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Question 1 of 10
1. Question
1 pointsDirection: Q(15)
The following graph represents the split up of clients for a software company.(in degree).Total clients=720
A:Banking B:Insurance C :Education D :Consumer DurablesE: Media and Entertainment F :Automobile G:Pharmaceutical
H:Textile I: Infrastructure
The following table represents the revenue from different clients depending upon whether the projects were implanted inhouse or were outsourced.
Client No of Projects Revenue(Rs Million) Inhouse Outsourced Inhouse Outsourced A 100 200 80 70 B 80 40 120 60 C 60 0 60 0 D 0 30 0 75 E 30 0 90 0 F 60 30 90 60 G 30 30 60 120 H 45 15 45 30 I 90 30 60 60 For how many industries is the revenue generated per project by the software firm by outsourcing the projects of that industry more than that generated by implementing inhouse the projects of that industry, but at the same time, the number of inhouse projects of that industry is more than that of the outsourced projects of that industry? Consider only those industries where the projects are both outsourced and implemented inhouse.
Correct
Explanation:
The following are the possible cases, where revenue for the project from outsourcing
is greater than that generated by inhouse per project but, the number of inhouse
projects is more than that of outsourcing.
F:60/30>90/60 but 60>30
H:30/ 15>45/45 but 45>15
I:60 /30>60/90 but 90>60Incorrect
Explanation:
The following are the possible cases, where revenue for the project from outsourcing
is greater than that generated by inhouse per project but, the number of inhouse
projects is more than that of outsourcing.
F:60/30>90/60 but 60>30
H:30/ 15>45/45 but 45>15
I:60 /30>60/90 but 90>60 
Question 2 of 10
2. Question
1 pointsDirection: Q(15)
The following graph represents the split up of clients for a software company.(in degree).Total clients=720
A:Banking B:Insurance C :Education D :Consumer DurablesE: Media and Entertainment F :Automobile G:Pharmaceutical
H:Textile I: Infrastructure
The following table represents the revenue from different clients depending upon whether the projects were implanted inhouse or were outsourced.
Client No of Projects Revenue(Rs Million) Inhouse Outsourced Inhouse Outsourced A 100 200 80 70 B 80 40 120 60 C 60 0 60 0 D 0 30 0 75 E 30 0 90 0 F 60 30 90 60 G 30 30 60 120 H 45 15 45 30 I 90 30 60 60 If for any industry,the number of projects from a particular industry is more than the number of clients from it then what is the average revenue generated (in millions) per client by the software firm from that industry?
Correct
Explanation:
For banking industry only this condition is fulfilled where number of clients=75/360*720=150
But total projects=300
Average revenue =150/150=1 million RsIncorrect
Explanation:
For banking industry only this condition is fulfilled where number of clients=75/360*720=150
But total projects=300
Average revenue =150/150=1 million Rs 
Question 3 of 10
3. Question
1 pointsDirection: Q(15)
The following graph represents the split up of clients for a software company.(in degree).Total clients=720
A:Banking B:Insurance C :Education D :Consumer DurablesE: Media and Entertainment F :Automobile G:Pharmaceutical
H:Textile I: Infrastructure
The following table represents the revenue from different clients depending upon whether the projects were implanted inhouse or were outsourced.
Client No of Projects Revenue(Rs Million) Inhouse Outsourced Inhouse Outsourced A 100 200 80 70 B 80 40 120 60 C 60 0 60 0 D 0 30 0 75 E 30 0 90 0 F 60 30 90 60 G 30 30 60 120 H 45 15 45 30 I 90 30 60 60 From which client is the difference in revenue per project, from inhouse or outsourced projects, the highest?
Correct
Explanation:
Revenue from outsource for G=120/30=4
Revenue from inhouse=60/30=2
Difference=42=2Incorrect
Explanation:
Revenue from outsource for G=120/30=4
Revenue from inhouse=60/30=2
Difference=42=2 
Question 4 of 10
4. Question
1 pointsDirection: Q(15)
The following graph represents the split up of clients for a software company.(in degree).Total clients=720
A:Banking B:Insurance C :Education D :Consumer DurablesE: Media and Entertainment F :Automobile G:Pharmaceutical
H:Textile I: Infrastructure
The following table represents the revenue from different clients depending upon whether the projects were implanted inhouse or were outsourced.
Client No of Projects Revenue(Rs Million) Inhouse Outsourced Inhouse Outsourced A 100 200 80 70 B 80 40 120 60 C 60 0 60 0 D 0 30 0 75 E 30 0 90 0 F 60 30 90 60 G 30 30 60 120 H 45 15 45 30 I 90 30 60 60 The revenue generated by the software firm from outsourced projects of the automobile industry is what percentage more or less than the revenue generated by the firm from the inhouse projects of the insurance industry?
Correct
Explanation:
Revenue of automobile from outsourcing=60 million
Revenue of insurance from inhouse=120 million
Percentage=(12060/120)*100=50%Incorrect
Explanation:
Revenue of automobile from outsourcing=60 million
Revenue of insurance from inhouse=120 million
Percentage=(12060/120)*100=50% 
Question 5 of 10
5. Question
1 pointsDirection: Q(15)
The following graph represents the split up of clients for a software company.(in degree).Total clients=720
A:Banking B:Insurance C :Education D :Consumer DurablesE: Media and Entertainment F :Automobile G:Pharmaceutical
H:Textile I: Infrastructure
The following table represents the revenue from different clients depending upon whether the projects were implanted inhouse or were outsourced.
