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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**Find the approximate value of x.**

X= 81% of (√680 -√480) + 70% of (22.95+ 25.89)Correct**Answer -4) 38**

Explanation –

X= 81% of (√680 -√480) + 70% of (22.95+ 25.89)

81/100 × (26 – 22) + 70/100 × 48.84

81/100 × (4) + 34.2

3.24 + 34.2

= 37.44Incorrect**Answer -4) 38**

Explanation –

X= 81% of (√680 -√480) + 70% of (22.95+ 25.89)

81/100 × (26 – 22) + 70/100 × 48.84

81/100 × (4) + 34.2

3.24 + 34.2

= 37.44 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Find the missing number in the series**

40, 40, 20, 60, 15, 75, __Correct**Answer -3) 12.5**

Explanation

40 ×1 =40

40 × ½ = 20

20 × 3 =60

60× ¼ = 15

15× 5 = 75

75 × 1/6 = 12.5Incorrect**Answer -3) 12.5**

Explanation

40 ×1 =40

40 × ½ = 20

20 × 3 =60

60× ¼ = 15

15× 5 = 75

75 × 1/6 = 12.5 - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**Find the roots of the quadratic equation to compare the values of x and y.**

**X**^{2}-31x+238=0

**Y**^{2}-28y+187=0Correct**Answer – 5) x = y or no relation can be established.**

**Explanation**

X^{2}-31x+238=0

X^{2}-14x-17x+238=0

X(x-14)-17(x-14) =0

X=17, 14Y

^{2}-28y+187=0

Y^{2}-11y-17y+187=0

Y(y-11)-17(y-11)=0

Y=11,17Incorrect**Answer – 5) x = y or no relation can be established.**

**Explanation**

X^{2}-31x+238=0

X^{2}-14x-17x+238=0

X(x-14)-17(x-14) =0

X=17, 14Y

^{2}-28y+187=0

Y^{2}-11y-17y+187=0

Y(y-11)-17(y-11)=0

Y=11,17 - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**This question contains two sub- questions i.e., Quantity 1 and Quantity 2. Quantity 1 will be the answer of the first question and Quantity 2 will be the answer of second question. Compare the two quantities –**

**Quantity -1)**Temple trust decides to build a worship hall having a carpet area of 300 square metres with its length one metre more than twice its breadth. What should be the breadth of the hall?

**Quantity- 2)**There are two numbers whose sum is 27 and product is 182. Find the smaller number?Correct**Answer -3. Quantity 1****<****Quantity 2**

Q1 = 12

Q2 = 13

**Explanation –**

Q1 = 12

Let the breadth of the hall = x

Length of the hall well be 2x+1

(2x+1).x = 300

2x^{2}+x = 300

2x^{2}+x-300 = 0

2x^{2}-24x+25x-300 = 0

2x(x-12) +25(x-12) = 0

X = 12, -12.5 (breadth cannot be negative)Quantity 2= 13

Let the first number is x

Second number will be 27-x

X(27-x) = 182

X^{2}-27x+182 =0

X=13, 14Incorrect**Answer -3. Quantity 1****<****Quantity 2**

Q1 = 12

Q2 = 13

**Explanation –**

Q1 = 12

Let the breadth of the hall = x

Length of the hall well be 2x+1

(2x+1).x = 300

2x^{2}+x = 300

2x^{2}+x-300 = 0

2x^{2}-24x+25x-300 = 0

2x(x-12) +25(x-12) = 0

X = 12, -12.5 (breadth cannot be negative)Quantity 2= 13

Let the first number is x

Second number will be 27-x

X(27-x) = 182

X^{2}-27x+182 =0

X=13, 14 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**This consists of a question and two statements numbered 1 and 2 given below it. You have to decide if the data provided in the statements are sufficient to answer the question. Read both statements and mark answer.**

**There are two bikes A and B which are 600km apart from each other. Find the distance between A and B at 11am.**

Statement 1: Both the bikes started to move towards each other at 7am.

Statement 2: Speed of bike A is 40km/hr at 7am which decreases by 10% after every hour and speed of bike Q is 50km/ht at 7am which increases by 10% after every hour.Correct**Answer -5) The data in both the statements 1 and 2 together are necessary to answer the question.**

Explanation –

Statement 1 gives Direction in which bikes are moving.

