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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (15): In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer –
3x^{2} – 20x + 12 = 0, 2y^{2} – 15y + 18 = 0
Correct
Explanation:
3x^{2} – 20x + 12 = 0
3x^{2} – 20x + 12 = 0
Gives x = 6, 2/3
2y^{2} – 15y + 18 = 0
2y^{2} – 12y – 3y + 18 = 0
Gives y = 6, 3/2
Put on number line
2/3…… 3/2 ….. 6
When y = 3/2, y < x(2/3) and y > x(6), so cant be determined.Incorrect
Explanation:
3x^{2} – 20x + 12 = 0
3x^{2} – 20x + 12 = 0
Gives x = 6, 2/3
2y^{2} – 15y + 18 = 0
2y^{2} – 12y – 3y + 18 = 0
Gives y = 6, 3/2
Put on number line
2/3…… 3/2 ….. 6
When y = 3/2, y < x(2/3) and y > x(6), so cant be determined. 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude12x^{2} + x – 1 = 0, 3y^{2} + 13y + 4 = 0
Correct
Explanation:
12x^{2} + x – 1 = 0
12x^{2} + 4x – 3x – 1 = 0
Gives x = 1/3, 1/4
3y^{2} + 13y + 4 = 0
3y^{2} + 12y + y + 4 = 0
Gives y = 1/3, 4
Put on number line
4……. 1/3….. 1/4Incorrect
Explanation:
12x^{2} + x – 1 = 0
12x^{2} + 4x – 3x – 1 = 0
Gives x = 1/3, 1/4
3y^{2} + 13y + 4 = 0
3y^{2} + 12y + y + 4 = 0
Gives y = 1/3, 4
Put on number line
4……. 1/3….. 1/4 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitude3x^{2} + 8x + 5 = 0, 4y^{2} – 13y + 10 = 0
Correct
Explanation:
3x^{2} + 8x + 5 = 0
3x^{2} + 3x + 5x + 5 = 0
Gives x = 5/3, 1
4y^{2} – 13y + 10 = 0
4y^{2} – 8y – 5y + 10 = 0
Gives y = 5/4, 2
Put on number line
5/3… 1……. 5/4….. 2Incorrect
Explanation:
3x^{2} + 8x + 5 = 0
3x^{2} + 3x + 5x + 5 = 0
Gives x = 5/3, 1
4y^{2} – 13y + 10 = 0
4y^{2} – 8y – 5y + 10 = 0
Gives y = 5/4, 2
Put on number line
5/3… 1……. 5/4….. 2 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitudex^{2} + 4x ¬+ 3 = 0, 2y^{2} – 11y + 12 = 0
Correct
Explanation:
x^{2} + 4x ¬+ 3 = 0
x^{2} + 3x + x ¬+ 3 = 0
Gives x = 1, 3
2y^{2} – 11y + 12 = 0
2y^{2} – 8y – 3y + 12 = 0
Gives y = 3/2, 4
Put on number line
3…………. 1………. 3/2……… 4Incorrect
Explanation:
x^{2} + 4x ¬+ 3 = 0
x^{2} + 3x + x ¬+ 3 = 0
Gives x = 1, 3
2y^{2} – 11y + 12 = 0
2y^{2} – 8y – 3y + 12 = 0
Gives y = 3/2, 4
Put on number line
3…………. 1………. 3/2……… 4 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative Aptitude2x^{2} + 13x + 6 = 0, 2y^{2} + y – 10 = 0
Correct
Explanation:
2x^{2} + 13x + 6 = 0
2x^{2} + 12x + x + 6 = 0
Gives x = 6, 1/2
2y^{2} + y – 10 = 0
2y^{2} 4y + 5y – 10 = 0
Gives y= 5/2 , 2
Put on number line
6……….. 5/2……. 1/2…….2Incorrect
Explanation:
2x^{2} + 13x + 6 = 0
2x^{2} + 12x + x + 6 = 0
Gives x = 6, 1/2
2y^{2} + y – 10 = 0
2y^{2} 4y + 5y – 10 = 0
Gives y= 5/2 , 2
Put on number line
6……….. 5/2……. 1/2…….2 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
Approximately what percentage of females in department B are less than that in department C?
Correct
Explanation:
Females in department B = (40/100)*290 = 116
In department C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8%Incorrect
Explanation:
Females in department B = (40/100)*290 = 116
In department C = (35/100)*360 = 126
Required % = (126116)/126 * 100 ≈ 8% 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
How many males in department D are married?
Correct
Explanation:
3/5 * (75/100)*540Incorrect
Explanation:
3/5 * (75/100)*540 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
What is the difference between the total number of females in department A and number of males in department B who are unmarried?
Correct
Explanation:
Females in A = (20/100)*450 = 90
Males in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058Incorrect
Explanation:
Females in A = (20/100)*450 = 90
Males in B who come by bus = (1/3) * (60/100)*290 = 58
Difference = 9058 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
What is the total number of males in departments D and E?
Correct
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200Incorrect
Explanation:
D + E
(75/100)*540 + (80/100)*250 = 405+200 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeDirections (6 – 10): Study the following table and answer the questions that follow:
The table shows the number of employees in 5 departments – A, B, C, D and E in a company, the percentage of females in each department and the ratio of number of males who are unmarried to married.
What is the ratio of number of unmarried males in department C to number of married males in department B?
Correct
Explanation:
Unmarried males in department C = (4/9) * (65/100)*360 = 104
Married Males in department B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29Incorrect
Explanation:
Unmarried males in department C = (4/9) * (65/100)*360 = 104
Married Males in department B = (2/3) * (60/100)*290 = 116
104 : 116 = 26 : 29
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