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Question 1 of 10
1. Question
1 pointsCategory: Quantitative AptitudeThe sum of the present ages of the Sharma’s family members is 78. There are 4 members namely viz Sharma, Rose, Divya and Thomas. Sharma is 4 years older than Rose. Divya is two years older than Thomas. Sharma is 7 times as old as Thomas.
Quantity I: The Difference between the age of Sharm and Divya
Quantity II: The Difference between the age of Rose and ThomasCorrect
Answer – 1. Quantity I > Quantity II
Explanation:
S+R+D+T = 78 – (i)
S = R + 4 – (ii)
D = T + 2 – (iii)
S = 7T – (iv)
7T = R+4
R= 7T – 4
S+R+D+T = 78 – (i)
7T+7T4+T+2+T = 78
16T = 80
T = 5
D = T+2 = 5+2 = 7
R = 7T – 4 = 31
S = 7T = 35
Quantity I = 35 – 7 = 28
Quantity II = 31 – 5 = 26Incorrect
Answer – 1. Quantity I > Quantity II
Explanation:
S+R+D+T = 78 – (i)
S = R + 4 – (ii)
D = T + 2 – (iii)
S = 7T – (iv)
7T = R+4
R= 7T – 4
S+R+D+T = 78 – (i)
7T+7T4+T+2+T = 78
16T = 80
T = 5
D = T+2 = 5+2 = 7
R = 7T – 4 = 31
S = 7T = 35
Quantity I = 35 – 7 = 28
Quantity II = 31 – 5 = 26 
Question 2 of 10
2. Question
1 pointsCategory: Quantitative AptitudeP and Q both are dealers of TVS Motorcycles. The price of a used TVS Scooty Pep is Rs.28,000. Dealer P gives a discount of 10% on whole, while Dealer Q gives a discount of 12% on the first Rs. 20,000 and 8% on the rest Rs. 8000.
Quantity I: The Discount offer by Dealer P
Quantity II: The Total Discount offer by Dealer QCorrect
Answer – 2. Quantity I < Quantity II
Explanation :
Discount offer by P = 10 % of 28000 = 2800
Total Discount offer by Q = 12% of 20,000 + 8% of 8000 = 3040Incorrect
Answer – 2. Quantity I < Quantity II
Explanation :
Discount offer by P = 10 % of 28000 = 2800
Total Discount offer by Q = 12% of 20,000 + 8% of 8000 = 3040 
Question 3 of 10
3. Question
1 pointsCategory: Quantitative AptitudePrince sells an watch at 20% profit to Queen, Queen sells it to Rose at 10% profit. Rose sells it to Daniel at Rs. 16 profit. The difference between the cost price of Daniel and cost price of Prince was Rs. 500.
Quantity I: Cost Price of Rose
Quantity II: Cost Price of Daniel – 16Correct
Answer – 5. Quantity I = Quantity II
Explanation:
Cost Price of Prince = 100x
Cost Price of Queen = 120x
Cost Price of Rose = 132x
Cost Price of Daniel = 132x + 16
132x + 16 – 100x = 500
32x + 16 = 500
32x = 484
x = 484/32 = 15.125
Cost Price of Rose = 132x = 132 * 15.125 = 1996.5
Cost Price of Daniel = 132x + 16 = 1996.5 + 16Incorrect
Answer – 5. Quantity I = Quantity II
Explanation:
Cost Price of Prince = 100x
Cost Price of Queen = 120x
Cost Price of Rose = 132x
Cost Price of Daniel = 132x + 16
132x + 16 – 100x = 500
32x + 16 = 500
32x = 484
x = 484/32 = 15.125
Cost Price of Rose = 132x = 132 * 15.125 = 1996.5
Cost Price of Daniel = 132x + 16 = 1996.5 + 16 
Question 4 of 10
4. Question
1 pointsCategory: Quantitative Aptitudex² – 26x + 168 = 0
y² – 32y + 252 = 0Correct
Answer – 4. X ≤ Y
Explanation:
x² – 26x + 168 = 0
x = 12, 14
y² – 32y + 252 = 0
y = 14, 18Incorrect
Answer – 4. X ≤ Y
Explanation:
x² – 26x + 168 = 0
x = 12, 14
y² – 32y + 252 = 0
y = 14, 18 
Question 5 of 10
5. Question
1 pointsCategory: Quantitative AptitudeThe average weight of 39 Students in a class is 23. Among them Suresh is the heaviest while Thomas is the lightest. If both of them are excluded from the class still the average remains same. The ratio of weight of Suresh to Thomas is 15:8.
