Hello Aspirants

Welcome to Online **Quant** **Test** in AffairsCloud.com. We are starting **Cumulus Course for RRB Clerk 2019 Prelims Exam** and we are creating sample questions in Quant section, this type of Question will be asked in RRB Clerk 2019!!!

**Click Here to View Cumulus Course: RRB Clerk 2019 Mains**

**RRB Clerk 2019 Mains: GA Test **– 7.00 PM Every Day

**RRB Clerk 2019 Mains: Reasoning Test **– 8.00 PM Every Day

**RRB Clerk 2019 Mains: Quant Test **– 9.00 PM Every Day

**RRB Clerk 2019 Mains: English Test **– 10.00 PM Every Day

**Help:- **Share Our Cumulus Course for RRB Clerk 2019 Exam Course page to your Friends & FB Groups

**Click Here to Subscribe Crack High Level Puzzles & Seating Arrangement Questions PDF 2019 Plan**

_______________________

#### Quiz-summary

0 of 10 questions completed

Questions:

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

#### Information

**All the Best**

You have already completed the quiz before. Hence you can not start it again.

Quiz is loading...

You must sign in or sign up to start the quiz.

You have to finish following quiz, to start this quiz:

#### Results

0 of 10 questions answered correctly

Your time:

Time has elapsed

You have reached 0 of 0 points, (0)

#### Categories

- Quantitative Aptitude 0%

- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10

- Answered
- Review

- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5): Study the following table carefully and answer the given questions. The table shows the discount rate of four different items in five different shops. Only one item of each type is there in each shop.**

Note: Marked price of each item is same in all the shops**Quantity 1:**The selling price of item 1 in shop A is Rs. 4000. The profit obtained by selling item 1 in shop A is Rs. 800. The ratio of profit obtain for item 1 in shop A to shop C is 2:5. Find the cost price of item 1 in shop C.

**Quantity 2:**The selling price of item 2 in shop E is Rs. 8500. The cost price of item 2 in shop B is Rs. 4000. Find the profit obtained by selling item 2 in shop B.CorrectAnswer: 3) Quantity 1 = Quantity 2

Q1:

Marked price of item 1 = 4000*(100/80) = 5000

Cost price of item 1 in shop A = 4000-800 = 3200

Profit obtained for item 1 in shop C = 800*(5/2) = 2000

Selling price of item 1 in shop C = 5000*(9/10) = 4500

Cost price of item 1 in shop C = 4500-2000 =**2500**

**Q2:**

Marked price of item 2 = 8500*(100/85) = 10000

Selling price of item 2 in shop B = 10000*{(100-35)/100} = 10000*(65/100) = 6500

Profit obtained by selling item 2 in shop B = 6500-4000 =**2500**IncorrectAnswer: 3) Quantity 1 = Quantity 2

Q1:

Marked price of item 1 = 4000*(100/80) = 5000

Cost price of item 1 in shop A = 4000-800 = 3200

Profit obtained for item 1 in shop C = 800*(5/2) = 2000

Selling price of item 1 in shop C = 5000*(9/10) = 4500

Cost price of item 1 in shop C = 4500-2000 =**2500**

**Q2:**

Marked price of item 2 = 8500*(100/85) = 10000

Selling price of item 2 in shop B = 10000*{(100-35)/100} = 10000*(65/100) = 6500

Profit obtained by selling item 2 in shop B = 6500-4000 =**2500** - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5): Study the following table carefully and answer the given questions. The table shows the discount rate of four different items in five different shops. Only one item of each type is there in each shop.**

Note: Marked price of each item is same in all the shops**Quantity 1:**The cost price of item 2 for shop E is Rs. 5000 and 70% profit is obtained by shop E on item 2. Find the selling price of item 2 in shop A.

**Quantity 2:**The cost price of item 2 for shop A is Rs. 8000 and 30% loss happens to shop A on selling item 2. Find the selling price of item 2 in shop B.Correct**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Selling price of item 2 in shop E = (170/100)*5000 = 8500

Marked price of item 2 = 8500*(100/85) = 10000

Selling price of item 2 in shop A = 10000*(70/100) =**7000****Q2:**

Selling price of item 2 in shop A = 8000*(70/100) = 5600

Marked price of item 2 = 5600*(100/70) = 8000

Selling price of item 2 in shop B = 8000*(65/100) =**5200**Incorrect**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Selling price of item 2 in shop E = (170/100)*5000 = 8500

Marked price of item 2 = 8500*(100/85) = 10000

Selling price of item 2 in shop A = 10000*(70/100) =**7000****Q2:**

Selling price of item 2 in shop A = 8000*(70/100) = 5600

Marked price of item 2 = 5600*(100/70) = 8000

Selling price of item 2 in shop B = 8000*(65/100) =**5200** - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Directions (1-5): Study the following table carefully and answer the given questions. The table shows the discount rate of four different items in five different shops. Only one item of each type is there in each shop.**

Note: Marked price of each item is same in all the shops**Quantity 1:**The profit obtained by selling item 3 in shop D is Rs. 1000. The cost price of item 3 in shop D is 7000. Find the selling price of item 3 in E.

