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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): study the following information carefully and answer the questions given below:
What is the ratio of the total number of male students learning Japanese Language in school L and O together to the total number of female students learning Japanese Language in the same schools together?
Correct
Answer – 2. 31:38
Explanation:
Required ratio = Japanese Language (L + O) males / Japanese Language (L + O) females
= [450 × (30/100) × (7/15)] + [400 × (18/100) × (5/12)] / [450 × (30/100) × (8/15)] + [400 × (18/100) × (7/12)]
= (63+30)/(72+42) = 93/114 = 31/38 = 31 : 38Incorrect
Answer – 2. 31:38
Explanation:
Required ratio = Japanese Language (L + O) males / Japanese Language (L + O) females
= [450 × (30/100) × (7/15)] + [400 × (18/100) × (5/12)] / [450 × (30/100) × (8/15)] + [400 × (18/100) × (7/12)]
= (63+30)/(72+42) = 93/114 = 31/38 = 31 : 38 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): study the following information carefully and answer the questions given below:
In school M, out of the total number of students (both male and female) learning Japanese Language, 1/19 are below 15 years of age. If out of the total students who are below 15 years of age, 50% are females, then what is the number of female students learning Japanese Language Who are 15 years or above?
Correct
Answer – 5. 38
Explanation:
Total number of students who are learning Japanese Language in School M 200 x (38/100) = 76
Number of male students who are learning Japanese Language = 76 x (9/19) = 36 19
Number of female students who are learning Japanese Language = 76 x (10/19) = 40
Both males and females below 15 years = 76 × (1/19) = 4
Number of females below 15 years = 4 × (50/100) = 2
Number of female students learning Japanese Language who are 15 years or above = 40 – 2 = 38Incorrect
Answer – 5. 38
Explanation:
Total number of students who are learning Japanese Language in School M 200 x (38/100) = 76
Number of male students who are learning Japanese Language = 76 x (9/19) = 36 19
Number of female students who are learning Japanese Language = 76 x (10/19) = 40
Both males and females below 15 years = 76 × (1/19) = 4
Number of females below 15 years = 4 × (50/100) = 2
Number of female students learning Japanese Language who are 15 years or above = 40 – 2 = 38 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): study the following information carefully and answer the questions given below:
What is the difference between the total number of male students learning Japanese Language in schools M and N together and the total number of female students learning the same language in the same schools together?
Correct
Answer – 2. 74
Explanation:
Total number of male students learning Japanese Language in school M and N together
= 200 × (38/100) × (9/19) + 500 × (24/100) × (5/24)
= 36 + 25 = 61
Total number of female students learning Japanese Language in school M and N together
= 200 × (38/100) × (10/19) + 500 × (24/100) × (19/24)
= 40 + 95 = 135
Required difference = 135 — 61 = 74Incorrect
Answer – 2. 74
Explanation:
Total number of male students learning Japanese Language in school M and N together
= 200 × (38/100) × (9/19) + 500 × (24/100) × (5/24)
= 36 + 25 = 61
Total number of female students learning Japanese Language in school M and N together
= 200 × (38/100) × (10/19) + 500 × (24/100) × (19/24)
= 40 + 95 = 135
Required difference = 135 — 61 = 74 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections (Q. 1 – 5): study the following information carefully and answer the questions given below:
What is the average number of students learning Languages(other than Japanese Language) in school L, M and N?
Correct
Answer – 5. 273
Explanation:
Average =[ 450 × (70/100) + 200 × (62/100) + (500 × 76) /100] / 3
= (315+124+380) / 3 = 819/3 = 273Incorrect
Answer – 5. 273
Explanation:
Average =[ 450 × (70/100) + 200 × (62/100) + (500 × 76) /100] / 3
= (315+124+380) / 3 = 819/3 = 273 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe number of students(both male and female) who are learning Japanese Language in school M and O together is approximately what percent less than the number of students (both male and female) who are learning the same Language in school L and N together?
