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Question 1 of 10

1. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.
Each student in the school either participate in any one of the events or don’t participate in any events.

What is the difference between the number students, who participate in Painting from school P & Q to number of students who participate in Acting from the same school.

Correct

Answer – 1. 28 Explanation:
School P:
10x = 120
X = 12; Acting – 7x, Painting – 3x
School Q:
9x = 180
X = 20; Acting – 4x, Painting – 5x
Number students, who participate in Painting from school P & Q = 36 + 100 = 136
Number students, who participate in Acting from school P & Q = 84 + 80 = 164
Difference = 164 – 136 = 28

Incorrect

Answer – 1. 28 Explanation:
School P:
10x = 120
X = 12; Acting – 7x, Painting – 3x
School Q:
9x = 180
X = 20; Acting – 4x, Painting – 5x
Number students, who participate in Painting from school P & Q = 36 + 100 = 136
Number students, who participate in Acting from school P & Q = 84 + 80 = 164
Difference = 164 – 136 = 28

Question 2 of 10

2. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.
Each student in the school either participate in any one of the events or don’t participate in any events.

Number of students who participate in Painting competition from school R is what percentage of number of students who don’t participate in any of the events from school S.

Correct

Answer – 2. 25% Explanation:
Students participated in competition from School R = 330 – 225 = 105
7x = 105; x = 15
Painting competition from school R = 4x = 60
Number of students who don’t participate in any of the events from school S = 240
% = (60/240) * 100 = 25%

Incorrect

Answer – 2. 25% Explanation:
Students participated in competition from School R = 330 – 225 = 105
7x = 105; x = 15
Painting competition from school R = 4x = 60
Number of students who don’t participate in any of the events from school S = 240
% = (60/240) * 100 = 25%

Question 3 of 10

3. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.
Each student in the school either participate in any one of the events or don’t participate in any events.

The total number of students who participated in Painting competition from school U is 5/9th those who participated in Acting from school R. What is the number of students participated in Painting from school U?

Correct

Answer – 3. 25 Explanation:
Students participated in competition from School R = 330 – 225 = 105
7x = 105; x = 15
Acting from School R = 3x = 45
Total number of students who participated in Painting competition from school U
= 5/9 * (Acting from School R)
= 5/9 * 45 = 25

Incorrect

Answer – 3. 25 Explanation:
Students participated in competition from School R = 330 – 225 = 105
7x = 105; x = 15
Acting from School R = 3x = 45
Total number of students who participated in Painting competition from school U
= 5/9 * (Acting from School R)
= 5/9 * 45 = 25

Question 4 of 10

4. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.
Each student in the school either participate in any one of the events or don’t participate in any events.

What is the total number students who participated in Painting from all the schools?

Correct

Answer – 4. 347 Explanation:
Total number students who participated in Painting from all the schools = 36 + 100 + 60 + 100 + 51 = 347

Incorrect

Answer – 4. 347 Explanation:
Total number students who participated in Painting from all the schools = 36 + 100 + 60 + 100 + 51 = 347

Question 5 of 10

5. Question

1 points

Category: Quantitative Aptitude

Directions:(Q.1-5) Read the given data and answer the following question.
Each student in the school either participate in any one of the events or don’t participate in any events.

What is the difference between total number of students who participated in Acting from all schools to total number of students who participated in painting from all schools?

Correct

Answer – 5. 44 Explanation:
Total number students who participated in Painting from all the schools = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Acting from all the schools = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 – 303 = 44

Incorrect

Answer – 5. 44 Explanation:
Total number students who participated in Painting from all the schools = 36 + 100 + 60 + 100 + 51 = 347
Total number students who participated in Acting from all the schools = 84 + 80 + 45 + 60 + 34 = 303
Difference = 347 – 303 = 44

The average age of Amit and Bharat, 2 years ago was 26. If the age of Amit, 5 years hence is 40 years, and Bharat is 5 years younger to Catherine, then find the difference between the age of Amit and Catherine?

Correct

Answer – 2. 9 years Explanation:
Let the present ages of Amit and Bharat be ‘x’ and ‘y’ respectively
[(x-2) + (y-2)]/2 = 26 => x+y = 56
The age of Amit, 5 years hence is 40 years => Present age of Amit = 40 – 5 = 35
=> x = 35 => y = 56 – 35 = 21 => Age of Bharat = 21 yrs
Bharat is 5 years younger to Catherine, Age of Catherine = 21 + 5 = 26
Required Difference between ages of Amit and Catherine = 35 – 26 = 9 years.

Incorrect

Answer – 2. 9 years Explanation:
Let the present ages of Amit and Bharat be ‘x’ and ‘y’ respectively
[(x-2) + (y-2)]/2 = 26 => x+y = 56
The age of Amit, 5 years hence is 40 years => Present age of Amit = 40 – 5 = 35
=> x = 35 => y = 56 – 35 = 21 => Age of Bharat = 21 yrs
Bharat is 5 years younger to Catherine, Age of Catherine = 21 + 5 = 26
Required Difference between ages of Amit and Catherine = 35 – 26 = 9 years.

Question 9 of 10

9. Question

1 points

Category: Quantitative Aptitude

An Express train covers the distance between station “O” and “P”, 40 minutes faster than a passenger train. Find this distance between “O” and “P”, if the average speed of the Express train is 50 kmph and that of passenger train is 30 kmph?

Correct

Answer – 1. 50 km
Explanation:
Let the distance be ‘X’ km.
X/30 − X/50 = 40/60 hours
6X = 300=> X = 50 km

Incorrect

Answer – 1. 50 km
Explanation:
Let the distance be ‘X’ km.
X/30 − X/50 = 40/60 hours
6X = 300=> X = 50 km

Question 10 of 10

10. Question

1 points

Category: Quantitative Aptitude

Arun and Bala invest Rs. 1,16,000 and 1,44,000 respectively. Bala invests for 6 months. At the end of the year, Bala’s share is Rs. 9000, find the overall profit?

Correct

Answer – 5. Rs. 23,500 Explanation :
Arun’s investment = 116000 x 12 = 13,92,000
Bala’s investment = 144000 x 6 = 8,64,000
Ratio = 1392 : 864 = 29 : 18
Let the Annual profit = X
Bala’s share = Rs. 9000
=> 18/47 x X = 9000
=> X = 9000 x 47/18
=> X = 23,500
Hence, Overall profit = X = Rs. 23,500

Incorrect

Answer – 5. Rs. 23,500 Explanation :
Arun’s investment = 116000 x 12 = 13,92,000
Bala’s investment = 144000 x 6 = 8,64,000
Ratio = 1392 : 864 = 29 : 18
Let the Annual profit = X
Bala’s share = Rs. 9000
=> 18/47 x X = 9000
=> X = 9000 x 47/18
=> X = 23,500
Hence, Overall profit = X = Rs. 23,500

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