**Quantity 2:**The marked price of item 3 in shop C is 125% of its cost price. The cost price of item 3 in shop C is Rs. 12000 and the loss occurred on selling item 3 in shop C is 50% of its marked price. Find the different between selling price of item 3 in shop C and selling price of item 3 in shop A.Correct**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Selling price of item 3 in shop D = 7000+1000 = Rs. 8000

Marked price of item 3 in shop D = 8000*(100/80) = 10000

Selling price of item 3 in shop E = 10000*(85/100) =**8500****Q2:**

Marked price of item 3 in shop C = 12000*(125/100) = 15000

Loss occurred = (50/100)*15000 = 7500

Selling price of item 3 in shop C = 12000-7500 = 4500

Selling price of item 3 in shop A = 15000*(75/100) = 11250

Required difference = 11250 – 4500 =**6750**Incorrect**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Selling price of item 3 in shop D = 7000+1000 = Rs. 8000

Marked price of item 3 in shop D = 8000*(100/80) = 10000

Selling price of item 3 in shop E = 10000*(85/100) =**8500****Q2:**

Marked price of item 3 in shop C = 12000*(125/100) = 15000

Loss occurred = (50/100)*15000 = 7500

Selling price of item 3 in shop C = 12000-7500 = 4500

Selling price of item 3 in shop A = 15000*(75/100) = 11250

Required difference = 11250 – 4500 =**6750** - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude

Note: Marked price of each item is same in all the shops**Quantity 1:**The ratio of cost price to selling price of item 4 in shop B is 4:5. The profit obtained by selling item 4 by shop B is Rs. 3000. Find the sum of marked price of item 3 and selling price of item 3 in shop E.

**Quantity 2:**The selling price of item 4 in shop E is Rs. 16000. By selling item 4 the loss for shop B and profit obtained by shop D is Rs. 4500 and Rs. 500 respectively. Find the sum of cost price of item 4 in shop B and shop D.Correct**Answer: 3) Quantity 1 = Quantity 2**

**Q1:**

Let the cost price of item 4 for shop B = 4x and selling price of item 4 in shop B = 5x

Profit obtained = 5x-4x = x = 3000

Selling price of item 4 in shop B = 5x = 5*3000 = 15000

Marked price of item 4 = 15000*(100/75) = 20000

Selling price of item 4 in shop E = 20000*(80/100) = 16000

Required sum = 20000+16000 =**36000****Q2:**

Marked price of item 4 = 16000*(100/80) = 20000

Selling price of item 4 in shop B = 20000*(75/100) = 15000

Cost price of item 4 in shop B = 15000+4500 = 19500

And selling price of item 4 in shop D = 20000*(85/100) = 17000

Cost price of item 4 in shop D = 17000-500 = 16500

The sum of cost price of item 4 in shop B and shop D = 19500+16500 =**36000**Incorrect**Answer: 3) Quantity 1 = Quantity 2**

**Q1:**

Let the cost price of item 4 for shop B = 4x and selling price of item 4 in shop B = 5x

Profit obtained = 5x-4x = x = 3000

Selling price of item 4 in shop B = 5x = 5*3000 = 15000

Marked price of item 4 = 15000*(100/75) = 20000

Selling price of item 4 in shop E = 20000*(80/100) = 16000

Required sum = 20000+16000 =**36000****Q2:**

Marked price of item 4 = 16000*(100/80) = 20000

Selling price of item 4 in shop B = 20000*(75/100) = 15000

Cost price of item 4 in shop B = 15000+4500 = 19500

And selling price of item 4 in shop D = 20000*(85/100) = 17000

Cost price of item 4 in shop D = 17000-500 = 16500

The sum of cost price of item 4 in shop B and shop D = 19500+16500 =**36000** - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude

Note: Marked price of each item is same in all the shops**Quantity1:**The marked price of item 1 is Rs. 2500 and the ratio of marked price of item 1, item 2, item 3 and item 4 is 5:3:4:8. Find the sum of selling prices of item 1, item 2, item 3 and item 4 in shop E.