Quantity I: Weight of Thomas
Quantity II: Weight of SureshCorrect
Answer – 2. Quantity I < Quantity II
Explanation:
S+T = 23*(3937) = 46
S/T = 15/8
T = 16
S = 30Incorrect
Answer – 2. Quantity I < Quantity II
Explanation:
S+T = 23*(3937) = 46
S/T = 15/8
T = 16
S = 30 
Question 6 of 10
6. Question
1 pointsCategory: Quantitative AptitudeSharma got married 8 years ago. His present age is 7/5 times of age at the time of his marriage Sharma’s brother was 10 years younger to him at the time of his marriage. The present age of Sharma’s brother is
Correct
Answer – 3. 18
Explanation :
Sharma’s age at the time of his marriage = X years
X + 8 = 7/5 X
X = 20.
Present age of Sharma = 28
Sharma’s brother age = 28 – 10 = 18 yearsIncorrect
Answer – 3. 18
Explanation :
Sharma’s age at the time of his marriage = X years
X + 8 = 7/5 X
X = 20.
Present age of Sharma = 28
Sharma’s brother age = 28 – 10 = 18 years 
Question 7 of 10
7. Question
1 pointsCategory: Quantitative AptitudeThe prices of two balls are in the ratio 3 : 4. If the price of the first ball be increased by 10% and that of the second by Rs. 4, the original ratio remains the same. The original price of the second ball is
Correct
Answer – 1. Rs.40
Explanation:
Let the price of two balls are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second ball = 4X = 4*10 = Rs. 40Incorrect
Answer – 1. Rs.40
Explanation:
Let the price of two balls are 3X and 4X.
After increment the ratio will be:
110% of 3x/(4X+4) = 3/4
x=10
Thus the CP of second ball = 4X = 4*10 = Rs. 40 
Question 8 of 10
8. Question
1 pointsCategory: Quantitative Aptitude6, 20, 90, 440, ?, 10940
Correct
Answer – 4. 2190
Explanation :
6 * 5 – 10 = 20
20 * 5 – 10 = 90
90 * 5 – 10 = 440
440 * 5 – 10 = 2190
2190 * 5 – 10 = 10940Incorrect
Answer – 4. 2190
Explanation :
6 * 5 – 10 = 20
20 * 5 – 10 = 90
90 * 5 – 10 = 440
440 * 5 – 10 = 2190
2190 * 5 – 10 = 10940 
Question 9 of 10
9. Question
1 pointsCategory: Quantitative Aptitude8 18 28 ? 356 1782
Correct
Answer – 2. 90
Explanation :
* 1 + 10
* 2 – 8
* 3 + 6Incorrect
Answer – 2. 90
Explanation :
* 1 + 10
* 2 – 8
* 3 + 6 
Question 10 of 10
10. Question
1 pointsCategory: Quantitative Aptitudex² – 28x + 192 = 0
y² – 34y + 288 = 0Correct
Answer – 4. X ≤ Y
Explanation:
x² – 28x + 192 = 0
x = 12, 16
y² – 34y + 288 = 0
y = 18, 16Incorrect
Answer – 4. X ≤ Y
Explanation:
x² – 28x + 192 = 0
x = 12, 16
y² – 34y + 288 = 0
y = 18, 16
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