**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

[flipclock]

**Variety A and B of rice were priced at Rs 20 per kg and Rs 30 per kg respectively. They are mixed in the same ratio as their prices and the mixture is sold at Rs 39 per kg. Find the percentage profit made in this transaction.**

A) 34%

B) 25%

C) 50%

D) 52%

E) 45%

**C) 50%**

Explanation:

Let CP of mixture is x

By method of allegation:

A(20kg) B(30 kg)

20 30

. x

(30-x) (x-20)

Then, (30-x)/(x-20) = 20/30

Solve, x = 26

SP = 39

So profit% = [(39-26)/26] * 100

**A TV and a CD player are sold for a total of Rs 24,920 making a profit of 30% on the TV and 20% on the CD player. Had there been a profit of 20% on TV and 30% on CD Player, the total selling price of the two would have been Rs 25,080. Find the total cost price of the TV and the CD player.**

A) Rs 23,000

B) Rs 20,000

C) Rs 24,000

D) Rs 22,000

E) None of these

**B) Rs 20,000**

Explanation:

By a shortcut it can be find as

CP(TV+Player) = [24920+25080]/[(120/100) + (130/100)]**6 men and 8 women can complete a work in 10 days and 8 men and 22 women can complete the same work in 5 days. What is the number of days in which 34 women will complete thrice the same work?**

A) 5 days

B) 10 days

C) 15 days

D) 20 days

E) None of these

**C) 15 days**

Explanation:

6m + 8w = 10 days so 60m + 80w = 1 day

8m + 22w = 5 days so 40m + 110w = 1 day

So 60m + 80w = 40m + 110w . It gives 1m = (3/2) w

6m + 8w = 10, so 6*(3/2)w + 8w = 10, so 17 w do 1 work in 10 days, so 34 w thrice work in (17*10*3)/34**A bag contains 3 white, 4 black and 5 green balls. 2 balls are drawn at random. What is the probability that both balls are different in color?**

A) 47/66

B) 69/120

C) 7/90

D) 13/160

E) 21/66

**A) 47/66**

Explanation:

Case 1: 1 white+1 black

^{3}C_{1}*^{4}C_{1}/^{12}C_{2}

Case 2: 1 white+1 green

^{3}C_{1}*^{5}C_{1}/^{12}C_{2}

Case 3: 1 green+1 black

^{5}C_{1}*^{4}C_{1}/^{12}C_{2}

Add all cases

**Ratio of the age of A to age of B is 2 : 3. The difference in the ages of B and C is 15 and the ratio of the age of A to C is 4 : 9. Find the total of the ages of A, B and C.**

A) 90

B) 95

C) 45

D) 105

E) 100

**B) 95**

Explanation:

B/A = 3/2 and A/C = 4/9

So B : A : C = 3*4 : 2*4 : 2*9 = 6 : 4 : 9

So 9x – 6x = 15, this gives x = 5

So age of A = 4x = 20

Age of B = 6x = 30

Age of C = 9x = 45

** Directions (6-10): Each of the questions below consists of a question and two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question: **

**A total of Rs 24000 is borrowed from A and B. Interest of 6% p.a. is to be paid to A and of 4% p.a. is to be paid to B. How much money was borrowed from each of A and B?**

I. After 1 year the total interest paid was Rs 6200.

II. The interest on one sum was twice that on the other.

A) I only is sufficient

B) II only is sufficient

C) I and II both are required

D) Neither I nor II is sufficient

E) Either I or II is sufficient

**E) Either I or II is sufficient**

Explanation:

From I: x*6/100 + (24000-x)*8/100 = 6200

Individual sums can be calculated.

From II: x*6/100 = 2 [(24000-x)*8/100]

Individual sums can be calculated.

So from both the statements alone, answer can be known.

**In a business started by A, B and C, what is their ratio of investments?**

I. A’s contribution is Rs 5200 and the total investments equal Rs 15000.

II. Ratio of the investments of A to B is 3 : 2 and that of B to C is 5 : 4

A) I only is sufficient

B) II only is sufficient

C) I and II both are required

D) Neither I nor II is sufficient

E) Either I or II is sufficient

**B) II only is sufficient**

Explanation:

From I: A = 5200, B+C = 15000-5200, so B and C’s cannot be known.

From II: A/B = 3/2, and B/C = 5/4

So A : B : C = 3*5 : 2*5 : 2*4, so answer is 15 : 10 : 8

**What is the number of students in class 10 of a school?**

I. The average weight of class 10 is 52 kg.

II. If 2 of the students weighing 48 kg and 52 kg are replaced by the one weighing 40 kg and 42 kg, then the average weight is reduced by 1 kg.

A) I only is sufficient

B) II only is sufficient

C) I and II both are required

D) Neither I nor II is sufficient

E) Either I or II is sufficient

**C) I and II both are required**

Explanation:

From I: Let number of students be x, then total of ages of x students is 52x

From II: new total of the ages is 51x

Then 52x – 51x = 48+52 – (42+50)

**How many days are required to complete a work by 12 men?**

I. The number of days in which 12 women can complete a work is 8 days.

II. The number of days in which 24 women can complete a work is 22 days.

A) I only is sufficient

B) II only is sufficient

C) I and II both are required

D) Neither I nor II is sufficient

E) Either I or II is sufficient

**D) Neither I nor II is sufficient**

Explanation:

Since we are not given any relation between men and women or men and children, from both the statements the answer cannot be found.**What is the cost of flooring the floor of a room?**

I. Length of the room is 10 m and cost of flooring is Rs 600 per 100 m^{2}.

II. Breadth of the room is two-fifth its length.

A) I only is sufficient

B) II only is sufficient

C) I and II both are required

D) Neither I nor II is sufficient

E) Either I or II is sufficient

**C) I and II both are required**

Explanation:

From I: l = 10m. For 100 m^{2}, cost is 600 so for 1 m^{2}, cost is 600/100 = Rs 6

From II: b = (2/5)*10 = 4 m

Area = 10*4 = 40 m^{2}, so cost of flooring = 40*6

**AffairsCloud Recommends Oliveboard Test**

**AffairsCloud Ebook - Support Us to Grow**

**Govt Jobs by Category**

**Bank Jobs Notification**