**Quanity2:**The marked price of item 1 is Rs. 2000 and the ratio of marked price of item 1, item 2, item 3 and item 4 is 4:5:6:8. The ratio of selling price of item 3 to item 4 in shop A is 5:4. Find the sum of selling prices of item 1, item 2, item 3 and item 4 in shop A.Correct**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Let the marked price of item 1 = 5x

Marked price of item 2 = 3x

Marked price of item 3 = 4x

Marked price of item 4 = 8x

5x = 2500

x = 500

Marked price of item 2 = 3x = 3*500 = 1500

Marked price of item 3 = 4x = 4*500 = 2000

Marked price of item 4 = 8x= 8*500 = 4000

Selling price of item 1 in shop E = 2500*(75/100) = 1875

Selling price of item 2 in shop E = 1500*(85/100) = 1275

Selling price of item 3 in shop E = 2000*(85/100) = 1700

Selling price of item 4 in shop E = 4000*(80/100) = 3200

Required sum = 1875+1275+1700+3200 = Rs.**8050****Q2:**

Let the marked price of item 1 = 4x

Marked price of item 2 = 5x

Marked price of item 3 = 6x

Marked price of item 4 = 8x

4x = 2000

x = 500

Marked price of item 2 = 5x = 5*500 = 2500

Marked price of item 3 = 6x = 6*500 = 3000

Marked price of item 4 = 8x= 8*500 = 4000

Selling price of item 1 in shop A = 2000*(80/100) = 1600

Selling price of item 2 in shop A = 2500*(70/100) = 1750

Selling price of item 3 in shop A = 3000*(75/100) = 2250

Selling price of item 4 in shop A = 2250*(4/5) = 1800

Required sum = 1600+1750+2250+1800 = Rs.**7400**Incorrect**Answer: 1) Quantity 1 > Quantity 2**

**Q1:**

Let the marked price of item 1 = 5x

Marked price of item 2 = 3x

Marked price of item 3 = 4x

Marked price of item 4 = 8x

5x = 2500

x = 500

Marked price of item 2 = 3x = 3*500 = 1500

Marked price of item 3 = 4x = 4*500 = 2000

Marked price of item 4 = 8x= 8*500 = 4000

Selling price of item 1 in shop E = 2500*(75/100) = 1875

Selling price of item 2 in shop E = 1500*(85/100) = 1275

Selling price of item 3 in shop E = 2000*(85/100) = 1700

Selling price of item 4 in shop E = 4000*(80/100) = 3200

Required sum = 1875+1275+1700+3200 = Rs.**8050****Q2:**

Let the marked price of item 1 = 4x

Marked price of item 2 = 5x

Marked price of item 3 = 6x

Marked price of item 4 = 8x

4x = 2000

x = 500

Marked price of item 2 = 5x = 5*500 = 2500

Marked price of item 3 = 6x = 6*500 = 3000

Marked price of item 4 = 8x= 8*500 = 4000

Selling price of item 1 in shop A = 2000*(80/100) = 1600

Selling price of item 2 in shop A = 2500*(70/100) = 1750

Selling price of item 3 in shop A = 3000*(75/100) = 2250

Selling price of item 4 in shop A = 2250*(4/5) = 1800

Required sum = 1600+1750+2250+1800 = Rs.**7400** - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Two trains A and B running at speeds 50 km/hr and 70 km/hr respectively are approaching each other. They are 360 km away. After 30 minutes, A bird starts from Train A towards Train B at the speed of 80km/hr. It reverses his direction as soon as he reached Train B and flies towards A, it continues this until Train A and Train B meets. The total distance covered by the bird until Train A and Train B meet is ___A_ km. The time taken by the bird to meet Train B for the first time is ___B__ hours. The distance between Train A and Train B when the bird meets Train B for the first time is __C__ km. A bee also joins the bird at the time when the bird meets Train B for the first time. The bee covers 25km distance at a speed of __D__ km/hr until Train A and Train B meet. The speed of Bee is ___E%_ of the speed of train A.**Find the value of A.**Correct**Answer: 1) 200**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)Incorrect**Answer: 1) 200**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A) - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Two trains A and B running at speeds 50 km/hr and 70 km/hr respectively are approaching each other. They are 360 km away. After 30 minutes, A bird starts from Train A towards Train B at the speed of 80km/hr. It reverses his direction as soon as he reached Train B and flies towards A, it continues this until Train A and Train B meets. The total distance covered by the bird until Train A and Train B meet is ___A_ km. The time taken by the bird to meet Train B for the first time is ___B__ hours. The distance between Train A and Train B when the bird meets Train B for the first time is __C__ km. A bee also joins the bird at the time when the bird meets Train B for the first time. The bee covers 25km distance at a speed of __D__ km/hr until Train A and Train B meet. The speed of Bee is ___E%_ of the speed of train A.**Find the value of B.**Correct**Answer: 3) 2**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)Incorrect**Answer: 3) 2**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B) - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Two trains A and B running at speeds 50 km/hr and 70 km/hr respectively are approaching each other. They are 360 km away. After 30 minutes, A bird starts from Train A towards Train B at the speed of 80km/hr. It reverses his direction as soon as he reached Train B and flies towards A, it continues this until Train A and Train B meets. The total distance covered by the bird until Train A and Train B meet is ___A_ km. The time taken by the bird to meet Train B for the first time is ___B__ hours. The distance between Train A and Train B when the bird meets Train B for the first time is __C__ km. A bee also joins the bird at the time when the bird meets Train B for the first time. The bee covers 25km distance at a speed of __D__ km/hr until Train A and Train B meet. The speed of Bee is ___E%_ of the speed of train A.**Find the value of C.**Correct**Answer: 3) 60**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time

