Quants Questions : Quadratic Equations Set 10

Hello Aspirants. Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating sample questions in Quadratic Equations which is common for all the competitive exams. We have included Some questions that are repeatedly asked in bank exams !!!

You have to solve equation I and II ,Give answer
1)If X>Y
2)If X<Y
3)If X≥ Y
4)If X≤ Y           
5)If X=Y or cannot be established

1. I. 4X²  – 19X + 12= 0
   II. 3Y² + 8Y + 4 = 0
   
   Answer

   Answer –1)If X>Y
   Explanation :
   (x-4)(4x-3) = 0
   X=4,3/4
   (y+2)(3y+2) = 0
   y=-2, -2/3
   4,3/4,-2/3,-2
   Xxyy = x>y
   
   
   
2. I. X² = 729
   II. Y – √324 = √81
   
   Answer

   Answer –4)If X≤ Y
   Explanation :
   X= ±27
   Y = 9+18 = 27
   x≤y
   
   
   
3. I. X²  + X – 56= 0
   II. Y² – 17Y + 72 = 0
   
   Answer

   Answer –2)If X<Y
   Explanation :
   (x+8)(x-7) = 0
   X=7,-8
   (y-8)(y-9) = 0
   Y=8, 9
   9,8,7,-8
   Yyxx = x<y
   
   
   
4. I. 20X²  – 17X + 3= 0
   II. 20Y² – 9Y + 1 = 0
   
   Answer

   Answer –3)If X≥ Y
   Explanation :
   (4x-1)(5x-3) = 0
   X=1/4, 3/5
   (4y-1)(5y-1) =0
   Y = 1/4, 1/5
   3/5, ¼,1/4, 1/5
   Xxyy => X≥ Y
   
   
   
5. I. 3X²  – 10X + 8= 0
   II. Y^{2 +} 3Y – 4 = 0
   
   Answer

   Answer –1)If X>Y
   Explanation :
   (x-2)(3x-4) = 0
   X=2, 4/3
   (y-1)(y+4) = 0
   Y = 1, -4
   2,4/3,1,-4
   Xxyy => x>y
   
   
   
6. I. X²  + 5X + 6= 0
   II. Y² + 3Y + 2 = 0
   
   Answer

   Answer –4)If X≤ Y
   Explanation :
   (x+2)(x+3) = 0
   X=-2,-3
   (y+1)(y+2) = 0
   Y=-1,-2
   -1,-2,-2,-3
   Yyxx => x≤y
   
   
   
7. I. 2X²  + 5X + 2= 0
   II. 4Y² – 1 = 0
   
   Answer

   Answer –4)If X≤ Y
   Explanation :
   (2x+1)(x+2) = 0
   X= – 1/2, -2
   Y = ½, -1/2
   ½, -1/2, -1/2, -2
   Yyxx => x≤y
   
   
   
8. I. X²  + 14X -72= 0
   II. 3Y² + 14Y + 15 = 0
   
   Answer

   Answer – 5)If X=Y or cannot be established
   Explanation :
   (x-4)(x+18) = 0
   X=4,-18
   (y+3)(3y+5) = 0
   Y= -3, -5/3
   4,-5/3, -3, -18
   xyyx
   
   
   
9. I. X²  + 8X + 15= 0
   II. Y² – Y + 12 = 0
   
   Answer

   Answer – 4)If X≤ Y
   Explanation :
   (x+5)(x+3) = 0
   X=-5,-3
   (y-4)(y+3) = 0
   Y=4,-3
   4,-3,-3,-5
   Yyxx => x≤y
   
   
   
10. I. 4X²  – 13X – 12= 0
    II. Y² – 7Y – 60 = 0
    
    Answer

    Answer – 5)If X=Y or cannot be established
    Explanation :
    (x-4)(4x+3) = 0
    X=4, -3/4
    (x+5)(x-12) =0
    Y = 12, -5