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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

The price of a bike is Rs. 4,50,000. It was insured to 70% of its price. The bike was damaged completely in an accident and the insurance company paid 80% of the insurance. What was the difference between the price of the bike and the amount received?

The ratio of the number of boys and girls in a school is 3:7. If 10% of the boys and 20% of the girls are scholarship holders, the percentage of the students who are not scholarship holders is

Correct

Answer – 4. 83%
Explanation:
Consider Total no of students = 100
Ratio is 3:7 i.e Boys=30 and Girls=70
10% of boys who get scholarship = 30*10/100 = 3%
20% of girls who get scholarship = 70*20/100 =14%
Therefore % of students who do not get scholarship =100-(3+14) = 83%

Incorrect

Answer – 4. 83%
Explanation:
Consider Total no of students = 100
Ratio is 3:7 i.e Boys=30 and Girls=70
10% of boys who get scholarship = 30*10/100 = 3%
20% of girls who get scholarship = 70*20/100 =14%
Therefore % of students who do not get scholarship =100-(3+14) = 83%

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Ajay went to buy a Sony TV, the shopkeeper told him to pay 20% tax if he asked the bill. Ajay manages to get the discount of 5% on the actual sale price of the TV and he paid the shopkeeper Rs. 8740 without tax. Besides he manages to avoid to pay 20% tax on the already discounted price, what is the amount of discount?

Vignesh lends Rs 30,000 of two of his friends. He gives Rs 15,000 to the first friend Pradeep at 6% p.a. simple interest. He wants to make a profit of 20% on the whole. The simple interest rate at which he should lend the remaining sum of money to the second friend, Suresh is

Correct

Answer – 4. 34%
Explanation:
S.I. on Rs 15000
=(15000×6×1)/100 = Rs. 900
Profit to made on Rs 30000
= 30000×20/100=Rs 6000
S.I.on Rs.15000 = 6000-900 = Rs.5100
Rate=(S.I.* 100)/(P * T)=(5100×100)/15000
=34% per annum

Incorrect

Answer – 4. 34%
Explanation:
S.I. on Rs 15000
=(15000×6×1)/100 = Rs. 900
Profit to made on Rs 30000
= 30000×20/100=Rs 6000
S.I.on Rs.15000 = 6000-900 = Rs.5100
Rate=(S.I.* 100)/(P * T)=(5100×100)/15000
=34% per annum

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

The compound interest on a certain amount for 2 years is Rs. 105 and S.I. is Rs. 100. If the amount is invested such that the S.I. is Rs. 625 and the number of
years is equal to the rate per cent per annum, Find the rate of interest?

Correct

Answer – 2.5%
Explanation :
CI for 2 years = Rs. 105
SI for 2 years = Rs. 100
P = 500
P*x*x/100 = 625
x = 5%

Incorrect

Answer – 2.5%
Explanation :
CI for 2 years = Rs. 105
SI for 2 years = Rs. 100
P = 500
P*x*x/100 = 625
x = 5%

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

Kajol can do a work in 25 days, while Rajesh can do the same work in 50 days. They started the work jointly. Few days later Suresh also joined them and thus all of them completed the whole work in 10 days. All of them were paid total Rs.5000. What is the Share of Suresh?

Correct

Answer – 3. Rs.2000
Explanation :
Efficiency of Kajol = 4%
Efficiency of Rajesh = 2%
[(4+2)*10] = 60%
The remaining work done by Suresh = 40%.
40% of 5000 = 2000

Incorrect

Answer – 3. Rs.2000
Explanation :
Efficiency of Kajol = 4%
Efficiency of Rajesh = 2%
[(4+2)*10] = 60%
The remaining work done by Suresh = 40%.
40% of 5000 = 2000

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

Two places X and Y are 1200 km apart from each other. Two persons start from X towards Y at an interval of 2 hours. Whereas A leaves X for Y before B. The speeds of A and B are 30 kmph and 40 kmph respectively. B overtakes A at M, which is on the way from X to Y. What is the extra time taken by A to reach at Y?

Correct

Answer – 4. 10 hours
Explanation :
Time taken by A to reach at Y = 1200/30 = 40 hours
Time taken by B to reach at Y = 1200/60 = 30 hours
A takes 10 hours extra time to reach at Y.

Incorrect

Answer – 4. 10 hours
Explanation :
Time taken by A to reach at Y = 1200/30 = 40 hours
Time taken by B to reach at Y = 1200/60 = 30 hours
A takes 10 hours extra time to reach at Y.

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A boat travels upstream from Q to P and downstream from P to Q in 9 hours. If the speed of the boat in still water is 9 kmph and the speed of the current is 3 kmph the distance between P and Q is?

Correct

Answer – 2. 36 km
Explanation :
Speed downstream = (9 + 3) kmph = 12 kmph
Speed upstream = = (9 – 3) km/hr = 6km/hr
Let the distance PQ= d km
Then, d/6 + d/12 = 9
⇒ 2d + d = 108
⇒ d = 36
Distance AB = 36 km

Incorrect

Answer – 2. 36 km
Explanation :
Speed downstream = (9 + 3) kmph = 12 kmph
Speed upstream = = (9 – 3) km/hr = 6km/hr
Let the distance PQ= d km
Then, d/6 + d/12 = 9
⇒ 2d + d = 108
⇒ d = 36
Distance AB = 36 km

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

If a pipe L can fill a tank 3 times faster than pipe M and takes 64 minutes less than pipe M to fill the tank. If both the pipes are opened simultaneously, then find the time taken to fill the tank?

Correct

Answer – 1. 24 minutes
Explanation :
3x – x = 64
x = 32
1/32 + 1/96 = 4/96
Time taken to fill the tank = 96/4 = 24 minutes

Incorrect

Answer – 1. 24 minutes
Explanation :
3x – x = 64
x = 32
1/32 + 1/96 = 4/96
Time taken to fill the tank = 96/4 = 24 minutes

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The length of train is equal to the length of the platform. Suppose the train is running at a speed of 72 km/hr and it crosses a platform in 2 minutes. What is then the length of the train?

Correct

Answer – 3. 1200 m
Speed in m/sec = 72 km/hr x (5/18) = 20 m/s
Time taken by train to cross the platform = 2 min = 120 s
The distance covered by train when crossing the platform = 20 m/s x 120 s = 2400 m
Distance covered by train when crossing the platform = Length of train + Length of Platform
Length of train = Length of Platform = x
2x = 2400
x = Length of train = 1200

Incorrect

Answer – 3. 1200 m
Speed in m/sec = 72 km/hr x (5/18) = 20 m/s
Time taken by train to cross the platform = 2 min = 120 s
The distance covered by train when crossing the platform = 20 m/s x 120 s = 2400 m
Distance covered by train when crossing the platform = Length of train + Length of Platform
Length of train = Length of Platform = x
2x = 2400
x = Length of train = 1200

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