= 300 – 2*(50+70)

= 60km (C)Incorrect**Answer: 3) 60**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time

= 300 – 2*(50+70)

= 60km (C) - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Two trains A and B running at speeds 50 km/hr and 70 km/hr respectively are approaching each other. They are 360 km away. After 30 minutes, A bird starts from Train A towards Train B at the speed of 80km/hr. It reverses his direction as soon as he reached Train B and flies towards A, it continues this until Train A and Train B meets. The total distance covered by the bird until Train A and Train B meet is ___A_ km. The time taken by the bird to meet Train B for the first time is ___B__ hours. The distance between Train A and Train B when the bird meets Train B for the first time is __C__ km. A bee also joins the bird at the time when the bird meets Train B for the first time. The bee covers 25km distance at a speed of __D__ km/hr until Train A and Train B meet. The speed of Bee is ___E%_ of the speed of train A.**Find the value of D.**Correct**Answer: 3) 50**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time = 300 – 2*(50+70)

= 60km (C)

Distance left between train A and train B when bee joins = 60km

Hence, time for which Bee fly = 60/(50+70) = 60/120 = ½ hours

Bee covers 25 km in ½ hours

Hence, speed of bee = {25/(1/2)} = 50km/hr (D)Incorrect**Answer: 3) 50**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time = 300 – 2*(50+70)

= 60km (C)

Distance left between train A and train B when bee joins = 60km

Hence, time for which Bee fly = 60/(50+70) = 60/120 = ½ hours

Bee covers 25 km in ½ hours

Hence, speed of bee = {25/(1/2)} = 50km/hr (D) - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10):**Two trains A and B running at speeds 50 km/hr and 70 km/hr respectively are approaching each other. They are 360 km away. After 30 minutes, A bird starts from Train A towards Train B at the speed of 80km/hr. It reverses his direction as soon as he reached Train B and flies towards A, it continues this until Train A and Train B meets. The total distance covered by the bird until Train A and Train B meet is ___A_ km. The time taken by the bird to meet Train B for the first time is ___B__ hours. The distance between Train A and Train B when the bird meets Train B for the first time is __C__ km. A bee also joins the bird at the time when the bird meets Train B for the first time. The bee covers 25km distance at a speed of __D__ km/hr until Train A and Train B meet. The speed of Bee is ___E%_ of the speed of train A.**Find the value of E.**Correct**Answer: 4) 100**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time = 300 – 2*(50+70)

= 60km (C)

Distance left between train A and train B when bee joins = 60km

Hence, time for which Bee fly = 60/(50+70) = 60/120 = ½ hours

Bee covers 25 km in ½ hours

Hence, speed of bee = {25/(1/2)} = 50km/hr (D)

Required percentage = (50/50)*100 = 100% (E)Incorrect**Answer: 4) 100**

Explanation:

Initial distance between train A and train B = 360 km

Relative speed of train A and train B = 50+70 = 120 km/hr

Distance between Train A and Train B when bird started flying = 360 – 120*(1/2) = 300 km/hr

Time taken by Train A and Train B to meet (when bird started) = 300/120 = 2.5 hours

Distance covered by bird in 2.5 hours = 80*2.5 = 200km (A)

The time taken by bird to meet Train B for the first time = 300/(70+80) = 2 hours (B)

Distance between Train A and Train B when bird meets Train B for the first time = 300 – 2*(50+70)

= 60km (C)

Distance left between train A and train B when bee joins = 60km

Hence, time for which Bee fly = 60/(50+70) = 60/120 = ½ hours

Bee covers 25 km in ½ hours

Hence, speed of bee = {25/(1/2)} = 50km/hr (D)

Required percentage = (50/50)*100 = 100% (E)

**Click view Questions button to view Explanation****Note:-**We are providing unique questions for you to practice well, have a try !!- Ask your doubt in comment section, AC Mod’s ll clear your doubts in caring way.
- If you find any mistake, please tell us in the comment section.

**Bank Jobs Notification**

**Central Govt Jobs Notification**