Client No of Projects Revenue(Rs Million) Inhouse Outsourced Inhouse Outsourced A 100 200 80 70 B 80 40 120 60 C 60 0 60 0 D 0 30 0 75 E 30 0 90 0 F 60 30 90 60 G 30 30 60 120 H 45 15 45 30 I 90 30 60 60 If the number of projects for textile and education industry gets exchanged whereas revenue remains same then what is the ratio of revenue per project from education to infrastructure industry?
Correct
Explanation:
Number of projects for education =60
Revenue =60 million Rs
Number of projects for infrastructure=120
Revenue=120 million Rs
Ratio=(60/60)/(120/120)=1:1Incorrect
Explanation:
Number of projects for education =60
Revenue =60 million Rs
Number of projects for infrastructure=120
Revenue=120 million Rs
Ratio=(60/60)/(120/120)=1:1 
Question 6 of 10
6. Question
1 pointsVessels A and B contain mixtures of milk and water. The milk concentrations of the mixture in A and in B are a% and b% respectively. When a% of the contents of A are mixed with (100 – b)% of the contents of B or when b% of the contents of B are mixed with (100 – a)% of the contents of A, the milk concentrations in the resulting mixtures are equal. If A and B have a litres and b litres of the mixture respectively and a ≠ b, find a + b.
Correct
Explanation:
Let milk concentration in each of resulting mixture be r%
Now applying allegation:
(a*a)/100/(100b)/100=ra/rb
On solving: ab(100^{2}100a100b)=0
Therefore either ab=0 or a+b=100Incorrect
Explanation:
Let milk concentration in each of resulting mixture be r%
Now applying allegation:
(a*a)/100/(100b)/100=ra/rb
On solving: ab(100^{2}100a100b)=0
Therefore either ab=0 or a+b=100 
Question 7 of 10
7. Question
1 pointsTwo men started simultaneously from town P and town Q towards Q and P respectively. On reaching their destinations, each of them turned back and without changing their speeds, walked towards their starting points. The two men met at a distance of 23 km from P, for the first time and at a distance of 11 km from Q, for the second time (after both had turned back and were returning to their starting points). Find the distance PQ.
Correct
Explanation:
Let the two men be A and B respectively and let their speeds be x km/hr and y km/hr
respectively_ Let PQ= d km.
When the two met for the first time, A would have covered 23 km and B would have
covered (d — 23) km.
therefore x/y=23/d23
When they met for the second time, A have covered (d + 11) km and B would have
covered 2d — 11 km.
therefore x/y=d+11/2d11
on equating
23/d23=d+11/2d11
d(d58)=0
therefore d=58Incorrect
Explanation:
Let the two men be A and B respectively and let their speeds be x km/hr and y km/hr
respectively_ Let PQ= d km.
When the two met for the first time, A would have covered 23 km and B would have
covered (d — 23) km.
therefore x/y=23/d23
When they met for the second time, A have covered (d + 11) km and B would have
covered 2d — 11 km.
therefore x/y=d+11/2d11
on equating
23/d23=d+11/2d11
d(d58)=0
therefore d=58 
Question 8 of 10
8. Question
1 pointsAman invests a total of 40000 in two schemes – A and B, both of which offer interests which are compounded annually. A offers 60% p.a. and B offers 20% p.a. If after 2 years the values of the two investments are in the ratio 8 : 3, what was the initial ratio of the investments made in B and A?
Correct
Explanation:
Let investment in a and b be x and y
Therefore x+y=40000
Y(1.44)/x(2.56)=3/8
On solving y/x=2/3Incorrect
Explanation:
Let investment in a and b be x and y
Therefore x+y=40000
Y(1.44)/x(2.56)=3/8
On solving y/x=2/3 
Question 9 of 10
9. Question
1 pointsPipes X, Y and Z are fitted to a tank. X can fill the tank in twice the time taken by all the 3 pipes to fill the tank. Y can fill the tank in 12 hours less than 4 times the time taken by all the 3 pipes to fill the tank. Z can fill the tank in 12 hours less than 7 times the time taken by all the 3 pipes to fill the tank. Which pipe takes the least time to fill the tank?
Correct
Explanation:
Let time taken by all the 3 pipes together=a hours. Time taken by X=2a hours,time taken by Y=4a12 hours,time taken by Z=7a12 hours
1/a=1/2a+1/(4a12)+1/(7a12)
On solving (a12)(a2)=0
A=12,2
A has to be 12 as time taken by all pipes is positive
A=12,time taken by X=24,Y=36,Z=72Incorrect
Explanation:
Let time taken by all the 3 pipes together=a hours. Time taken by X=2a hours,time taken by Y=4a12 hours,time taken by Z=7a12 hours
1/a=1/2a+1/(4a12)+1/(7a12)
On solving (a12)(a2)=0
A=12,2
A has to be 12 as time taken by all pipes is positive
A=12,time taken by X=24,Y=36,Z=72 
Question 10 of 10
10. Question
1 pointsThe owner of a shop increases the price of an article by x% and then decreases it by x%. As a result the price of the article falls by Rs.180. After one more such iteration the price falls by further Rs.160. Find the original price (in Rs.) of the article.
Correct
Explanation:
Let P be the original price and let y% be the net decreased after increasing the price
by x% and then decreasing by x%
Given y%(P)= 180
y%(P – 180)= 160
On solving P=1620 Rs.Incorrect
Explanation:
Let P be the original price and let y% be the net decreased after increasing the price
by x% and then decreasing by x%
Given y%(P)= 180
y%(P – 180)= 160
On solving P=1620 Rs.
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