72.
If 6 is at third place, then 9 choices (0,1,2,3,4,5,7,8,9) for 2nd digit, and 8 choices for 1st digit (1,2,3,4,5,7,8,9) numbers – 9*8 = 72.
So total – 81+72+72 = 225 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeA train starts from station A and another train from station B at same time. When both travel in same direction, they meet in 7 hrs and when they travel in opposite direction they meet in 1 hour. If the distance between both stations is 70 km, what is the speed of train that started from station B?
Correct
Explanation:
Let speeds – x and y km/hr resp
So 70/(x+y) = 1
And 70/(xy) = 7
Solve both equations, y = 30Incorrect
Explanation:
Let speeds – x and y km/hr resp
So 70/(x+y) = 1
And 70/(xy) = 7
Solve both equations, y = 30
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