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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeDirections(Q15). Refer to the table and answer the given questions.
Data related to number of students in 5 different colleges in December, 2017
I. Students of the given colleges can be categorised only in three types:
Commerce Students, Chemistry students and Maths students
II. Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.What is the sum of the number of Maths students and Commerce Students in college N?
Correct
Answer – 5) 483
Explanation :
Number of Maths students = 40% of 700 = 280
Number of Commerce students = 29% of 700 = 203
Difference = 280 + 203 = 483Incorrect
Answer – 5) 483
Explanation :
Number of Maths students = 40% of 700 = 280
Number of Commerce students = 29% of 700 = 203
Difference = 280 + 203 = 483 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeDirections(Q15). Refer to the table and answer the given questions.
Data related to number of students in 5 different colleges in December, 2017
I. Students of the given colleges can be categorised only in three types:
Commerce Students, Chemistry students and Maths students
II. Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.The average number of Maths students and Chemistry students in college Q was 325. what was the total number of students in college Q?
Correct
Answer – 2) 1000
Explanation :
Average number of Maths students and Chemistry students in college Q = 325
Total no of Maths students and Chemistry students in college Q = 650
Total number of students in college Q = X
X = 650 * (100/65) = 1000Incorrect
Answer – 2) 1000
Explanation :
Average number of Maths students and Chemistry students in college Q = 325
Total no of Maths students and Chemistry students in college Q = 650
Total number of students in college Q = X
X = 650 * (100/65) = 1000 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeDirections(Q15). Refer to the table and answer the given questions.
Data related to number of students in 5 different colleges in December, 2017
I. Students of the given colleges can be categorised only in three types:
Commerce Students, Chemistry students and Maths students
II. Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.If the respective ratio between the number of Chemistry students and Maths students in college M was 10:7, what was the number of Chemistry students in M?
Correct
Answer – 5) 420
Explanation :
Number of Commerce students = 32% of 1050 = 336
Number of Chemistry students and Maths students = 1050 336 = 714
Number of Chemistry students in M = 714 * (10/17) = 420Incorrect
Answer – 5) 420
Explanation :
Number of Commerce students = 32% of 1050 = 336
Number of Chemistry students and Maths students = 1050 336 = 714
Number of Chemistry students in M = 714 * (10/17) = 420 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeDirections(Q15). Refer to the table and answer the given questions.
Data related to number of students in 5 different colleges in December, 2017
I. Students of the given colleges can be categorised only in three types:
Commerce Students, Chemistry students and Maths students
II. Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.Total number of students in college N increased by 20% from December 2017 to 2018, If 30% of the total number of students in college N in December, 2018 was Commerce Students, what was the number of Commerce Students in college N in December 2018?
Correct
Answer – 4) 252
Explanation :
Total number of students in college N in 2018 = 840
Commerce Students in college N in December 2018 = 30% of 840 = 252Incorrect
Answer – 4) 252
Explanation :
Total number of students in college N in 2018 = 840
Commerce Students in college N in December 2018 = 30% of 840 = 252 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeDirections(Q15). Refer to the table and answer the given questions.
Data related to number of students in 5 different colleges in December, 2017
I. Students of the given colleges can be categorised only in three types:
Commerce Students, Chemistry students and Maths students
II. Few values are missing in the table (indicated by ___). A candidate is expected to calculate the missing value, if it is required to answer the given questions, on the basis of the given data and information.Total number of students in college P was 3 times the total number of students in college O. If the difference between the number of Maths students in college P and that in college O was 180, what was the total number of students in college O?
Correct
Answer – 4) 900
Explanation :
Total number of students in college P = 3 times the total number of students in college O.
40% – 20% = 180
20% = 180
Total number of students in college O = 360 * (100/40) = 900Incorrect
Answer – 4) 900
Explanation :
Total number of students in college P = 3 times the total number of students in college O.
