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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Boat P travels upstream from point L to point M in 3 hours more than the time taken by Boat Q to travel downstream from point N to point M. The distance between L and M is 40 km and the distance between M and N is 24 km. The speed of Boat P in still water is equal to the speed of Boat Q in downstream. What is the speed of Boat P in still water?

Correct

Answer – 4. 24 kmph
Explanation:
Let the speed of the current = X kmph
Speed of boat Q in still water =10 kmph
Speed of boat Q in downstream =X+10
Speed of boat P in still water = X+10
Speed of boat P in upstream = X+10-X=10 kmph
(40/10)- 24/(10+X) = 3
X=14
So speed of boat P in still water =10 + 14 = 24 kmph

Incorrect

Answer – 4. 24 kmph
Explanation:
Let the speed of the current = X kmph
Speed of boat Q in still water =10 kmph
Speed of boat Q in downstream =X+10
Speed of boat P in still water = X+10
Speed of boat P in upstream = X+10-X=10 kmph
(40/10)- 24/(10+X) = 3
X=14
So speed of boat P in still water =10 + 14 = 24 kmph

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

The cost price of two shirts are the same. A seller got a profit of 50% on the first shirt, and the selling price of second shirt is 20% less than the cost price of the first shirt. Find the overall profit percentage.

Mano, Naveen and Sharma, each working alone, can finish a work in 84 days, 56 days and 96 days respectively. Mano worked along for 23 days and then Naveen took over from Mano, Naveen worked only for 24 days and then Sharma took over from Naveen. In how many days will Sharma finish the remaining work?

Correct

Answer – 3. 28(4/7)
Explanation:
Total work = 84,56 and 96=672 units
Now Mano can work in one days =672/84=8 units, similarly Naveen =12 units, Sharma = 7 units
Total work done = 23 *8 + 24 *12 = 184 +288= 472 units
Remaining work =672-472=200 units
Time taken by Sharma =200/7 =28(4/7) days

Incorrect

Answer – 3. 28(4/7)
Explanation:
Total work = 84,56 and 96=672 units
Now Mano can work in one days =672/84=8 units, similarly Naveen =12 units, Sharma = 7 units
Total work done = 23 *8 + 24 *12 = 184 +288= 472 units
Remaining work =672-472=200 units
Time taken by Sharma =200/7 =28(4/7) days

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Two schemes are announced on the sale of Basic Feature Phones costing Rs 1400. Scheme P offers discount of 25% and 10% successively during reduction and festival scheme Q offers 30% and 5% successively. What is the difference in the selling price in the two schemes?

An Express, which is 480 m long, can cross a pole in 16 seconds. If it halts 5 times, each time for exactly 24 minutes, how many hours will it take to cover a distance of 864 km?(in hours)

Correct

Answer – 4. 10 hours
Explanation:
Speed of train 480 /16=30 m/sec =108 kmph
Total time taken to cover 864 km = 864/108 = 8 hours
Total halt time =5*24 = 120 min
Total time taken = 8 + 2 = 10 hours

Incorrect

Answer – 4. 10 hours
Explanation:
Speed of train 480 /16=30 m/sec =108 kmph
Total time taken to cover 864 km = 864/108 = 8 hours
Total halt time =5*24 = 120 min
Total time taken = 8 + 2 = 10 hours

Question 6 of 10

6. Question

1 points

Category: Quantitative Aptitude

The ratio of the speed of two bikes P & Q is 5 : 9. If P takes 480 minutes more than Q to cover a certain distance, then find the actual time taken by Q to cover the same distance

Correct

Answer – 4. 10 hours
Explanation :
Ratio of speed = 5 : 9
So ratio of time = 9 : 5
Now 9-5= 480 min
So 5 = 600 min = 10 hours

Incorrect

Answer – 4. 10 hours
Explanation :
Ratio of speed = 5 : 9
So ratio of time = 9 : 5
Now 9-5= 480 min
So 5 = 600 min = 10 hours

Question 7 of 10

7. Question

1 points

Category: Quantitative Aptitude

A vessel contains a mixture of Solution “A” and water in the respective ratio of 3:1. 32 litre of mixture was taken out and replaced with the same quantity of Solution “A” so that the resultant ratio between the quantities of Solution “A” and water in the mixture was 4:1 respectively, If 10 litre of mixture is again taken out from the vessel,what is the resultant quantity of water in the mixture?(in litre)

