Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS exams. We have included Some questions that are repeatedly asked in exams.

**A sugar and a water solution of 100 litres consists of 20% of sugar. If the solution is heated, water evaporates and the sugar concentration becomes 80% of the solution. What amount of water has evaporated?**

A. 70 litres

B. 50 litres

C. 75 litres

D. 65 litres**C. 75 litres**

Explanation:

In 100 litres solution, sugar = 20 l, water = 80 l

Suppose x litres of water evaporated.

So now the solution becomes (100-x) litres and water becomes (80-x) litres.

In this (100-x) litres, 20% is water.

So 20/100 (100-x) = 80-x

Solve, x = 75**Two die are tossed simultaneously. Find the probability that the multiplication of the two numbers on the die is a composite number.**

A. 1/6

B. 1/2

C. 5/6

D. 29/36**D. 29/36**

Explanation:

Maximum product can be 6*6 = 36

Prime numbers = 2, 3, 5, 7, …

But after 5, the pairs for multiplication are not available.

So the required 6 pairs are – {(1,2)(2,1)(1,3)(3,1)(1,5)(5,1)}

With 6 pairs as prime number multiplication, we are left with 36-6 = 30 pairs for composite numbers, by pair (1,1) is neither prime nor composite, so composite pairs are 30-1 = 29

So prob of composite = 29/36**A and B move towards each other from two towns that are 55 km apart. A’s speed is 12 km/hr and B’s speed is 10 km/hr. After how much time will they be 11 km apart?**

A. 1 hr

B. 2 hr

C. 4hr

D. 6 hr**B. 2 hr**

Explanation:

They have to be 11 km apart, so total distance to be travelled by them is (55-11) = 44 km

Since in opposite direction, so relative speed = 12+10 = 22 km/hr

So time = 44/22 = 2**20 men and 30 women take 5 days to complete a piece of work. It takes 20 days for the same work to be completed by 6 men and 5 women. How many days will it take for 40 men to complete the same work?**

A. 2

B. 3

C. 4

D. 6**C. 4**

Explanation:

(20 m + 30 w) × 5 = (6 m + 5 w) × 20

Solve, 1 w = 2/5 m

Therefore, 30 w = 12 m

We have 20 m + 30 w takes 5 days

Or now 20 m + 12 m takes 5 days

32 m takes 5 days, so 40 m takes 32×5 ÷ 40 = 4**A works twice as fast as B and three times as fast as C. If C can complete a job in 12 hr, then what part of the job can B complete in 1 hr?**

A. 1/2

B. 1/4

C. 1/8

D. 1**C. 1/8**

Explanation:

Time taken by A, B and C is x, 2x, and 3x

3x = 12, x = 4

Time taken by B to complete a work = 8 hr

So part of work in 1 hr = 1/8**A commodity is sold at 10% profit. If it had been bought at 10% less and sold for Rs 2 less, then the gain% would have been 16 2/3%. Find the cost price.**

A. Rs 30

B. Rs 40

C. Rs 25

D. Rs 35**B. Rs 40**

Explanation:

We have a direct formula for these type of ques:

x = 10% profit, y = 10% loss, z = 16 2/3% new profit, A = Rs 2

(100+x)/100 * CP + A = (100-y)/100 * (100+z)/100 * CP

Here the article is sold for Rs 2 less, so for less we take (-2)

(100+10)/100 * CP + (-2) = (100-10)/100 * (100+(50/3))/100 * CP

Solve, CP = 40**There are 3 red balls, 4 blue balls, 6 white balls. Three balls are drawn at random. Find the probability that there is at least 2 red ball.**

A. 21/286

B. 31/286

C. 16/143

D. 20/143**B. 31/286**

Case 1 : 2 red balls:

Prob =^{3}C_{2}×^{10}C_{1}/^{13}C_{3}= 15/143.

Case 2 : 3 red balls:

Prob =^{3}C_{3}/^{13}C_{3}= 1/286.

So total prob. = 15/143 + 1/286= 31/286**A trader bought 10 kg oranges for Rs 405 of which 1 kg was found rotten. If he wishes to make a profit of 10%, at what rate per kg should he sell the remaining oranges?**

A. Rs 48.66

B. Rs 49.50

C. Rs 51.25

D. Rs 44.55**B. Rs 49.50**

Explanation:

After 1 kg found rotten, CP of 9 kg of oranges becomes Rs 405

For 10% profit, SP of 9 kg = 110/100 * 405 = 445.50

So SP per kg = 445.50 ÷ 9 = 49.50**In a town of population 1,20,000, 55% were males and rest females. If 48% of males and 60% of females can vote, then what is the total number of voters in the town?**

A. 64,320

B. 64,080

C. 70,000

D. 69,890**B. 64,080**

Explanation:

Males = 55/100 * 1,20,000 = 50/100 of 1,20,000 + 5/100 of 1,20,000 = 60,000 + 6000 = 66,000

Male voters = 48/100 * 66,000 = 50% of 66,000 – 2% of 66,000 = 33,000 – 1320 = 31680

Females = 1,20,000 – 66,000 = 54,000

Female voters = 60/100 * 54,000 = 32400

Total voters = 31680 + 32400**A man can row 10 km/hr in still water. When the river is running at 4 km/hr, it takes him 5 hrs to row to a place and come back. How far is the place?**

A. 20 km

B. 22 km

C. 21 km

D. 35 km**C. 21 km**

Explanation:

B is speed of boat in still water, R is speed of stream

Time is total time taken for upstream and downstream

Distance = time * [B^2 – R^2] / 2*B

=5 * [10^2 – 4^2] / 2*10

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