40% – 20% = 180
20% = 180
Total number of students in college O = 360 * (100/40) = 900 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeWhen the price of Moong Dal was increased by 32%, a boarding house reduced its consumption in such a way that the expenditure on Moong Dal was only 10% more than before. If 30 kg per month were consumed before, find the new monthly consumption of boarding house?
Correct
Answer – 2) 25 kg
Explanation:
Initial Moong Dal per kg cost be Rs. 100
Then, monthly expenditure of the boarding house = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of boarding house.
X x 132 = 110/100 x 3000
=> X = 25 kg.Incorrect
Answer – 2) 25 kg
Explanation:
Initial Moong Dal per kg cost be Rs. 100
Then, monthly expenditure of the boarding house = 30 x 100 = 3000
After increase in cost,
Let X be new monthly consumption of boarding house.
X x 132 = 110/100 x 3000
=> X = 25 kg. 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeSilvia lent Rs. 16000 partly at the rate of 5% and partly at the rate of 6% per annum SI. The total interest she get after 2 years is Rs. 1640, then in which ratio will Rs. 16000 is to be divided?
Correct
Answer – 1) 7:1
Explanation:
1640 = x*5*2/100 + [16000x]*6*2/100
164000 = 10x + 192000 – 12x
x = 14000
16000 x = 2000
=>14000:2000
=>7:1Incorrect
Answer – 1) 7:1
Explanation:
1640 = x*5*2/100 + [16000x]*6*2/100
164000 = 10x + 192000 – 12x
x = 14000
16000 x = 2000
=>14000:2000
=>7:1 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeThe ratio of efficiencies of Praveen, Suresh and Ravi is 2:3:4. While Praveen and Ravi work on alternate days and Suresh work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1800. Find the amount of each person(respectively).
Correct
Answer – 2) 300, 900, 600
Explanation:
Ratio of efficiencies of Praveen, Suresh and Ravi = 2:3:4
Number of working days of Praveen, Suresh, Ravi = 5:10:5
Hence, ratio of amount of Praveen, Suresh, Ravi = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Praveen, Suresh, Ravi = 300, 900 and 600.Incorrect
Answer – 2) 300, 900, 600
Explanation:
Ratio of efficiencies of Praveen, Suresh and Ravi = 2:3:4
Number of working days of Praveen, Suresh, Ravi = 5:10:5
Hence, ratio of amount of Praveen, Suresh, Ravi = 2×5 : 3×10 : 4×5 = 10 : 30 : 20 = 1:3:2
Amount of Praveen, Suresh, Ravi = 300, 900 and 600. 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeA Water tank can be filled by two tubes P and Q in 60 and 40 minutes respectively. How many minutes will it take to fill the Water tank from empty state if Q is used for half the time and P and Q fill it together for the other half?
Correct
Answer – 4) 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutesIncorrect
Answer – 4) 30 minutes
Explanation:
Part filled by (P + Q) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 minutes 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeIn a building, the length of a floor exceeds its breadth by 25 m. The area of the floor remains unchanged when the length is decreased by 10 m but the breadth is increased by 8 m. What is 1/5th of the sum of the length and breadth of the floor?
Correct
Answer – 3) 29 m
Explanation:
Let the breadth of floor be ‘b’ m.
Then, length of the floor is ‘l = (b + 25)’
Area of the rectangular floor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m
l = b + 25 = 60 + 25 = 85 m
Sum = 85 + 60 = 145
⅕ * 145 = 29Incorrect
Answer – 3) 29 m
Explanation:
Let the breadth of floor be ‘b’ m.
Then, length of the floor is ‘l = (b + 25)’
Area of the rectangular floor = l x b = (b + 25) × b
(b + 15) (b + 8) = (b + 25) × b
b^2 + 8b + 15b + 120 = b^2 + 25b
8b + 15b + 120 = 25b
2b = 120
b = 60 m
l = b + 25 = 60 + 25 = 85 m
Sum = 85 + 60 = 145
⅕ * 145 = 29
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