IBPS PO 2017 Practice Test – Quant Day 1

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Welcome to Online Reasoning Section with explanation in AffairsCloud.com. Here we are creating Best question samples for IBPS PO 2017. We have included Some questions that are repeatedly asked in bank exams !!!

Q(1-5). Study the following data and answer the questions
In the given below table the roots of the equations are radius of the circles C 1, C 2, C 3, C 4, C 5. Radius of the circles are R1, R2, R3, R4, R5 not necessarily in the same order. Below figure depicts the picture of circles with their radius and having common centre O.

1. What is the difference between the area of circles having radius R1 and R2?
   A. 11
   B. 22
   C. 33
   D. 44
   E. None
   
   Answer

   Answer – D. 44
   Solution:
   For Circle C 1 equation X= 6v2, -4v2
   C 2 : Y = 5v3, -7v3
   C 3 : Z = 4v5, -2v5
   C 4 : A = 3v6 , -4v6
   C 5 : B = 2v10, -3v10
   Since radius is always positive so we have to consider only positive rots
   Based on figure R5>R4>R3>R2>R1
   Radius of Circles C 1, C 2, C 3, C 4,, C 5 are (6v2=8.485), (5v3 = 8.666),(4v5 = 8.944), (3v6 = 7.348), (2v10 =6.324)
   respectively
   Then raidus of the circles C 1, C 2, C 3, C 4,, C 5 will be R3,R4,R5,R2,R1 respectively
   For question difference of areas p(2v10) 2 – p(3v10) 2 = 44 units
   
   
2. What is the ratio of perimeters of smallest circle to largest circle ?
   A. 1:2
   B. 1:v2
   C. 1:v3
   D. 2:v5
   E. None of these
   
   Answer

   Answer – B. 1:v2
   Solution : 2v10: 4v5 =1:v2
   
   
3. What is the area of the largest square that can be inscribed in the smallest circle?
   A. 80
   B. 40
   C. 20
   D. 10
   E. None of these
   
   Answer

   Answer – A. 80
   Solution: Largest square that can be inscribed in a circle will have diagonal of 2R
   Side of square will be v2 R
   R = 2v10 for smallest circle
   Area of square = (v2 * 2v10) 2 = 80
   
   
4. Which circle is having the maximum diameter?
   A. Circle C 1
   B. Circle C 2
   C. Circle C 3
   D. Circle C 4
   E. Circle C 5
   
   Answer

   Answer – C. Circle C 3
   Circle C 3 is having bigger radius 4v5
   
   
5. Area of Circle having radius R5 is how many times the area of circle having radius R1?
   A. 1
   B. 2
   C. 3
   D. 4
   E. None
   
   Answer

   Answer – B. 2
   Area of Circle C 3 = p * (4v5) 2 = 80p
   Area of Circle C 5 = p* (2v10) 2 = 40p (means 2 times)
   
   

Q(6-10). Study the following and answer the questions
In the given table contains selling prices of items on different days and also no of items sold by two shopkeepers M & N. Cost price ’A’ of one item is same for both shop keepers which is the difference of total items sold by Shopkeeper M & N in rupees.

6. Which shopkeeper has earned the total profit?
   A. Shopkeeper M
   B. Shopkeeper N
   C. Both Equal
   D. Cannot be determined
   E. None
   
   Answer

   Answer – B. Shopkeeper N
   Solution: Cost Price = A =110 = difference of items sold by M & N
   (253+440+649+407+363) – (231+418+627+385+341) = 2112 – 2002 = 110
   Profit: SP- CP based on table
   Calculating SP on all days
   Then Total Profit earned by M is 5060 and N is 6710
   
   
7. The difference between total profit earned by the shopkeepers is?
   A. 1650
   B. 1680
   C. 1860
   D. 1720
   E. None
   
   Answer

   Answer – A. 1650
   Solution:
   6710-5060 = 1650
   
   
8. What is the approximate total profit percentage earned by shopkeeper M?
   A. 1%
   B. 2%
   C. 3%
   D. 4%
   E. None
   
   Answer

   Answer – B. 2%
   Solution:
   CP = total items * 110 =2112*110 = 2323220
   SP =(649*120+440*110+253*90+407*110+363*120) = 237380
   % = (237380-232320)/232320*100 = 2.17%
   
   
9. The difference between the profit earned by shopkeepers on Monday is?
   A. 6050
   B. 6490
   C. 6270
   D. 6660
   E. None
   
   Answer

   Answer – A. 6050
   Solution: 627*20 – 649*10 = 6050
   
   
10. What is the Selling price offered by Shopkeeper N on Thursday?
    A. 110
    B. 120
    C. 100
    D. 90
    E. None
    
    Answer

    Answer – D. 90
    Solution: 110- 2 *10 =90