Hello Aspirants. Welcome to Online Quantitative Aptitude section in AffairsCloud.com. Here we are creating question sample From all topics , which are Important for upcoming IBPS and RRB exams. We have included Some questions that are repeatedly asked in exams.
- A does a work in 10 days, and B does the same work in 18 days. A and B started the work, by A left after some days. B completed the remaining work in 6 4/5 days. Find the number of days after which A left?
A. 2
B. 3
C. 4
D. 5C. 4
Explanation:
Let A left after ‘x’ days. B completed remaining work in 6 4/5 days or 34/5 days. So,
(1/10 + 1/18) * x + 1/18 * 34/5 = 1
Find x - A does a work in 10 days and B does the same work in 18 days. They started the work alternately starting with A. After how many days the work will be completed?
A. 12 days
B. 12 2/3 days
C. 20 2/3 days
D. 24 daysB. 12 2/3 days
LCM (10, 18) = 90
So total work = 90
A’s efficiency = 90/10 = 9
B’s efficiency = 90/18 = 5
2 days work (A+B) = 9+5 = 14
Multiply by 6 both side
12 days work (A+B) = 84
Remaining work = 90-84 = 6
Now A’s turn, he will complete remaining work in 6/9 or 2/3 day
So total 12 2/3 days.
- Rs 7000 is deposited in two schemes, one part at 6% per annum and other at 4% per annum. After 5 years, the total interest on both the schemes becomes Rs 1600. Find the amount deposited with 6% per annum?
A. Rs 1000
B. Rs 2000
C. Rs 4000
D. Rs 5000B. Rs 2000
Explanation:
Find the rate % of 5 yrs:
1600 = 7000*r*5 / 100, this gives r = 32/7%
By the method of allegation:
6 4
. 32/7
32/7 – 4 = 4/7 6 – 32/7 = 10/7
4/7 : 10/7 or 2 : 5
Amount at 6% = 2/(2+5) * 7000 = 2000 - An article is bought at an amount of Rs 840. 1/4th of it is sold at 20% loss, find the profit percent on remaining part such that there is a profit of 20% on the whole?
A. 33 1/3%
B. 33%
C. 25%
D. 20%A. 33 1/3%
Explanation:
Remaining part = 1- 1/4 = 3/4
1/4(-20) + 3/4(x) = 20
Find x - A train travelling at 25 km/hr leaves Delhi at 9 AM and another train travelling at 35 km/hr starts at 2 PM in the same direction. How many km form Delhi will they be together?
A. 440 km
B. 400 km
C. 437 ½ km
D. 400 ½ kmC. 437 ½ km
Explanation:
Distance = (S1*S2)/[(S1-S2)t]
Difference in time = 2Pm – 9AM = 5 hrs
Distance = (25*35)/[(35-25)*5] = 437 ½ km - A man covers a certain distance between his house and office. If his average speed is 20 km/hr, he is late by 10 min and if his average speed is 50 km/hr, he reaches 20 min early. Find the distance between his house and office?
A. 50 km
B. 50/3 km
C. 55 km
D. 56/7 kmB. 50/3 km
Explanation:
Distance = (S1*S2)/[(S1-S2)t]
Difference in time = (10)late – (-20)early = 30 min or 1/2 hr
Distance = (20*50)/[(50-20)*1/2] = 50/3 km - A shopkeeper bought 80 kg rice for Rs 384 and sold it at a loss of as much money as he received for 16 kg. Find selling price (per kg) of rice.
A. Rs 3.84
B. Rs 4
C. Rs 3.60
D. Rs 4.50B. Rs 4
Explanation:
C.P. of 80 kg – S.P. of 80 kg = S.P. of 16 kg
C.P. of 80 kg = S.P. of 96 kg
Find loss%, loss% = (96-80)/96 * 100 = 50/3*
Find S.P. per kg - Ten years ago, A was half of B in age. If the ratio of their present ages in 3 : 4, what will be the total of their present ages?
A. 15 yrs
B. 20 yrs
C. 35 yrs
D. 40 yrsC. 35 yrs - The sum of the ages of a mother and her daughter is 50 yrs. Also 5 yrs ago, the mother’s age was 7 times the age of the daughter. What is the present age of the mother?
A. 20 yrs
B. 32 yrs
C. 40 yrs
D. 45 yrsC. 40 yrs
Explanation:
Mother = x, Daughetr = 50-x
5 yrs ago, x-5 = 7(50-x-5), this gives x = 40 - A man purchased two cows for Rs 500. He sells the first at 12% loss and second at 8% gain. In this he neither gains nor loses. Find the selling price of the first cow?
A. Rs 156
B. Rs 170
C. Rs 176
D. Rs 200C. Rs 176
Explanation:
12 8
. 0
8 12
8 : 12 or 2 : 3
CP of 1st cow = 2/(2+3) * 500 = 200
SP = 88/100 * 200 = 176
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