Correct

Answer – 2. 30
Explanation :
Let the total quantity of mixture =X litre
4/(4+1)= (X-32)/X
X=160 litre
The quantity of Solution “A” in mixture = 160 *(3/4)=120 litre
The quantity of water in mixture =160 * (1/4)=40 litre
32 litre of mixture was taken out and replaced with the
Same quantity of Solution “A”
Then, the quantity of Solution “A” in mixture
=120- 32*(3/4)+32
=128 litre
The quantity of water in mixture =40 -32 *(1/4)=32 litre
New ratio of Solution “A” and water =128 : 32=4:1
After 10 litre of mixture is again taken out from the vessel,
The resultant quantity of water in the mixture
=32-(10*1/5)=30 litre

Incorrect

Answer – 2. 30
Explanation :
Let the total quantity of mixture =X litre
4/(4+1)= (X-32)/X
X=160 litre
The quantity of Solution “A” in mixture = 160 *(3/4)=120 litre
The quantity of water in mixture =160 * (1/4)=40 litre
32 litre of mixture was taken out and replaced with the
Same quantity of Solution “A”
Then, the quantity of Solution “A” in mixture
=120- 32*(3/4)+32
=128 litre
The quantity of water in mixture =40 -32 *(1/4)=32 litre
New ratio of Solution “A” and water =128 : 32=4:1
After 10 litre of mixture is again taken out from the vessel,
The resultant quantity of water in the mixture
=32-(10*1/5)=30 litre

Question 8 of 10

8. Question

1 points

Category: Quantitative Aptitude

A cistern has one inlet, P and one inlet, Q. P takes 5 hours to fill the empty tank, when Q is not open and Q takes 7 hours to empty the full tank, if the tank is three fifth full, how much time will it take to fill the tank completely when both P and Q are opened simultaneously?(in hours)

Correct

Answer – 5. 7 hours
Explanation:
If the tank is 3/5th full, then remaining empty tank will be = 1-3/5=2/5 th
P and Q can fill the empty tank in = (5*7)/(7-5)=35/2 hours
Then 2/5 th tank fill in = 35/2 * ⅖ = 7 hours

Incorrect

Answer – 5. 7 hours
Explanation:
If the tank is 3/5th full, then remaining empty tank will be = 1-3/5=2/5 th
P and Q can fill the empty tank in = (5*7)/(7-5)=35/2 hours
Then 2/5 th tank fill in = 35/2 * ⅖ = 7 hours

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

Rajesh invested a certain amount in Fund “X” and Fund “Y” in the ratio of 4:5 respectively. At the end of one year, he earned a total dividend of 30% on his investment. After one year he reinvested the amount including dividend in the ratio of 6:7 in Fund “X” and Fund “Y”. If the amount reinvested in Fund “Y” was Rs 94500, what was the original amount invested in Fund “X”?

Correct

Answer – 3. 60000
Let the common ratio be X
The amount invested in Fund “X” =4X
The amount invested in Fund “Y” =5X
After one year, Mr Rajesh’s total amount
= 9X * 130/100 = 11.7X
Amount reinvested in Fund “Y” = 11.7 X * (7/13)
11.7 X * (7/13)=94500
X=15000
The original amount invested in Fund “X” = 4 * 15000 = 60000

Incorrect

Answer – 3. 60000
Let the common ratio be X
The amount invested in Fund “X” =4X
The amount invested in Fund “Y” =5X
After one year, Mr Rajesh’s total amount
= 9X * 130/100 = 11.7X
Amount reinvested in Fund “Y” = 11.7 X * (7/13)
11.7 X * (7/13)=94500
X=15000
The original amount invested in Fund “X” = 4 * 15000 = 60000

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

The area of a rectangle is 4 times of the area of a square. The length of the rectangle is 160 cm and the breadth of the rectangle is 3/4 th of the side of the square. What is the side of the square?

Correct

Answer – 1. 30 cm
Explanation:
Side of the square – x
Breadth of the rectangle = 3/4th of the side of the square = 3/4x
4x^2 = 160 * (¾) x
4x = 160 * (¾)
x = 30

Incorrect

Answer – 1. 30 cm
Explanation:
Side of the square – x
Breadth of the rectangle = 3/4th of the side of the square = 3/4x
4x^2 = 160 * (¾) x
4x = 160 * (¾)
x = 30

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