Statement 2 gives Distance covered in that time.

Speed of bike A from 7am till 8am = 40km/hr

Speed of bike A from 8am till 9am = 40 × 9/10

Speed of bike A from 9am till 10am = 40 × 9/10 ×9/10

Speed of bike A from 10am till 11am = 40 × 9/10 ×9/10 × 9/10

Distance covered by bike A from 7am till 11am = 40[1+9/10 + (9/10)2 + (9/10)3] =137.56

Similarly, distance covered by bike B from 7am till 11am = 50[1 + 11/10 + (11/10)2 + (11/10)3] =232.05

Total distance covered till 11am = 137.56 + 232.05 = 369.61

Distance between A and B at 11am = 600-369.61 = 230.39Incorrect**Answer -5) The data in both the statements 1 and 2 together are necessary to answer the question.**

Explanation –

Statement 1 gives Direction in which bikes are moving.

Statement 2 gives Distance covered in that time.

Speed of bike A from 7am till 8am = 40km/hr

Speed of bike A from 8am till 9am = 40 × 9/10

Speed of bike A from 9am till 10am = 40 × 9/10 ×9/10

Speed of bike A from 10am till 11am = 40 × 9/10 ×9/10 × 9/10

Distance covered by bike A from 7am till 11am = 40[1+9/10 + (9/10)2 + (9/10)3] =137.56

Similarly, distance covered by bike B from 7am till 11am = 50[1 + 11/10 + (11/10)2 + (11/10)3] =232.05

Total distance covered till 11am = 137.56 + 232.05 = 369.61

Distance between A and B at 11am = 600-369.61 = 230.39 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10) A mobile survey company awarded the points to five top mobiles of year 2018 which is given in line chart.**

The above points are awarded by considering the following aspects given in pie chart.

**Find the total points achieved by all mobiles for their display.**Correct**Answer – 4) 665**

Explanation –

645+665+685+675+655 = 3325

20% of 3325 = 665Incorrect**Answer – 4) 665**

Explanation –

645+665+685+675+655 = 3325

20% of 3325 = 665 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10) A mobile survey company awarded the points to five top mobiles of year 2018 which is given in line chart.**

The above points are awarded by considering the following aspects given in pie chart.

Points achieved by F11 for camera is approximately what percent of points achieved by V15 for processor.

Correct**Answer- 3) 76%**

Explanation –

(655×24)/ (645×32) =( 655 × 3 )/ (645× 4) = (131 × 3) / ( 129 × 4) = 76 aproxIncorrect**Answer- 3) 76%**

Explanation –

(655×24)/ (645×32) =( 655 × 3 )/ (645× 4) = (131 × 3) / ( 129 × 4) = 76 aprox - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Directions (6-10) A mobile survey company awarded the points to five top mobiles of year 2018 which is given in line chart.**

The above points are awarded by considering the following aspects given in pie chart.

**Total Points received by S10 is approximately what percent of total points received by other four models in display?**Correct**Answer-1) 130%**

Explanation –

685 / 20% of (645+655+665+675) × 100 = 685/528 × 100 = 130%Incorrect**Answer-1) 130%**

Explanation –

685 / 20% of (645+655+665+675) × 100 = 685/528 × 100 = 130% - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude

The above points are awarded by considering the following aspects given in pie chart.

**Find the ratio of total points received by all mobiles together in Display to total points received by all mobiles together in Design.**Correct**Answer-4) 5:2**

Explanation –

20% / 8% = 5:2Incorrect**Answer-4) 5:2**

Explanation –

20% / 8% = 5:2 - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude

The above points are awarded by considering the following aspects given in pie chart.

**What is the difference between total points achieved by K20 and P30 together in Durability to total points achieved by S10 and V15 together in Processor?**Correct**Answer – 1) 211.2**

Explanation –

K20+P30 for Durability = 16% of (665+675) = 16% of 1340

S10+V15 for Processor = 32% of (685+645) = 32% of 1330

32% of 1330 – 16% of 1340

= 211.2Incorrect**Answer – 1) 211.2**

Explanation –

K20+P30 for Durability = 16% of (665+675) = 16% of 1340

S10+V15 for Processor = 32% of (685+645) = 32% of 1330

32% of 1330 – 16% of 1340

= 211.2

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