Hello Aspirants.

Welcome to Online Maths in AffairsCloud.com. Here we are creating question sample in **Compound Interest**, which is common for all the IBPS, SBI, RBI, IPPB, LIC and other competitive exams. We have included Some questions that are repeatedly asked in exams !!

**A part of 70000 is lent out at 10% annum. The rest of the amount is lent out at 5% per annum after one year. The ratio of interest after 3 years from the time when first amount was lent out is 1:2. Find the second part that was lent out at 5%.**

A.40000

B.50000

C.60000

D.48000

E.55000Answer –**C.60000**

**Explanation :**

10*3*x/5*2*y = 1/2

x/y = 1/6

6/7*70000 = 60000**There is 50% increase in an amount in 5 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate?**

A.Rs. 2255

B.Rs. 2792

C.Rs. 3580

D.Rs. 3972

E.None of theseAnswer –**D.Rs. 3972**

**Explanation :**

In S.I,

Let P=100, I=50, T=5 yrs

R = 50*100/100*5 = 10%

In C.I,

P = 12000, T=3 yrs, R= 10%

C.I = [12000*(1 + 10/100)^3 – 1 ]

C.I = 3972.**Karthik lends a certain amount to Vignesh on simple interest for two years at 20%. Vignesh gives this entire amount to Kamal on compound interest for two years at the same rate annually. Find the percentage earning of Vignesh at the end of two years on the entire amount.**

A.3%

B.3(1/7)%

C.4%

D.5(6/7)%

E.None of theseAnswer –**C.4%**

**Explanation :**

SI=20*2=40%

CI=20+20+(400/100)=44%

Diff = 44-40=4%**A man borrows 3000 rupees at 10% compound interest. At the end every year he pays rupees 1000 back. How much amount should he pay at the end of the fourth Year to clear all his debt?**

A.Rs. 680.5

B.Rs. 651.3

C.Rs. 751.3

D.Rs. 790.3

E.None of theseAnswer –**C.Rs. 751.3**

**Explanation :**

After one year amount = 3000 *110/100 = 3300

He pays 1000 back, so remaining = 3300-1000 = 2300

After two year amount = 2300 *110/100 = 2530

He pays 1000 back, so remaining = 2530-1000 = 1530

After three year amount = 1530*110/100 = 1683

He pays 1000 back, so remaining = 1683-1000= 683

After fouth year = 683 * 110/100 = 751.3**Rahul saves an amount of 800 every year and then lent that amount at an interest of 10 percent compounded annually. Find the amount after 3 years.**

A.Rs. 1822.8

B.Rs. 2252

C.Rs. 2550.50

D.Rs. 2912.8

E.None of theseAnswer –**D.Rs. 2912.8**

**Explanation :**

800*(11/10)³=1064.8

800*(11/10)²=968

800*(11/10)=880

Total amount =2912.8**Find the compound interest at the rate of 8% for 3 years on that principal which in 3 years at therate of 10% per annum gives 300 as simple interest.**

A.180.515

B.220.25

C.259.712

D.289.624

E.312.51Answer –**C.259.712**

**Explanation :**

SI =300

Per yr = 100

Rate = 10%

C.I = 1000*(108/100)³ -1000

C.I = 259.712**The difference between the total simple interest and the total compound interest compounded annually at the same rate of interest on a sum of money at the end of two years is Rs. 450. What is definitely the rate of interest per cent per annum?**

A.8400

B.4800

C.7800

D.Data inadequate

E.None of theseAnswer –**D.Data inadequate**

**Explanation :**

Difference = Pr^{2}/(100)^{2}

= (450×100×100)/(P×r^{2})

P is not given**The CI on Rs.6000 for 3 years at 8% for first year, 7% for second year, 6% for the third year will be**

A.Rs.1430

B.Rs.1530

C.Rs.1250

D.Rs.1350

E.None of theseAnswer –**D.Rs.1350**

**Explanation :**

A = 6000*108/100*107/100*106/100

= 6000*1.08*1.07*1.06

= 7349.616 = 7350

CI = 7350-6000 = 1350**Venkat and Vidhya have to clear their respective loans by paying 2 equal annual instalments of Rs.30000 each. Venkat pays at 10% pa of SI and Vidhyapays at 10% CI pa. What is the difference in their payments ?**

A.200

B.300

C.400

D.500

E.None of theseAnswer –**B.300**

**Explanation :**

D =[(30,000 *110/100*110/100) – 30,000] – 30,000 *10*2/100

=[36300-30000]- 6000

=6300 – 6000

D = 300**The difference between interest received by Vivek and Vimal is Rs.405 on Rs.4500 for 3 years. What is the difference in rate of interest ?**

A.1.5%

B.2%

C.3%

D.2.7%

E.None of theseAnswer –**C.3%**

**Explanation :**

4500*3/100(R1-R2) = 405

R1-R2 = 405*100/13500 = 3%

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