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Quantitative Aptitude Questions for IBPS/RRB Exam Set – 17

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Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.

  1. A bank offers 5% per annum CI calculated on half-yearly basis. A customer deposited Rs 1,600 each on January 1 and July 1 of a year. The interest he would have gained at the end of the year is
    A. Rs 244
    B. Rs 120
    C. Rs 121
    D. Rs 81
    C. Rs 121
    Explanation:
    Amount on June 30 = 1600 (1 + 5/(2*100))^1 = 1640
    now on July 1, again 1600 is deposited along with Rs 1640 which gives total as 1600 + 1640 = 3240
    Amount on Dec 31 = 3240 (1 + 5/(2*100))^1 = 3321
    C.I = 3321 – 1600 – 1600

  2. Rs 800 becomes Rs 956 in 3 years at a certain rate of simple interest. If the rate of interest is increased by 4%, what amount will Rs 800 become in 3 years?
    A. Rs 1,020
    B. Rs 1,050
    C. Rs 1,025
    D. Rs 1,052
    D. Rs 1,052

  3. A group of 10 students comprises of 5 boys and 5 girls. In how many ways could they be arranged in a row so that the boys and girls occupy alternate positions?
    A. 5! * 5! * 2
    B. 8! * 2
    C. 10!
    D. 16!
    A. 5! * 5! * 2
    Explanation:
    boys and girls have to occupy alternate positions.
    First, let 5 girls sit, this gives 5!, now boys have to sit in between the girls, this gives 5! again.
    now it is possible that first 5 boys sit, and then girls sit in between the boys, so we multiplied by 2

  4. In how many ways the letters of the word ‘OPTIONS’ can be arranged so that all the vowels always occur together?
    A. 5! * 3!/2!
    B. 7!/2!
    C. 4! + 3!/2!
    D. None of these
    A. 5! * 3!/2!

  5. In a solution of 35 litres, the respective ratio of milk and water is 4 : 1. If 7 litres of water is added to the solution, then the ratio of milk and water in the resulting solution will be
    A. 4 : 3
    B. 3 : 1
    C. 2 : 1
    D. 1 : 1
    C. 2 : 1
    Explanation:
    in 35 l, milk is 4/5 * 35 = 28 l, water = 7 l
    when 7 l of water added, new ratio of milk to water is 28/7+7 = 2 : 1

  6. In 80 litres mixture of milk and water, milk and water are in ratio of 5 : 3. If 16 litres of this mixture is replaced by 16 litres of milk, then the ratio of milk to water in the resulting mixture becomes
    A. 2 : 1
    B. 6 : 3
    C. 8 : 3
    D. 7 : 3
    D. 7 : 3
    Explanation:
    in 80 l, milk = 5/8 * 80 = 50 l, water = 30 l
    when 16 l of mixture removed, milk left = 50 – (5/8 * 16) = 40 l, water left = 30 – (3/8 * 16) = 24 l
    New ratio, when 16 l of milk added,
    M : W
    40+16 : 24


  7. The cost price of a commodity is Rs 1,331. By selling it at a discount of Rs 100, the dealer makes a profit of 9.09%. if he decides not to give any discount, then what will be the profit made by him?
    A. Rs 131
    B. Rs 221
    C. Rs 121
    D. Rs 231
    B. Rs 221

  8. A man bought a shirt at 3/4th of its list price and sold it at 50% above its list price. What is his percentage gain in the transaction?
    A. 60%
    B. 50%
    C. 25%
    D. 100%
    D. 100%

  9. Two trains, each 80 m long pass each other in parallel lines. If they are moving in the same direction, the faster one takes one minute to pass the slower one completely. If they are moving in opposite directions, they completely pass each other in 3 seconds. Find the speed of the trains in m/s.
    A. 25 m/s, 28 m/s
    B. 28 m/s, 25 1/3 m/s
    C. 20 m/s, 25 m/s
    D. 15 m/s, 10 m/s
    B. 28 m/s, 25 1/3 m/s
    Explanation:
    Let speeds x and y
    1 min is 60 s. When moving in same direction, x – y = ( 80 + 80)/60
    When moving in opposite direction, x + y = ( 80 + 80)/3

  10. A man can row 40 km upstream and 55 km downstream in 13 hours. Also he can row 30 km upstream and 44 km downstream in 10 hours. Find the speed of the man in still water and the speed of the current.
    A. 8, 3
    B. 5, 2
    C. 8, 5
    D. 5, 8
    A. 8, 3
    Explanation:
    upstream speed is x, downstream speed is y
    total time = distance/speed, so
    40/x + 55/y =13
    30/x + 44/y = 10
    Find x and y
    y=11, x=5
    speed in still water (y+x)/2
    speed of current (y-x)/2