Correct
Answer – 2. 42
Explanation:
The number of students (both male and female) who are learning Japanese Language in School M and O together = 200 x (38/100) + 400 × (18/100) = 76 + 72 = 148
The number of students (both males and females) who are learning Japanese Language in School L and N together
= 450 × (30/100) + (500 × 24)/100 = 135 + 120 = 255
Difference = 255 148 = 107
Required %=(107/255) × 100 = 42Incorrect
Answer – 2. 42
Explanation:
The number of students (both male and female) who are learning Japanese Language in School M and O together = 200 x (38/100) + 400 × (18/100) = 76 + 72 = 148
The number of students (both males and females) who are learning Japanese Language in School L and N together
= 450 × (30/100) + (500 × 24)/100 = 135 + 120 = 255
Difference = 255 148 = 107
Required %=(107/255) × 100 = 42 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative Aptitude82, 81, 85, 76, 92, ?
Correct
Answer – 2. 67
Explanation:
821 = 81
81+4 = 85
859 = 76
76+16 = 92
9225 = 67Incorrect
Answer – 2. 67
Explanation:
821 = 81
81+4 = 85
859 = 76
76+16 = 92
9225 = 67 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative Aptitude424, 379, 339, 304, 274, ?
Correct
Answer – 1. 249
Explanation:
42445 = 379
37940 = 339
33935 = 304
30430 = 274
27425 = 249Incorrect
Answer – 1. 249
Explanation:
42445 = 379
37940 = 339
33935 = 304
30430 = 274
27425 = 249 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeRohini invested Rs. X for 2 years in scheme P which offered 11% p.a. SI. She also invested Rs. 600 + X in scheme Q which offered 20% CI (compounded annually), for 2 years. If the amount received from scheme P was less than that received from scheme Q, by Rs. 1216 then what is the value of X?
Correct
Answer – 4. Rs. 1,600
Explanation:
Money Invested=X at 11% Simple interest.
X+600 At 20% C.I.
1.22X+1216=1.44(X+600)
Or 0.22X= 352
Hence X=1600Incorrect
Answer – 4. Rs. 1,600
Explanation:
Money Invested=X at 11% Simple interest.
X+600 At 20% C.I.
1.22X+1216=1.44(X+600)
Or 0.22X= 352
Hence X=1600 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeThe Percent profit earned when a bangle is sold for Rs. 546/ is double the percent profit earned when the same bangle is sold for Rs. 483/. If the marked price of the bangle is 40% above the cost price then, what is the marked price of the bangle?
Correct
Answer – 1. Rs. 588
Explanation
Let the profit be y and C.P.= x
x+2y=546 –(1)
x+y=483 –(2)
From (1) and (2)
y=63
x=48363=420
M.P.= 1.4*420=588Incorrect
Answer – 1. Rs. 588
Explanation
Let the profit be y and C.P.= x
x+2y=546 –(1)
x+y=483 –(2)
From (1) and (2)
y=63
x=48363=420
M.P.= 1.4*420=588 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeSuresh went downstream for 28 km in a water craft and immediately returned. It took him twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. What is the speed of the water craft in still water and the speed of the river flow?
Correct
Answer – 2. 9 kmph, 3 kmph
Explanation:
The speed of the water craft = a kmph
The speed of the river = b kmph
From the given data,
2 x [28/a + b]= 28/a − b
=> 56a – 56b 28a – 28b = 0
=> 28a = 84b
=> a = 3b.
28/3b + 2b + 28/3b − 2b = 672/60
=> 28/5b + 28/b = 672/60=> b = 3 kmph=> x =3b = 9 kmphIncorrect
Answer – 2. 9 kmph, 3 kmph
Explanation:
The speed of the water craft = a kmph
The speed of the river = b kmph
From the given data,
2 x [28/a + b]= 28/a − b
=> 56a – 56b 28a – 28b = 0
=> 28a = 84b
=> a = 3b.
28/3b + 2b + 28/3b − 2b = 672/60
=> 28/5b + 28/b = 672/60=> b = 3 kmph=> x =3b = 9 kmph
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