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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeWhich of the following teams drew the maximum number of matches?
Correct
Explanation:
Incorrect
Explanation:

Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeG lost match against which of the following team?
Correct
Explanation:G lost against both A and D
Incorrect
Explanation:G lost against both A and D

Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudeWhich team scored the least number of points ?
Correct
Incorrect

Question 4 of 10
4. Question
1 pointsCategory: Quantitative AptitudeThe team which scored the least number of points has won against which team?
Correct
Incorrect

Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeHow many matches does I lose?
Correct
Incorrect

Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeWhat is the remainder when we divide 3^{90 }+ 7^{90} by 58?
Correct
Explanation:
3^{90} + 7^{90}
=(3^{2})^{45}+ (7^{2})^{45}
=(9)^{45}+ (49)^{45}
Any number of the form (a)^{n} + (b)^{n} is a multiple of (a + b) whenever n is odd.
So, the remainder when we divide the given expression by 58 is zeroIncorrect
Explanation:
3^{90} + 7^{90}
=(3^{2})^{45}+ (7^{2})^{45}
=(9)^{45}+ (49)^{45}
Any number of the form (a)^{n} + (b)^{n} is a multiple of (a + b) whenever n is odd.
So, the remainder when we divide the given expression by 58 is zero 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeIf 15:13 is the ratio of present age of Riya and Siva respectively and 17:11 is the ratio between Riya’s age 4 years hence and Siva’s age 4 years ago. Then what will be the ratio of Riya’s age 4 years ago and Siva’s age 4 years hence ?
Correct
Explanation:
Let the present age of Riya and Siva be 15X and 13X respectively.
Given, Riya’s age 4 years hence and Siva’s age 4 years ago in the ratio 17:11
That is, 15X + 4 / 13X – 4 = 17/11
11(15X + 4) = 17(13X – 4)
165X + 44 = 221X – 68
56X = 112
X = 2
Therefore Riya=30
Siva=26
Ratio=304/26+4=13/15Incorrect
Explanation:
Let the present age of Riya and Siva be 15X and 13X respectively.
Given, Riya’s age 4 years hence and Siva’s age 4 years ago in the ratio 17:11
That is, 15X + 4 / 13X – 4 = 17/11
11(15X + 4) = 17(13X – 4)
165X + 44 = 221X – 68
56X = 112
X = 2
Therefore Riya=30
Siva=26
Ratio=304/26+4=13/15 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative AptitudeA man rows 4 km upstream in 2 hours and 8 km downstream in 3 hours then how long(approx) will he take to cover 16 km in still water?
Correct
Explanation:
Distance covered in downstream = 8 km
Time taken in downstream = 3 hours.
Rate of downstream = distance / time = 8km / 3 hours = 8/3 km/hr.
Distance covered in upstream =4 km
Time taken in upstream = 2 hours.
Rate of upstream = distance / time = 4 km / 2 hours = 2 km/hr.
Speed in still water = (upstream +downstream)/2 = (1/2)(8/3 + 2)
= (1/2)(14/3)= 7/3 km/hr.
Time Taken to cover 16 km in still water = distance / speed = 16 x 3/7 = 48 / 7 = 7 hours (approximately).Incorrect
Explanation:
Distance covered in downstream = 8 km
Time taken in downstream = 3 hours.
Rate of downstream = distance / time = 8km / 3 hours = 8/3 km/hr.
Distance covered in upstream =4 km
Time taken in upstream = 2 hours.
Rate of upstream = distance / time = 4 km / 2 hours = 2 km/hr.
Speed in still water = (upstream +downstream)/2 = (1/2)(8/3 + 2)
= (1/2)(14/3)= 7/3 km/hr.
Time Taken to cover 16 km in still water = distance / speed = 16 x 3/7 = 48 / 7 = 7 hours (approximately). 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative AptitudeHarish bought a book for Rs.485 and sold it at 20% loss. By using that amount he bought another book and sold it at 15% profit. Then overall profit/loss amount is:
Correct
Explanation:
485*.8*1.15=485*.92=446.20
Therefore loss=485446,20=38.8RsIncorrect
Explanation:
485*.8*1.15=485*.92=446.20
Therefore loss=485446,20=38.8Rs 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative AptitudeTwo friends A and B simultaneously start running around a circular track . They run in the same direction. A travels at 8 m/s and B runs at b m/s. If they cross each other at exactly three points on the circular track and b is a natural number less than 20, how many values can b take?
Correct
Explanation:
Let track length be equal to T.
Time taken to meet for the first time = T/relative speed=T/8−b or T/b−8
Time taken for a lap for A = T/8
Time taken for a lap for B = T/b
So, time taken to meet for the first time at the starting point = LCM (T/8,T/b)=T/HCF(8,b)
Number of meeting points on the track = Time taken to meet at starting point/Time taken for first meeting = Relative speed / HCF (8,b).
(8−b)/HCF(8,b) = 3 or (b−8)/HCF(8,b) = 3
b = 2, 5, 11,14 satisfy this equation. So, there are four different values that b can take.Incorrect
Explanation:
Let track length be equal to T.
Time taken to meet for the first time = T/relative speed=T/8−b or T/b−8
Time taken for a lap for A = T/8
Time taken for a lap for B = T/b
So, time taken to meet for the first time at the starting point = LCM (T/8,T/b)=T/HCF(8,b)
Number of meeting points on the track = Time taken to meet at starting point/Time taken for first meeting = Relative speed / HCF (8,b).
(8−b)/HCF(8,b) = 3 or (b−8)/HCF(8,b) = 3
b = 2, 5, 11,14 satisfy this equation. So, there are four different values that b can take.
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