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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeFind out the wrong number in the series given below
2, 4, 7, 27, 87, 344Correct
Answer – 2) 27
Explanation :
2 + 1² + 1 = 4
4 + 2² – 1 = 7
7 + 4² + 1 = 24
24 + 8² – 1 = 87
87 + 16² + 1 = 344Incorrect
Answer – 2) 27
Explanation :
2 + 1² + 1 = 4
4 + 2² – 1 = 7
7 + 4² + 1 = 24
24 + 8² – 1 = 87
87 + 16² + 1 = 344 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative Aptitude(54679.03 + 5981.9 + 32613.8) – (311.9 * 68.97) = ?
Correct
Answer – 2) 71747
Explanation :
54679 + 5982 + 32614 = 93275
312 * 69 = 21528
93275 – 21528 = 71747Incorrect
Answer – 2) 71747
Explanation :
54679 + 5982 + 32614 = 93275
312 * 69 = 21528
93275 – 21528 = 71747 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative Aptitudex² – 65x + 676 = 0
y² – 25y + 156 = 0
Correct
Answer – 3. X ≥ Y
Explanation:
x² – 65x + 676 = 0
x = 13, 52
y² – 25y + 156 = 0
y = 13, 12Incorrect
Answer – 3. X ≥ Y
Explanation:
x² – 65x + 676 = 0
x = 13, 52
y² – 25y + 156 = 0
y = 13, 12 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe average age of Suresh and Ganesh is 40 years. If Kathir replaces Suresh, the average age becomes 37 years and if Kathir replaces Ganesh, then the average age becomes 43 years. If the average age of Divya and Chitra be half of the average age of Suresh, Ganesh, and Kathir, then the average age of all the five people is?
Correct
Answer – 1) 32
Explanation:
(S+G)/2 = 40; (K+G)/2 = 37; (S+K)/2 =43
S+G+K =120
(D+C)/2 = ½*(S+G+K)/3
D+C =40
(S+G+K+D+C)/5 =32Incorrect
Answer – 1) 32
Explanation:
(S+G)/2 = 40; (K+G)/2 = 37; (S+K)/2 =43
S+G+K =120
(D+C)/2 = ½*(S+G+K)/3
D+C =40
(S+G+K+D+C)/5 =32 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeIn an office there are 40% female employees. 50% of all the male employees are commerce graduate. If there are total 62% employees commerce graduate out of the total 2600 employees, then the no. of female employees who are commerce graduate?
Correct
Answer – 3. 832
Explanation:
total employees = 2600
Number of commerce graduates = 1612
Male commerce graduates = 2600*60/100*50/100 = 780
Female commerce graduates = 1612780 = 832Incorrect
Answer – 3. 832
Explanation:
total employees = 2600
Number of commerce graduates = 1612
Male commerce graduates = 2600*60/100*50/100 = 780
Female commerce graduates = 1612780 = 832 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeThe profit on selling 12 pens is equals selling price of 5 pencils. While the loss on selling 12 pencils equal selling price of 4 pens. Also, profit percentage equals to the loss percentage and cost of a pen is half of the cost of a pencil. What is the ratio of selling price of pens to the selling price of a pencil?
Correct
Answer – 5) 5:2
Explanation:
Let CP of pen be x and SP of pen be y
Then CP of pencil be 2x and SP of pencil be z
pen: profit on 12 pens = SP of 5 pencils
12(yx) = 5z
pencil: loss on 12 pencils = SP of 4 pens
12(2xz) = 4y
Profit percentage is equal to loss percentage
5z/12x = 4y/12*2x
y/z = 5/2Incorrect
Answer – 5) 5:2
Explanation:
Let CP of pen be x and SP of pen be y
Then CP of pencil be 2x and SP of pencil be z
pen: profit on 12 pens = SP of 5 pencils
12(yx) = 5z
pencil: loss on 12 pencils = SP of 4 pens
12(2xz) = 4y
Profit percentage is equal to loss percentage
5z/12x = 4y/12*2x
y/z = 5/2 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeRitesh and Nitesh are two different persons, but when they worked together, they complete it in 20 days. Had Ritesh worked at half of his efficiency and Nitesh at five times of his efficiency it would have taken them to finish the job in 50% of the scheduled time. In how many days Nitesh can complete the job working alone?
Correct
Answer – 5) 60
Explanation:
1/Ritesh + 1/Nitesh = 1/20
1/2Ritesh + 5/Nitesh = 1/10
Solving both equations
Nitesh can complete the work alone in 60 daysIncorrect
Answer – 5) 60
Explanation:
1/Ritesh + 1/Nitesh = 1/20
1/2Ritesh + 5/Nitesh = 1/10
Solving both equations
Nitesh can complete the work alone in 60 days 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeSharmi lends an equal sum of money at the same rate of interest to A and B. The money lends to A becomes twice of the original amount in just four years at simple interest. While Sharmi lends to B for the first two years at compound interest and for the rest two years at simple interest. The difference between the amount of A and B after 4 years is Rs. 2970. What is the amount of money that Sharmi lends to each one?
Correct
Answer – 3) Rs.8640
Explanation:
2x = x + x*4*r/100
R = 25%
For B:
First two years CI
A = x (1+25/100) 2 = 25x/16
Next two years at SI
Interest = 25x/16*25*2/100 = 25x/32
Total amount 4 years = 25x/16+25x/32 = 75x/32
Difference between A and B amounts = 2970
75x/322x =2970
x =8640Incorrect
Answer – 3) Rs.8640
Explanation:
2x = x + x*4*r/100
R = 25%
For B:
First two years CI
A = x (1+25/100) 2 = 25x/16
Next two years at SI
Interest = 25x/16*25*2/100 = 25x/32
Total amount 4 years = 25x/16+25x/32 = 75x/32
Difference between A and B amounts = 2970
75x/322x =2970
x =8640 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA watercraft takes 7 hours more while going back in upstream than in downstream. If the distance between two places is 30 km and the speed of the watercraft in still water is 6.5 kmph, what must be the speed of a watercraft in still water so that it can row downstream 30 km in 4 hours?
Correct
Answer – 4) 4 Kmph
Explanation:
7 = 30(1/6.5R – 1/6.5+R)
R =3.5
S+R = 30/4 =7.5
S =7.53.5 =4Incorrect
Answer – 4) 4 Kmph
Explanation:
7 = 30(1/6.5R – 1/6.5+R)
R =3.5
S+R = 30/4 =7.5
S =7.53.5 =4 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudePrema, Sharmi and Mano are three sisters Prema and Sharmi are twins. The sum of the ages of Prema and Sharmi is same as that of Mano alone. Three years earlier the ratio of age of Prema and Mano was 3:7. What will be the age of Sharmi 4 years hence?
Correct
Answer – 2) 16 years
Explanation:
Prema = Sharmi = x
Mano = 2x
x3/2x3 = 3/7Incorrect
Answer – 2) 16 years
Explanation:
Prema = Sharmi = x
Mano = 2x
x3/2x3 = 3/7
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