Quantitative Aptitude – Mixed Questions Set 7

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Welcome to Online Quantitative Aptitude Section in AffairsCloud.com. Here we are creating question sample in Quadratic Equations and Miscellaneous based on prelim pattern, which is common for SBI,IBPS, RBI,LIC, NICL and other competitive exams.

1. 1. Q(1-5) In the following questions two equations numbered I & II are given. You have to solve both equations and mark one of the option given below
      I. 242X² + 88X + 6 = 0
      II. 363Y² + 165Y + 12 =0
      1. X > Y
      2. X <Y
      3. X ≥ Y
      4. X ≤ Y
      5. X = Y or relationship cannot be established
      
      Answer & Explanation

      Answer – 5. X = Y or relationship cannot be established
      Explanation :
      X = -3/11, -1/11
      Y = -4/11, -1/11
      
      
   2. I.2X² – (4+√14)X +√56 = 0
      II.10Y² – (18+5√14)Y + 9√14 =0
      1. X > Y
      2. X <Y
      3. X ≥ Y
      4. X ≤ Y
      5. X = Y or relationship cannot be established
      
      Answer & Explanation

      Answer – 3. X ≥ Y
      Explanation :
      X = 2, √14/2
      Y = 9/5, √14/2
      
      
   3. I. √2X² – 48X + 288√2 = 0
      II.Y² – 24√3Y + 420 = 0
      1. X > Y
      2. X <Y
      3. X ≥ Y
      4. X ≤ Y
      5. X = Y or relationship cannot be established
      
      Answer & Explanation

      Answer – 2. X <Y
      Explanation :
      X = 12√2
      Y = 10√3, 14√3
      
      
   4. I.X² + 56X + 783 = 0
      II.Y² – 2Y – 783 = 0
      1. X > Y
      2. X <Y
      3. X ≥ Y
      4. X ≤ Y
      5. X = Y or relationship cannot be established
      
      Answer & Explanation

      Answer –4. X ≤ Y
      Explanation :
      X = -29,- 27
      Y =-27,29
      
      
   5. I. 21X² + 336X + 1344 = 0
      II.24Y² + 384Y + 1536 = 0
      1. X > Y
      2. X <Y
      3. X ≥ Y
      4. X ≤ Y
      5. X = Y or relationship cannot be established
      
      Answer & Explanation

      Answer – 5. X = Y or relationship cannot be established
      Explanation :
      X + 16X + 64 = 0
      Y + 16Y + 64 = 0
      X = Y
      
      
   6. Badri is travelling a distance of 540 Km from Place A to Place B. He covered first 1/3 rd distance by Cycle, Second 1/3 rd distance by Bike and the remaining distance by Car. The average speed of entire journey is 9 Km/hr more than the speed of the Cycle. Speed of Bike is 6 Km/hr more than Speed of Cycle, While speed of Car is 4 times that of the speed of the Cycle. Then what is the average speed of the journey?
      1. 27 Km/hr
      2. 36 Km/hr
      3. 54 Km/hr
      4. 60 Km/hr
      5. Cannot be determined
      
      Answer & Explanation

      Answer – 1. 27 Km/hr
      Explanation :
      540/S = 180*(1/S-9 + 1/S-3 + 1/4*(S-9)
      S = 27
      
      
   7. In the year 2016 the average number of people visited Goa per day is 73. In the next year number of visitors increased by 657. Then average number of people visited Goa in the year 2017 is ?
      1. 73
      2. 74
      3. 75
      4. 76
      5. Cannot be determined
      
      Answer & Explanation

      Answer – 3. 75
      Explanation :
      x/366 =73
      x = 26718
      In 2017 = 26718+657 = 27375
      average = 27375/365 = 75
      
      
   8. Sumit lent a part of Rs. 6000 to Ramya at 6% SI. Rest to Anita at 5% SI. After 3 years he got an amount of Rs 6984 in total. Then what is the amount paid by Anita in total?
      1. Rs.2800
      2. Rs.3304
      3. Rs.3200
      4. Rs.3680
      5. Cannot be determined
      
      Answer & Explanation

      Answer – 4. Rs.3680
      Explanation :
      x*18+(6000-x)*15 = 98400
      x = 2800
      Anita = 3200+3200*5*3/100 = 3680
      
      
   9. A Sum of Rs. 1 Lakh increases by certain rate (compounded annually). The ratio of amounts for the Second year and third year is 10/11. Then amount for five years would be?
      1. Rs. 161151
      2. Rs. 161211
      3. Rs. 163201
      4. Rs. 164221
      5. None
      
      Answer & Explanation

      Answer – 5. None
      Explanation :
      11= 10(1+R/100)
      R =10%
      A= 1 L *(11/10) 5 = 161051
      
      
   10. From a container of Milk, a thief has stolen 16 litres of Milk and replaced it with same quantity of water. He repeated the same process again two more times. Then ratio of Milk and Water is 3375:1538. Then what is the initial amount of Milk in the container?
       1. 120 Litre
       2. 136 Litre
       3. 142 Litre
       4. 154 Litre
       5. None
       
       Answer & Explanation

       Answer – 2. 136 Litre
       Explanation :
       3375x = 4913x(1-16/y) 3
       15/17 = 1-16/y
       y = 136