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- Question 1 of 10
##### 1. Question

1 pointsCategory: Quantitative Aptitude**There are three vessels with equal volumes filled with mixtures of water and milk in the ratios 1:2, 2:3, and 3:4 respectively. These are all poured into a big vessel. What proportion of the mixture in the big vessel should substituted by water so that the milk forms 50% of the resulting mixture.**CorrectAnswer –

**2) 71/386**

Explanation

In the new vessel water and milk are in the ratio

= (1/3+2/5+3/7)(2/3+3/5+4/7)

= 122 : 193

Mixture with drawn = ½ x 193-122/193 = 71/386IncorrectAnswer –

**2) 71/386**

Explanation

In the new vessel water and milk are in the ratio

= (1/3+2/5+3/7)(2/3+3/5+4/7)

= 122 : 193

Mixture with drawn = ½ x 193-122/193 = 71/386 - Question 2 of 10
##### 2. Question

1 pointsCategory: Quantitative Aptitude**Pipes P and Q are inlet pipes while pipe R is an outlet pipe of a tank. Pipe P supplies water at 30 litres/hour. Pipe Q can fill the tank in 6 hours while pipe R can empty it in 24 hours. The empty tank gets filled in 2 hours when all the three pipes are opened simultaneously. What is the capacity of the tank.**CorrectAnswer –

**3) 80 liters**

Explanation

The fraction of the tank filled by Q in 2 hours = 1/3

R emptied in 2 hours 2/24 = 1/12

The fraction of tank filled by Q and R in 2 hours

= (1/3) – (1/12 )= 1/4

So (3/4) filled by P in 2 hours.

Water supplied by P in 2 hours = 2 x 30 = 60 liters

Capacity = 60 x 4/3 = 80 litersIncorrectAnswer –

**3) 80 liters**

Explanation

The fraction of the tank filled by Q in 2 hours = 1/3

R emptied in 2 hours 2/24 = 1/12

The fraction of tank filled by Q and R in 2 hours

= (1/3) – (1/12 )= 1/4

So (3/4) filled by P in 2 hours.

Water supplied by P in 2 hours = 2 x 30 = 60 liters

Capacity = 60 x 4/3 = 80 liters - Question 3 of 10
##### 3. Question

1 pointsCategory: Quantitative Aptitude**A boatman can row a distance of 40 km downstream and return in a total of 10 hours. If the speed of the boat in still water is five times that of the current, find the speed of the current.**CorrectAnswer –

**4) 5/3 km/hr**

Explanation

Let speed of current be s km/hr

Speed of the boat in still water = 5s km/hr

40/s+5s + 40/5s-s =10

5 = 3s

S = 5/3 km/hrIncorrectAnswer –

**4) 5/3 km/hr**

Explanation

Let speed of current be s km/hr

Speed of the boat in still water = 5s km/hr

40/s+5s + 40/5s-s =10

5 = 3s

S = 5/3 km/hr - Question 4 of 10
##### 4. Question

1 pointsCategory: Quantitative Aptitude**A new coach was appointed in cricket team in middle of the season. After the new coach took over, the team won 85 5/7% of the 35 matches that it played. However , the overall success rate of the team for entire season was only 50%. What could be minimum number of matches the team played that season before the new coach took over.**CorrectAnswer-

**1) 25**

Explanation

After coach was appointed the tean won 85 5/7 = 6/7 of 35 matches

But overall = 50 %

The minimum number of matches that it could have played before new coach by assuming that it lost all the matches before the coach took over.

30/x+35 = 1/2

X = 25IncorrectAnswer-

**1) 25**

Explanation

After coach was appointed the tean won 85 5/7 = 6/7 of 35 matches

But overall = 50 %

The minimum number of matches that it could have played before new coach by assuming that it lost all the matches before the coach took over.

30/x+35 = 1/2

X = 25 - Question 5 of 10
##### 5. Question

1 pointsCategory: Quantitative Aptitude**A sum of Rupee6440 is due to be repaid over four years. It has to be repaid in four equal annual instalments (the instalments being payable at the end of the 1st,2nd,3rd and 4th year) at 10 % p.a S.I. Find the value of each instalment.**CorrectAnswer –

**2) 1400**

Explanation

Let each instalment be Rupee x.

After four years, the first instalment, (paid at the end of first year) will amount x +x(3) (10/100) i.e. x(1.3)

Similar for 2,3 and 4 year will amount x(1.2),x(1.1) and x respectively.

Total amount paid = x(1.3) + x(1.2) + x(1.1) +x =x(4.6)

Given sum to be repaid = 6440

X(4.6) = 6440

X= 1400IncorrectAnswer –

**2) 1400**

Explanation

Let each instalment be Rupee x.

