Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From Mensuration that is important for all the competitive exams. We have included Some questions that are repeatedly asked in exams !!
- The area of a square field is 4050 m2the length of its diagonal is
A)76m
B)90m
C)84m
D)80m
E)None of theseB)90m
Explanation :
1/2 d2 = 4050
d2 = 8100
d = 90 m - The Surface area of cube is 216 m2. Find it’s diagonal
A)18.25m
B)10.38m
C)13.56m
D)20.67m
E)None of theseB)10.38m
Explanation :
6a2 = 216
a2 = 216/6 = 36
a= 6
Diagonal = a√3 = 6*1.73 = 10.38m - The length of a rope by which a cow must be tethered in order that she may be able to graze an area of 2826 sq.m is
A)20m
B)17m
C)27m
D)30m
E)None of theseD)30m
Explanation :
22/7×r2 =2826
r2 =(2826×7/22) = 899.18 = 900
r = 30 m - The number of rounds that a wheel of diameter14m will make in going 2 km is
A)62 rounds
B)50 rounds
C)45 rounds
D) 56 rounds
E)None of theseC)45 rounds
Explanation :N = 2000/(14*22/7) = 2000/44 = 45.45 = 45 rounds - The ratio of length to breadth of a rectangle is 7:6. The perimeter of the plot is 260m. Find the area of the plot ?
A)4800sq.m
B)5600sq.m
C)4200sq.m
D)2600sq.m
E)None of theseC)4200sq.m
Explanation :
2(7x+6x) = 260
26x = 260
X = 260/26 = 10
Area = 70*60 = 4200 - In a parallelogram the length of adjacent sides are 13m and 11m. If the length of one diagonal is 18m, find the length of the other diagonal ?
A)9m
B)16m
C)12m
D)19m
E)None of theseB)16m
Explanation :
d12+d22 = 2(a2+b2)
324+d22 = 2(169+121) = 580
d22 = 580 – 324 = 256
d = 16m - The circumference of the 2 circle is 212cm and 412cm. What is the difference between the area of the 2 circles ?
A)10048cm2
B) 10480cm2
C) 10070cm2
D) 10140cm2
E)None of theseA)10048cm2
Explanation :
2*3.14*r1 = 212
R1 = 212/6.28 = 33.75 = 34cm
2*3.14*r2 = 412
R1 = 412/6.28 = 65.60= 66cm
Diff = 3.14(662-342)
= 3.14(4356-1156) = 3.14*3200
= 10048 - If the length of the rectangular field is increased by 10% and the breadth is reduced by 10%, now the area of rectangle will be 217 cm2 .Find the area of the original rectangle ?
A)210 cm2
B)219 cm2
C) 215 cm2
D) 221 cm2
E)None of theseB)219 cm2
Explanation :
% change = 10 – 10 – 10*10/100 = -1%
99x/100 = 217
X = 217*100/99 = 219.19 = 219 - The area of right angle triangle is 100sq cm. The ratio of base to its height is 4:5.Find the length of the hypotenuse ?
A)20cm
B)22cm
C)28cm
D)30cm
E)None of theseA)20cm
Explanation :
Area = ½(4x*5x)
100 = 20x^2/2
X^2 = 100/10 =10
x = 3.16
4x:5x = 12.64:15.8
Hypotenuse = √12.642+15.82
= √409.40
= 20.23 = 20 - How many bricks, each measuring 20 cm x 8 cm x 5 cm, will be needed to build a wall of 10 m x 7 m x 20cm?
A)16000
B)11000
C)12000
D)17500
E)None of theseD)17500
Explanation :
Number of bricks =Volume of the wall/Volume of brick
= 1000 x 700 x 20/20 x 8x 5
= 17500
Note : Dear Friends if u know an alternate methods or shortcuts related to any chapter, you can share here.
AffairsCloud Recommends Oliveboard Mock Test
AffairsCloud Ebook - Support Us to Grow
Govt Jobs by Category
Bank Jobs Notification