**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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** Directions (1-5): Study the following pie-charts carefully to answer the questions that follow:
Percentage of Students in a College, studying in various subjects and the percentage of girls out of these.**

**What is the ratio of the number of boys to girls in Political Science subject?**

A) 3 : 2

B) 3 : 4

C) 4 : 5

D) 2 : 3

E) 3 : 5**B) 3 : 4**

Explanation:

Put on number line

Girls in political science = (30/100) * 1200 = 360

Total students in political science = (35/100) * 1800 = 630

So boys = 630-360 = 270

Ratio = 270 : 360**The number of girls studying Computer is what per cent less than the number of boys studying Computer?**

A) 50%

B) 20%

C) 80%

D) 35%

E) None of these**B)20%**

Explanation:

Girls studying Computer = (10/100)*1200 = 120

Total students in Computer = (15/100)*1800 = 270

So boys = 270-120 = 150

Required % = [(150-120)/150] * 100**Number of boys is minimum in which stream?**

A) Math

B) Biology

C) Law

D) Arts

E) Political Science**B) Law**

Explanation:

We will have to find number of boys in each of the subjects given in options.

In Math = (5/100)*1800 – (2/100)*1200 = 66

In Biology = (13/100)*1800 – (14/100)*1200 = 66

In Law = (20/100)*1800 – (30/100)*1200 = 0

The number cannot be less than 0 in any stream, so need to find any further.**What is the number of boys in Arts stream?**

A) 65

B) 75

C) 68

D) 52

E) 48**E) 48**

Explanation:

(12/100)*1800 – (14/100)*1200 = 48**Number of boys in Political Science stream is what percent of the number of girls in Law?**

A) 70%

B) 68%

C) 72%

D) 75%

E) None of these**D) 75%**

Explanation:

Boys in Political Stream = (35/100)*1800 – (30/100)*1200 = 270

Girls in Law = (30/100)*1200 = 360

So required % = (270/360)*100**A and B together completed half the work in 18 days. B and C completed the remaining work in 12 days. If C can alone complete a work in 36 days, then find the number of days in which A can alone complete the whole work.**

A) 68 days

B) 72 days

C) 90 days

D) 84 days

E) 52 days**B) 72 days**

Explanation:

Given – [(1/A) + (1/B)] * 18 = 1/2

So (1/A) + (1/B) = 1/36

Given – [(1/B) + (1/C)] * 12 = 1/2

So (1/B) + (1/C) = 1/24

Given 1/C = 1/36

So 1/B = (1/24) – (1/36) = 1/72

And thus 1/A = (1/36) – (1/72) = 1/72**A sum of Rs 7.75 made up to 100 coins, which are in the denomination of 5 paise and 10 paise. Find the number of 5 paise coins.**

A) 75

B) 50

C) 55

D) 45

E) None of these**D) 45**

Explanation:

x + y = 100

(5/100)*x + (10/100)*x = 7.75

Solve both equations and find x.**The time taken by a boat to go 2 km against the stream is 1 hour and to go 1 km along the stream is 10 minutes. What is the time taken by boat to go 5 km in stationary water?**

A) 1 h

B) 1 h 25 min

C) 1 h 15 min

D) 1 h 45 min

E) 1 h 30 min**C) 1 h 15 min**

Explanation:

Downstream speed = 1/ (10/60) = 6 km/hr

Upstream speed = 2/1 = 2 km/hr

So speed in still water = (1/2)*(6+2) = 4 km/hr

So time = 5/4**Four friends – A, B, C and D started a business and their investments were in the ratio 3 : 4: 5: 6. B and C are working partners and they get equal salaries. The ratio of the total annual salary of B and C was 9 : 10. If the total annual profit was Rs 84,000, find B’s salary.**

A) Rs 8,000

B) Rs 18,000

C) Rs 12,000

D) Rs 15,000

E) Rs 20,000**D) Rs 15,000**

Explanation:

Let B’s salary = C’s salary = Rs x

Then profit after their salary given = 84000 – 2x

So B must get x + [4/(3+4+5+6)] * (84000-2x) and C must get x + [5/(3+4+5+6)] * (84000-2x)

Their both ratio is 9 : 10.

So

[x + (4/18)* (84000-2x)] / [x + (5/18)* (84000-2x)] = 9/10

Solve, x = 15000**In winters demand for ACs went down so a dealer sold an AC at 25% loss, but in summers when the demand went up, he sold the AC at 20% profit. If the difference in the amounts that he got is Rs 6750, find the cost price of an AC.**

A) Rs 18,000

B) Rs 10,500

C) Rs 15,000

D) Rs 17,500

E) Rs 12,500**C) Rs 15,000**

Explanation:

CP is x

(120/100)*x – (75/100)*x = 6750

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