After four years, the first instalment, (paid at the end of first year) will amount x +x(3) (10/100) i.e. x(1.3)

Similar for 2,3 and 4 year will amount x(1.2),x(1.1) and x respectively.

Total amount paid = x(1.3) + x(1.2) + x(1.1) +x =x(4.6)

Given sum to be repaid = 6440

X(4.6) = 6440

X= 1400 - Question 6 of 10
##### 6. Question

1 pointsCategory: Quantitative Aptitude**Rohan went to the market to purchase three pens. The cost of the first pen was more than that of the second by 25% which was more than that of the third by 20%. If the average cost of the first two pens was Rupee 15 more than that of the last two pens, find the cost of the costliest pen**CorrectAnswer –

**4) 90**

Explanation

Let cost of second be x , the cost of the first pen = x + 25x/100 = 5x/4

Cost of third be y

x= y + 20y/100 = 6y/5

y=5x/6

5/4x+x / 2 = x+5/6x /2 + 15 = x+5/6x+30 / 2

(1/4 – 1/6)x = 6

X=12 x 6 =72

The costliest = 5/4 x 72 = 90IncorrectAnswer –

**4) 90**

Explanation

Let cost of second be x , the cost of the first pen = x + 25x/100 = 5x/4

Cost of third be y

x= y + 20y/100 = 6y/5

y=5x/6

5/4x+x / 2 = x+5/6x /2 + 15 = x+5/6x+30 / 2

(1/4 – 1/6)x = 6

X=12 x 6 =72

The costliest = 5/4 x 72 = 90 - Question 7 of 10
##### 7. Question

1 pointsCategory: Quantitative Aptitude**Given below the line graph shows the production of two different companies A and B.****Find the difference between average production of two different companies in all the years combined.**CorrectAnswer –

**1) .25 tons**

Explanation

Average production of company A

= 5+10+12+15+5+15+15+5/8

=92/8 = 11.5 tons

Average production of company B

= 8+5+4+14+16+15+12+16/8

=90/8 = 11.25 tons

= 11.5 – 11.25 = .25 tonsIncorrectAnswer –

**1) .25 tons**

Explanation

Average production of company A

= 5+10+12+15+5+15+15+5/8

=92/8 = 11.5 tons

Average production of company B

= 8+5+4+14+16+15+12+16/8

=90/8 = 11.25 tons

= 11.5 – 11.25 = .25 tons - Question 8 of 10
##### 8. Question

1 pointsCategory: Quantitative Aptitude**Given below the line graph shows the production of two different companies A and B.****By how much percent the total production of compant A for the years 2003,2005 and 2008 is more/less than the total productions of company B for the year 2002,2004 and 2007.**CorrectAnswer –

**1) 35 (15/31)%**

Explanation

Total production of company A in 2003,2205 and 2008 = 42 tons

Total production of company B in years 2002,2004 and 2007 = 31 tons

Req % = 11/31 x 100 = 35(15/31) %IncorrectAnswer –

**1) 35 (15/31)%**

Explanation

Total production of company A in 2003,2205 and 2008 = 42 tons

Total production of company B in years 2002,2004 and 2007 = 31 tons

Req % = 11/31 x 100 = 35(15/31) % - Question 9 of 10
##### 9. Question

1 pointsCategory: Quantitative Aptitude**Given below the line graph shows the production of two different companies A and B.****The production of company A in 2009 is twice of the average production of company B in all years. Find the production of company B in 2010 if the ratio of production of company B in 2010 to the production of company A 2009 is 5:3.**CorrectAnswer –

**5) 37.5 tons**

Explanation

Avg. production of company B in all years.

=8+5+4+14+16+15+12+16/8

= 90/8

=11.25 tons

Production of company A in 2009 is = 11.25 x 2 = 22.5 tons

Production of company B in 2010 = 22.5/3 x 5 = 7.5 x 5 = 37.5 tonsIncorrectAnswer –

**5) 37.5 tons**

Explanation

Avg. production of company B in all years.

=8+5+4+14+16+15+12+16/8

= 90/8

=11.25 tons

Production of company A in 2009 is = 11.25 x 2 = 22.5 tons

Production of company B in 2010 = 22.5/3 x 5 = 7.5 x 5 = 37.5 tons - Question 10 of 10
##### 10. Question

1 pointsCategory: Quantitative Aptitude**Given below the line graph shows the production of two different companies A and B.****The production of company B in the year 2008 is what percent of production company A and B in year 2004.**CorrectAnswer –

**1) 55.17 %**

Explanation

production of company B in the year 2008 = 16 tons

production of company A and B in the year 2004 = 29 tons

= 16/29 x 100 = 55.17 %IncorrectAnswer –

**1) 55.17 %**

Explanation

production of company B in the year 2008 = 16 tons

production of company A and B in the year 2004 = 29 tons

= 16/29 x 100 = 55.17 %

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