**Hello Aspirants,**

Welcome to Online Quant Section in AffairsCloud.com. We are starting **IBPS Clerk course 2015 **and we are creating sample questions in **Quantitative Aptitude** section, type of which will be asked in IBPS Clerk Main Exam.

**Stratus – IBPS Clerk Course 2015 **

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**2x**^{2}+ 3x – 35 = 0, 2y^{2}– 3y – 9 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**E) x = y or relationship cannot be determined**

Explanation:

2x^{2}+ 3x – 35 = 0

2x^{2}+ 10x – 7x – 35 = 0

Gives x = -5, 7/2

2y^{2}– 3y – 9 = 0

2y^{2}– 6y + 3y – 9 = 0

Gives y = -3/2 3

Put on number line

-5 -3/2 3 7/2**3x**^{2}+ 10x + 7 = 0, 2y^{2}– 5y = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**B) x < y**

Explanation:

3x^{2}+ 10x + 7 = 0

3x^{2}+ 3x + 7x + 7 = 0

Gives x = -7/3, -1

2y^{2}– 5y = 0

y(2y-5) = 0

gives y = 0, 5/2

put on number line

-7/3 -1 0 5/2**3x**^{2}– 7x – 20 = 0, 6y^{2}+ 31y + 35 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**C) x ≥ y**

Explanation:

3x^{2}–7x – 20 = 0

3x^{2}– 12x + 5x – 20 = 0

Gives, x = -5/3, 4

6y^{2}+ 31y + 35 = 0

6y^{2}+ 10y + 21y + 35 = 0

Gives y = -7/2, -5/3

Put on number line

-7/2 -5/3 4**3x**^{2}+ 4x – 32 = 0, y^{2}+ y – 12 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**E) x = y or relationship cannot be determined**

Explanation:

3x^{2}+ 4x – 32 = 0

3x^{2}+ 12x – 8x – 32 = 0

Gives, x = -4, 8/3

y^{2}+ y – 12 = 0

gives, y = -4, 3

put on number line

-4 8/3 3**3x**^{2}+ 7x + 4 = 0, 3y^{2}+ y – 2 = 0

A) x > y

B) x < y

C) x ≥ y

D) x ≤ y

E) x = y or relationship cannot be determined

**D) x ≤ y**

Explanation:

3x^{2}+ 7x + 4 = 0

3x^{2}+ 3x + 4x + 4 = 0

Gives, x = -4/3, -1

3y^{2}+ y – 2 = 0

3y^{2}+ 3y – 2y – 2 = 0

Gives, y = -1, 2/3

Put on number line

-4/3 -1 2/3**A, B, and C can complete a work in 20/11 hours. Time taken by C to complete the same work is 9/2 times the time taken by A and B together to complete that work. Also time taken by A to complete the work is 5/6 times the time taken by B and C together to complete that work. What is the time in which B can alone complete the work?**

A) 3 1/3 hours

B) 6 hours

C) 6 2/3 hours

D) 5 hours

E) None of these

**C) 6 2/3 hours**

Explanation:

(1/A) + (1/B) + (1/C) = 11/201/C = (2/9) * [(1/A) + (1/B)]1/A = (6/5) * [(1/B) + (1/C)]

From 2nd and 3rd equation put values of 1/A and 1/C in equation 1 to find value of B

**The average of money with A, B, C, and D is Rs 200. If the money with A increases by 100% and that with B increases by 200%, then the average money with four increases by Rs 62.50. If the percentage increases of the amounts with A and B gets swapped, average money with A and B will be Rs 275. What is the amount of money that A had originally?**

A) Rs 200

B) Rs 175

C) Rs 150

D) Rs 180

E) None of these

**C) Rs 150**

Explanation:

(A+B+C+D)/4 = 200

So A+B+C+D = 200*4

Money with A increases by 100%, so with A money becomes (200/100)*A = 2A

With B money becomes 3B

(2A+3B+C+D)/4 = 200+62.50

Or A+2B+(A+B+C+D) = 262.5*4

So A+2B = 262.5*4 – 200*4

Or A+2B = 62.5*4

Also given that if increase in money gets swapped

(3A+2B)/2 = 275

Now solve both equations in A and B to find value of A

**Some toffees were bought at 10 for Rs 1.50 and an equal number at 20 paise each. On selling all the toffees at 20 for Rs 4, a profit of Rs 10 was made. How many toffees were purchased?**

A) 200

B) 300

C) 400

D) 450

E) 250

**C) 400**

Explanation:

Let x toffees purchased. If 10 toffees are for Rs 1.50 then x toffees for Rs 15x/100

If each toffee is for 20 paise or RS 20/100, then x toffees for Rs 20x/100

Total CP of 2x toffees = (15x/100) + (20x/100) = 35x/100

Now 20 toffees sold for Rs 4, so SP of 2x toffees = 4x/10

Now given that (35x/100) + 10 = 4x/10

Solve, x = 200

Total toffees bought = 2x

**In a business started by A and B, a profit of Rs 50,000 was made after a year. B being a working partner received 20% of the annual profit as his salary. Had the entire profits divided in the ratio of their investments A would have received Rs 8000 more as his profit share than what he actually got. What is the actual profit share of A?**

A) Rs 35,000

B) Rs 30,000

C) Rs 42,000

D) Rs 32,000

E) Rs 40,000

**D) Rs 32,000**

Explanation:

As salary, B got = 20/100 * 50,000 = Rs 10,000

So remaining profit = 50,000 – 10,000 = 40,000

Let the investment ratio of A and B is x : y

Then A will get = [x/(x+y)] * 40,000

But if entire profits were divided between them

Then A would have got [x/(x+y)] * 50,000

Now given that [x/(x+y)] * 50,000 = [[x/(x+y)] * 40,000] + 8000

Solve, x = 4y

So the ratio of investments become 4 : 1

So A will get [4/(4+1)] * 40,000

**A bag contains 5 black and 7 green balls. Two balls are drawn one after the other with 1st ball being replaced. What is the probability that both the balls are green?**

A) 36/225

B) 48/121

C) 49/144

D) 40/221

E) None of these

**C) 49/144**

Explanation:

7/12 * 7/12

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